FIND X,Y IF sqrt(x)+y=7 sqrt(y)+x=11
FIRST: sqrtx and sqrt y are both real numbers so x and y are both equal or greater than 0
\(\)
\(\sqrt{x}+y=7\)
Lets think about this.
x muxt be a perfect square because otherwise the sum will be irrational.
If x=0 y=7
As x gets bigger y gets smaller,
When x=49 y=0
So this is an ever decreasing curve (The gradient is always negative)
Now look at
\(\sqrt{y}+x=11\)
When y=121 x=0
as y decreases, x will increase until when x=11 y = 0
Again this is a monotonically decreasing curve.
This means that the 2 curves will only cross at one point.
With a little thought I can see that
sqrt(9)+4=7
sqrt(4)+9 =11
So the point of intersection is (9,4)
Here is a graph to confirm and help explain what I have told you :)
https://www.desmos.com/calculator/no2h6io7l7