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Area, x = a*b; x = 1
Therefore 1 = a*b_________________ Eq .1

Ratio of sides a and b, a/b, is √2,
Therefore a/b = √2
Hence a = (√2)*b__________________Eq. 2

Eq.2 in Eq.1:
1 = [(√2)*b]*b
1 = (√2)*bsqared
bsquared = 1/√2
b = √(1/√2)

Replace value of b into Eq. 2
Therefore a = (√2)* √(1/√2)

Hence value a = (√2)* √(1/√2) and b = √(1/√2). (Surd format )

GuestMay 16, 2012

+3146

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[input]x^2-6x=0[/input]

adminMay 16, 2012

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I'm going to assume that the triangles are right.

The solution for the 1st question would be tan(-1) = 3/9 which is roughly 18.43

The solution for the second one would be tan (-1) = 5/14 which is roughly 19.65

GuestMay 16, 2012

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GuestMay 16, 2012

May 15, 2012

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GuestMay 15, 2012

0

GuestMay 15, 2012

+3146

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[input]sqrt(2x)=6[/input]

adminMay 15, 2012

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(square root of 2x)=6
2x=6^2
2x=36
x=36/2
x=18

GuestMay 15, 2012

+3146

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[input]1+1[/input]

adminMay 15, 2012

+3146

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[input]5z^2-23z-10[/input]

(z-5)*(5z+2)

adminMay 15, 2012

+3146

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[input]60+60-120+1786499833[/input]

adminMay 15, 2012

+3146

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x*87.5%=112
x*87.5/100=112
x*87.5=112*100
x=112*100/87.5
x=128

[input]x*87.5%=112[/input]

adminMay 15, 2012

+2

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The answer would be 64.

If the square is split along the diagonal, it creates a 45-45-90 right triangle.

The hypotenuse is a product of one of the side lengths and the square root of 2.

If that is so, then the side length of the square is 16.

Therefore, the perimeter of the square is 64.

davisi453May 15, 2012

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Thank your for your help, I appreciate it.

GuestMay 15, 2012

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What is the correct way to show your work and get your answer? How do you set up the equation naimean?

GuestMay 15, 2012

May 14, 2012

+3146

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[input]-1/2-(-5/8)[/input]

adminMay 14, 2012

+3146

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[input]6.67 * 10^-11[/input]
[input]6.67e-11[/input]

adminMay 14, 2012

May 13, 2012

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12- 1/9d=177
108 - d = 1593
-d = 1485
d = -1485

GuestMay 13, 2012

+3146

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[input]x^2-2x+0.75=-1.5x+4[/input]

x^2-2x+0.75=-1.5x+4
x^2-2x+0.75+1.5x-4=0
x^2-2x+0.75+1.5x-4=0
x^2-0.5x-3.25=0

a*x^2 + b*x + c = 0
p= b/a
q= c/a
here a = 1, then
p = -0.5
q = -3.25

x _{1, 2} = -p/2 +- sqrt( (p/2)^2 - q )

x ₁ = +0.5/2 + sqrt( (-0.5/2)^2 + 3.25 )
x ₂ = +0.5/2 - sqrt( (-0.5/2)^2 + 3.25 )
[input]+0.5/2 + sqrt( (-0.5/2)^2 + 3.25 )[/input]
[input]+0.5/2 - sqrt( (-0.5/2)^2 + 3.25 )[/input]

adminMay 13, 2012

+3146

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[input]x^3-3x^2-16x+48=0[/input]

adminMay 13, 2012

+3146

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[input]solve( a+b=23100, 1833=a*(3/100) + b*(13/100) )[/input]

adminMay 13, 2012

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GuestMay 13, 2012

May 12, 2012

+3146

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[input]50 = 16t^2[/input]

adminMay 12, 2012

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hollydolly98:
if the area of x is 1m squared

hollydolly98:
the ratio of the long side to the short side is root 2

a/b = sqrt(2)

[input]solve( a*b=1, a/b = sqrt(2))[/input]

adminMay 12, 2012

May 11, 2012

+3146

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[input]12 - 1/(9d) = 177[/input]

adminMay 11, 2012

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