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I'm sorry, all of my jokes are laughed at only because of how cheesy and pathetic they are.

I looked it up and saw a lot of good ones online...

I hope he feels better!

Thanks for all of the answers!

I don't think it's possible for a fish to drown...

Actually, the formula for the circumference of a circle is 2(pi)(r).

It is easy to get this and the formula for calculating the area of a circle, pi(r)^2, confused since they use the same numbers.

No....you have the area formula for a circle

The circumference is  :   2 * pi * r      or, as sometimes written :     pi * diameter

No, it is either 2pi*r, or pi*d, area is pi*r^2.

None of those...

.600  = 600/ 1000  = 6 / 10   = .6

Not 4.

I should have added the words "difference of"

11

For every 1 horizontal unit there are 11 vertical units.

Sorry......I typed the wrong function into Desmos......Guest 2  is correct.....the answer occurs at about x = 0.258

Here's the correct graph ........https://www.desmos.com/calculator/t9ttiydcve

CPhill: The figure of .189 does not appear to balance the equation? The figure that I obtained, x=0.2576276530, does to a dozen decimal places.

Here's a graphical solution : https://www.desmos.com/calculator/c0vu5ffqbv

It  occurs  at about  x = 0.189

x=1/(3*e^x)

The real value can be obtained either through graphing or interpolation. My calculator gives a value of x=0.2576276530.......through interpolation.

Look at the graph : https://www.desmos.com/calculator/ijwc1arqf6

Note that there is no intersection point .......thus.......no solutions......!!!!

x=(3*e^x)^-1

1/x=3*e^x

1/3x=e^x

ln(1/3x) = x

-ln(3)-ln(x)=x
-ln(3) = x + ln(x)

-(log(3)/log(e))=-1.0986122886681098 = x + ln(x)

This is a hard problem, I hope I may have given you enough to solve it, but I forget how to do this kind of thing.

3. 16 tan t − 16 = 0    divide both sides by 16

tant - 1  = 0

tan t = 1       and this occurs at  pi/4  + npi     where  n is an integer

I assume that the second one is :

[6 cot t]^2  = 108

36cot^2 t  =  108       divide both sides by 36

cot^2 t  = 3       take the square root of both sides

cot t  =  ± sqrt (3)

For the first soluton, we have

cot t = sqrt(3)       this occurs at   pi/6 + n*pi    where n is an integer

For the second solution, we have

cot t = - sqrt(3)       this occurs at 5pi/6 + n*pi   where n is an integer 

Here's the graph [in degrees] :  https://www.desmos.com/calculator/hbl4cuxc3a

69 fish

1. 2 sin 2t − 3tan 2t = 0

2sin2t - 3sin2t / cos2t = 0

sin2t [ 2 - 3/cos2t]  = 0

Set each factor to 0

sin2t = 0    and this occurs at  n* pi/2     where n is an integer

For the second factor, we have

2 - 3/cos2t  = 0

2 - 3sec(2t)  = 0    

sec(2t)  = 2/3       and there is no solution to this 

Here's a graph [in degrees ]  .......https://www.desmos.com/calculator/x7dws0dxus

put it like a division problem. for example, the fraction 3/4 would be 3÷4

78 = 3c+12-c+4    combine like terms on the right

78 = 2c + 16    subtract 16 from both sides

62  = 2c     divide both sides by 2

31 = c