All Answers

#1

+130511

0

Here's a pretty good explanation with some examples :

http://mathsa.ucd.ie/courses/math1200/algebra/algebranotes8-3.pdf

CPhillApr 20, 2016

#2

+130511

0

Volume of the water in the bucket before the b***s are added =

pi * (d/2)^2 * h = pi *(10/2)^2 * 4 = pi * (5)^2 * 4 = 100pi in^3

Volume of the three b***s =

3 * (4/3) pi (d/2)^3 = 4pi ( 6/2)^3 = 4pi (3)^3 = 108 pi in^3

So...the total volume of the water and b***s = 208 pi in^3

And [ assuming the bucket is tall enough] ......the height of the water will be :

208pi = pi * (10/2)^2 *h

208 = 5^2 * h

208 = 25 *h

208/25 = h = about 8.32 in = about 8 in [rounded]

CPhillApr 20, 2016

#1

+130511

0

(50 /9 ) / 2 =

(50/9) / (2 /1) = [ Invertir la segunda fracción y multiplicar ]

(50/9) * (1/2) =

50 / 18 =

25 / 9

CPhillApr 20, 2016

#1

+130511

0

Frequency = 1 / period

We can find the period of f(θ)=−1.75 cos(1/2(θ + 60°)) thusly :

(1/2)x = 2pi multiply both sides by 2

x = 4 pi ......and this is the period

So the frequency = 1 / [4 pi ]

CPhillApr 20, 2016

#2

+118723

0

Hi Gibsonj338

I cannot make that work. Maybe i am doing it wrong? I am not used to using special characters and I am on a PC.

MelodyApr 20, 2016

#2

+118723

+5

Guest is right

It has NO REAL roots !

And most likely you have not learned about complex numbers yet.

MelodyApr 20, 2016

#1

+118723

0

A bucket holding water has a diameter of 10 in. The water in the bucket has a height of 4in. Charlie places 3 b***s in the bucket of water. Each ball has a diameter of 6 in. What is the height of the water after he puts the ball in the bucket? Round to the nearest whole number.

The volume of 1 ball = (4/3)*pi r^3

So the volume of 3 b***s is 4pi r^3

Let V=4pi r^3 Where r=radius of ball You can work out what that is.

The surface area of the bucket is S = pi r^2 where r = radius of bucket, you can work that out

V=hS

change in height is H=V/S

You can now work out what the new height is. :)

MelodyApr 20, 2016

#1