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what is 852185.81 in money terms

$8,521,185.81 dollars and cents.

1 1/8 POUNDS=1.125 pounds

what is the answer to 1+i divided by 1-2i

\(\frac{1+i }{1-2i}\\ =\frac{1+i }{1-2i}\times\frac{1+2i}{1+2i}\\ =\frac{(1+i)(1+2i) }{(1-2i)(1+2i)}\\ =\frac{1(1+2i) +i(1+2i)}{1-4(i^2)}\\ =\frac{1+2i +i-2}{1+4}\\ =\frac{-1+3i }{5}\\ =\frac{-1 }{5}+\frac{3 }{5}i \)

Simplify the following:
(6-1/x)/(1/x)

Multiply the numerator of (6-1/x)/(1/x) by the reciprocal of the denominator. (6-1/x)/(1/x) = (6-1/x) x:
x (6-1/x)

Put each term in 6-1/x over the common denominator x: 6-1/x  =  (6 x)/x-1/x:
(6 x)/x-1/x x

(6 x)/x-1/x = (6 x-1)/x:
(6 x-1)/x x

((6 x-1) x)/x = x/x×(6 x-1) = 6 x-1:
Answer: |  6 x-1

The third child is named Dave. He wasn't loved as much as the other two kids.He became quiet, and read a lot. Finally, he grew up and became a Donald Trump supporter. In other words, he was a failure. And that child is you.

42. 

Don't question it.

If the width is 18 then the diameter is 18 (if i've understood you right). The radius is therefore 9. The area of a circle (as the base of a cylinder is a circle) is calculated with the formula A = r * r * pi = 9*9*3.1415926535 = 254.47 length units. 

If you want to calculate the volume too you use the formula V = B * H = Base * Height = 254.47 * 10 = 2544.7 Area units. 

What does it takento become a site admin

C=2*pi*r

sub your values in and solve ro r

then double it to get your diameter.

Yes if you divide both sides of the circumference equation by 2pi you will get

r= c/(2pi)       You need tge brackets there :)

cos2theta = -4/5 and 90* < theta < 135*, what is the value of costheta

 \(cos2\theta = \frac{-4}{5}\\ cos^2\theta - sin^2\theta = \frac{-4}{5}\\ 1-sin^2\theta - sin^2\theta = \frac{-4}{5}\\ 1-2sin^2\theta = \frac{-4}{5}\\ 1+\frac{4}{5} = 2sin^2\theta\\ \frac{9}{5} = 2sin^2\theta\\ \frac{9}{10} = sin^2\theta\\ sin\theta=\pm\frac{3}{\sqrt{10}} \\ \mbox{But theta is in the second quadrant}\\ sin\theta=\frac{3}{\sqrt{10}} \\ \theta = 180-sin^{-1}\frac{3}{\sqrt{10}} \\ \theta \approx 108^026'58" \)

Sometimes it isn't possible to use a measuring tool. It will also likely be more accurate asssuming the other measurements are accurate.

solve for x: cos(x)=0.342/0.798

\(\begin{array}{rcll} \cos(x) &=& \frac{0.342}{0.798} \\ \cos(x) &=& 0.42857142857 \qquad & | \qquad \pm\arccos{()}\\ x &=& \pm\arccos{( 0.42857142857 )}\\ x &=& \pm64.6230664748^{\circ}\\ \mathbf{ x_1 } & \mathbf{=} & \mathbf{64.6230664748^{\circ} }\\\\ x_2 &=& -64.6230664748^{\circ} \\ x_2 &=& -64.6230664748^{\circ}+ 360^{\circ} \\ \mathbf{ x_2 } & \mathbf{=} & \mathbf{295.376933525^{\circ}} \end{array} \)

its 10 duuuuuude

this is not a arcus function "arc cosh" is wrong, this is a area - function area cosh(x) or arcosh(x) is right!

just re-arrange to get

cosh(0.438X) = 143.3/15.25

then

(0.438X) = arc cosh( 143.3/15.25),and just do the arithmetic.

The cosh function is never zero,by the way,as it is e^x + e^(-x).The x axis is an asymptote of the function.

2m-4n when m = 1.8 and n = -0.7

2[1.8] - 4 [-0.7]  =

3.6 + 2.8 =

6.4

143.3-15.25 cosh(0.0438x)=0

Subtract   143.3 from both sides

-15.25cosh(0.0438x)  =  - 143.3     

Divide both sides by -15.25

cosh(0.0438x)  = 143.3/15.25

Take the arccosh to isolate x

arccosh(143.3/15.25) = 0.0438x

Divide both sides by 0.0438

arccosh(143.3/15.25)/0.0438  = x  = about 66.9102

As I'm not overly familiar with these functions, WolframAlpha  also gives the negative of this as the other [real solution] x intercept......here's a pic :

(82/100)x = 328

82x =32800

x = 32800/82

x = 400

82% of 400 is 328

i have no idea

I assume this is supposed ro be :

12 - x³  = 0       if so....    add x³ to both sides

12 = x³     take the cube root of both sides

∛12 =  x   = about 2.29

3(x^2) - 5 = 0

3(x²)  = 5

x² = 5/3

x = √(5/3)

x = ± 1.29099444874

asinus :- )

  !

15%  =  .15

Guest......here's an informal proof of why 0!   = 1

Note :

[n] !  = [n + 1 ] !  / [ n + 1]   ......so......

2!  =   3! / 3     =  2

1!  =   2! / 2    =  1

0!  = 1!  /  1     = 1

31.6916676717452859083 sq miles