All Answers 358087 Answers

4000 x 0.2 = 800

They use a comma for a decimal point.

To avoid confusion, for a thousand, no need for a separator, use a space to separate.

1 234 = 1 thousand 2 hundreds 3 tens 4 ones

1,234 or 1.234 = 1 one 2 tenths 3 hundredths 4 thousandths

I'll just change (b) to round off to whole number

I am assuming that A,c and E are collinear.

Use pythagorean theorum :)

\(AE^2=8.5^2+17^2\\\)

AE^2=8.5^2+17^2\\

Here is a nefty trick for finding the square of numbers ending in 5

85^2      

 = 8^2+8    with 25 tacked on the end.

= 64+8    with 25 tacked on the end.

= 72    with 25 tacked on the end.

=7225

so  8.5^2=72.25

17^2=289   (I just know that)      

But I could do it as (10+7)^2 = 100+140+49=289

so

\(AE^2=8.5^2+17^2\\ AE^2=72.25+289\\ AE^2=361.25\\ AE^2=\frac{36125}{100}\\ AE^2=\frac{25*1445}{100}\\ AE^2=\frac{25*5*289}{100}\\ AE=\frac{5*\sqrt5*17}{10}\\ AE=\frac{85\sqrt5}{10}\\ AE=8.5\sqrt5\\\)

That is in  8.5sqrt5    cm of course.

Will has given you a good decimal approximation.  Thanks Will

\(a^2=b^2+c^2\)

\(a^2=17^2+8.5^2\)

\({\left ( {2n}^{3} \right )}^{4} = {\left ( 2 \times {n}^{3} \right )}^{4} = {\left ( 2 \times {n}^{3} \right )}^{4} = {2}^{4} \times {\left ( {n}^{3} \right )}^{4} = 16 \times {\left ( {n}^{3} \right )}^{4} = 16 {\left ( {n}^{3 \times 4} \right )} = 16 {\left ( {n}^{12} \right )} = 16 {n}^{12}\)  

(2n^3)^4=16n^12

c² = a² + b²

c² = 14² + 12²

    ^{= 196 + 144}

    ^{= 340}

^{c = √340}

   ^{= √4 * √85}

   ^{= 2√85}

Poor juriemagic ,Bertie and CPhill Negative 2 is crazy!Must all be some bugs.And what is that {i'm not a robot}button does?It's sooooo annoying!!!!!!

Maybe try pressing F5 , the reload button or use firefox.

Hope this helps!

Uh... To multiply, you must do repeated addition.

ab = a + a + a + ... + a 

                       b times

(3u^2v^3)^3

\((3u^2v^3)^3 =3^3u^6v^9 =27u^6v^9\)

592/74 = 8

Shouldn't that be  ?        

(-1)^(1/2)(592/74)(3.14159265359...) and it was delicious!

Tara had 1 5/8 pounds of dried nuts. She ate 1/4 pound of dried nuts each day for 6 days. How many pounds of dried nuts did Tara have left after 6 days?

(1+5/8)    -   (1/4)*6 =     that is how many  :)

Thanks guest.

You did a good job os explaining why 1 book costs $19

The next step is 95/19 = 5 books

You probably mean

0.33/sqrt( -90*-45.9)

It doesn't mean anything.  Is there more to the question?

is the ratio of the area of two circles are 25:49 what is the ratio of the diameters.

\(\frac{\pi (R_1)^2}{\pi (R_2)^2}=\frac{25}{49}\\ \frac{ (R_1)^2}{(R_2)^2}=\frac{25}{49}\\ \frac{ R_1}{R_2}=\frac{5}{7}\\\)

The ratio of the radii is    5:7

and

The ratio of the diameters is also 5:7

Thanks Chris      

I should have seen that      

(x^3-x+1)-(3x-1) 

This is just an expression that simplifies to x^3 -4x + 2

.

.

If you have the quadratic equation  \(ax^2+bx+c=0\)

where a, b and c are constants, then the two solutions are given by the quadratic formula, which is:

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

-9<9x+9<27

\(-9 < 9x + 9 < 27 \\ \\ -1 < x+1 < 3 \\ \\ -2 < x < 2\) 

Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)

4 cos^3 x = 4 cos x

\(4 \cos^3(x) = 4\cos(x)\\ \\ \cos^3(x) = \cos(x)\)

\(\text{If }\cos(x) \neq 0 \\ \\ \cos^2(x)=1 \\ \\ \cos(x)=\pm 1\\ \\ x = 0, \pi\) 

\(\text{If }\cos(x)=0 \\ \\ x=\dfrac \pi 2, \dfrac {3\pi}{2}\)

so the full set of solutions is

\(x=\left \{0, \dfrac \pi 2, \pi, \dfrac {3\pi}{2}\right \}\)