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Hi Sadpumpkin,

Hopefully this will cheer you up a bit  :)

5x-7 = +1(5x-7)

and

7-5x= -1(5x-7)

So the  common factor is   5x-7      OR   7-5x   is you prefer

=((2*Y^2)^(5/3))/((4*Y)^(2/3))

\(\frac{(2Y^2)^{5/3}}{(4Y)^{2/3}}\\ =\frac{(2^5Y^{10})^{1/3}}{(4^2Y^2)^{1/3}}\\ =\frac{(2^5Y^{10})^{1/3}}{(2^4Y^2)^{1/3}}\\ =\frac{(2Y^{8})^{1/3}}{(1*1)^{1/3}}\\ =(2y^8)^{1/3}\\ =\sqrt[3]{2y^8} \)

It is undefined.

Quadrilaterals are 4 sided polygons.

the pic is from this site:

1461

Well, let's look at it this way.   0 (degrees C I will assume) is 273 degrees kelvin.    If it was going to be TWICE as HOT tomorrow it would be 546 kelvin or 273 C     With this in mind,   I would say 'Twice as cold' is 1/2 the temperature or 137 K tomorrow or -137C

(which is -214 F)    Unrealistic, for sure.

K=1/2 I w^2    Multiply both sides by 2

2K = I w^2       Divide both sides by w^2

2K/(w^2)  =  I

How many people did he share his half potoato with?

Anyway he'd have 1.5 potatoes plus a bit more. ://

To receive an annaul salary of  p  when a company pays  $20,000 per year plus  5%  sales commission:

  p  =  20000 + 0.05·s

log₁₀( sin(x) )  =  -0.49928

Write into exponential form:  sin(x)  =  10^-0.49928 

                                   --->     sin(x)  =  0.3167524626

Find  sin^-1(x)              --->            x   =  sin^-1( 0.3167524626 )

                                  --->            x   =  18.46664082

Converting the decimal  0.46664082 into minutes  --->   0.46664082 x 60  =  27.9984492   --->   28

So:  x  =  18° 28'

((3/5)+(pi/7-pi))*((3/5)+(pi/7-pi))=

Since  pi/7 - pi  =  pi/7 - 7·pi/7  =  -6·pi/7,

the problem becomes:  ( 3/5 - 6·pi/7 ) · ( 3/5 - 6·pi/7 )

     =       (3/5)·(3/5)  +  (3/5)·( - 6·pi/7 )  +  (3/5)·(  - 6·pi/7 ) + ( - 6·pi/7 )( - 6·pi/7)

     =             9/25  -  18·pi / 35  -  18·pi / 35  +  36·pi² / 49

     =                        9/25  -  36·pi / 35  +  36·pi² / 49

24/3=8 kmh-the speed of the boat with the current

24/5=4.8 kmh-the speed of the boat against the current

8 - 4.8 =3.2 kmh-difference in the speed of the boat due to current in coming and going.

3.2/2 =1.6 kph-speed of the current.

A boat took 3 hours to travel 24 km with the current. On the return trip, the boat took 5 hours to travel 24 km against the current. Determine the speed of the current.

Let  B  represent the rate of the boat in still water.

Let  C  represent the rate of the boat in still water.

The rate moving downstream is  B + C.

The rate moving upstream is       B - C

Distance  =  Rate x Time

Downstream:  24  =  (B + C)·3     --->   3B + 3C  =  24     --->   x 5    --->    15B + 15C  =  120

Upstream:       24  =  (B - C)·5     --->   5B  - 5C  =  24     --->   x -3   --->   -15B + 15C  =  -72

                                      Adding down the columns:                                                30C  =  48

                                                                                                                                    C  =  1.6

pie equals 3.14 my teacher told me.

The formula for the volume of a pyramid is:  V  =  (1/3)·(Area of the base)·(height of the pyramid).

Since all the base of the pyramid is a square whose sides are each 6  --->   Area of the base = 36

To find the height of the pyramid, use the right triangle whose endpoints are one of the corner points of the base, the center of the base, and the top point of the pyramid.

The hypotenuse of this triangle is an edge of the pyramid  =  6.

The side that connects one of the corner points of the base to the center of the base is one-half the distance from one of the corner points of the base to the corner point that is directly opposite it on the base.

Since the base is a square whose sides each equal 6, using the Pythagorean Theorem, we can find the distance from one of the corner points to its opposite corner point is 6·sqrt(2).   

So the distance from a corner point to the middle of the base is  3·sqrt(2).

To find the height of the pyramid, use the Pythagorean Theorem with one side = 3·sqrt(2) and the hypotenuse = 6, so that the other side (the height of the pyramid) is  3·sqrt(2).

The volume is:  V  =  (1/3)(36)(3·sqrt(2))  =  36·sqrt(2)

  Let a and b be the roots of the quadratic equation 2x^2-8x+7=0. Find 1/2a + 1/2b

1/2a + 1/2b  =  (1/2)(a + b)       which equals one-half the sum of the roots

So, we are looking for one-half the sum of the roots.

For every quadratic equation:  ax² + bx + c  =  0, the sum of the roots will be:  -b / a

For this problem:  a = 2     b = -8     c = 7

So the sum of the roots is:  -(-8) / 2  =  8/2  =  4

One-half the sum of the roots is  (1/2)(4)  =  2    

The answer is:  2.

2^2-50=0 Your equation does not make sense!!. I will change it so that it makes sense!!!!.

2^x - 50 =0

2^x=50

x=Log(50) / Log(2)

x=~5.64

Se o problema e  x²  - 50  =  0

--->                               x²  =  50

--->                                x  =  sqrt(50)  =  5sqrt(2)

                                      x  =  - sqrt(50)  =  - 5sqrt(2)

Ms. Melrose's BMW cost somebody $21,000 in 1988, it has lost 10% of its value every year since 1988. Find a function that gives the value of Ms. Melrose's BMW f(x) in terms of x years since 1988. Use your formula and a calculator to figure out how much Ms. Melrose's BMW is worth here in 2016.

x=2016 - 1988 =28 years elapsed since the purchase of the car.

f(x)=21,000 x .90^x

f(x)=21,000 x .90^28

f(x)=21,000 x 0.052335

f(x)=$1,099 The value of Ms. Melrose's BMW in 2016.

Sorry im wrong the calculator is right sorry people!!!

Thanks 315

Thats a great ego boost on which I will start my morning. :)

Plus

I am always pleased to help. :D

The height of an equilateral trial=6^2 - (6/2)^2 =sqrt(27)=~5.2

Volume=(H. S^2) / 3

Volume=(5.2 x 6^2) / 3

Volume=62.4 Cubic units.

CPhill: Please verify this. Thanks.