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3^x = 19683 = 27³ = (3³)³ = 3⁹

x = 9

3^x =19683 , find the value x

3^x =19683         

x * ln(3) = ln (19683)

x = ln (19683) / ln(3)

x = 9

Good Morning gamersguide and Guest !

A = (3x + 7) / (2x + 3)

x = - 1       x = - 4  also satisfies the condition. Therefore:

A = 4         A = 1

Greeting asinus :- )

   !

(x+45)/6=8    x=3

100-12y

A=(3x + 7) / (2x + 3)

x=1 satisfies the condition. Therefore:

A=2

This question can be answered in a variety of ways. There is a rather involved TVM formula for these type of problems but is rarely used.
What this problem entails is to find the PV of $1 and then 90% of subsequent payments for ten years. That is: $1/1.06 + $.9/1.06^2 + .9^2/1.06^3..........etc. This can be summed up very quickly by a solver, such as Wolfram/Alpha. Here is the summation formula that I plugged in Wolfram/Alpha, which gives the answer instantaneously: ∑ [.9^n/1.06^(n+1)], n=0 to 9. It gives: 5.03312362640.
         Now, we simply divide $250,000 / 5.03312362640=$49,670.94. This is the first payment of this annuity which decreases by 10% per year for 10 years.

http://www.wolframalpha.com/input/?i=%E2%88%91+%5B.9%5En%2F1.06%5E(n%2B1)%5D,+n%3D0+to+9

− ​7/6 ​​ ÷(− ​4/​5 ​​ )=-7/6 x -5/4 =35/24 =1+ 11/24

how much is 5 module 3=2

Let the number of students who earn a 'B' is B.

Since the probability of earning an 'A' is 0.7 times the probability of earning a 'B', the number of A's earned will be 0.7·B.

Since the probability of earning a 'C' is 1.4 times the probability of earning a 'B', the number of C's earned will be 1.4·B.

Since there is a total of 31 students:  0.7B + B + 1.4B  =  31

                                               --->                        3.1B  =  31

                                               --->                             B  =  10     (10 students will earn a 'B'.)

                                     Number of A's:  0.7B  =  0.7·10  =  7     (7 students will earn an 'A'.)

                                 Number of C's:  1.4B  =  1.4 ·10  =  14     (14 students will earn a 'C'.)

sorry dear , but if it was that easy , it will be published as a formula or something like this

there are officials calculations

http://www.jstor.org/pss/2688509

http://www2.stetson.edu/~efriedma/cirincir/

http://en.wikipedia.org/wiki/Circle_packing_in_a_circle

but there is no such formula

as R2^2/r1^2 = number of circles of inside a R2 radius circle ...

cordially sir,

what do u add to 45 that when u divide it by 6 it equals 8 

45 + (11 - 8) =48

45 + (10 - 7)=48

48/6 = 8

You should learn how to use the calculator here:cos^-1( 7/14)=60 degrees.

It is true what you say!!.

Radius=Diameter / 2

R=22.5 / 2 =11.25 mm-Radius of large circle

R=.9 / 2 =.45 mm-Radius of small circle

Since the area of a circle is proportional to r^2, then we have:

11.25^2 / .45^2 =625 small circles that will fit in the larger circle.

The 2 mm circle is exactly the same as above. So, you will have: 11.25^2 / 1=126.5625. But you can round it off to 126 or 127.

This is a hard problem , there are only some approximations

like \(\frac{π}{12}\times \left ( \frac{{R}_{2}^2}{{r}_{1}^2} \right ) - \frac{π}{12} \times \left ( \frac{{R}_{2}}{{r}_{1}} \right )\)

R2 is the large circle , r1 is the small circle

you can use an approximiate calculator 

http://www.engineeringtoolbox.com/smaller-circles-in-larger-circle-d_1849.html

You may find this interesting

http://www.jstor.org/pss/2688509

http://www2.stetson.edu/~efriedma/cirincir/

http://en.wikipedia.org/wiki/Circle_packing_in_a_circle

Pie is a dessert you eat after dinner, sometimes!!!. But, Pi is a mysterious number that NEVER ends and goes on forever!!!!. When you study circles, you will hear about Pi everyday!!!.

what is equivalent to 256 3/4=256.75=1,027/4

If u have $25.65 in dimes and quarters, and you have 20 more quarters than dimes, how many dimes do you have?

Let the number of dimes=D

Then number of quarters=D+20

.10D + .25(D + 20) =25.65

.10D + .25D + 5     =25.65

.35D =25.65 - 5 =20.65 divide both sides by .35

D =20.65 / .35

D=59 dimes

59 + 20 =79 quarters, so that:

[59 x .10] + [79 x .25]=$25.65

what would be the answer to no more than 4 fives in 10 rolls

I think they're only using charts in order to define Cl

it called somewhat ( Velocity Relationship Curve Graph ) or something like this

not sure 

sorry

infinitely many equations

, remember any equations is defined by two points

here is only one point , you can give any other point as you like

and try to find the equation using \(m=\frac{y1-y2}{x1-x2}\)

and when you find m , try to find p , using either the first point or the point you guessed lol

\(\frac{d^3}{d^5} = d^3 * d^{-5} = d^{3-5} = d^{-2} \)

There are infinitely many solutions for this equation

you just need to give a value to x , in order to find y , or the opposite , giving a value to y in order to find x.

the (1,1), (8,1) and (5.5) are the (x,y) coordinates of the vertices. 

Area of a triangle is (base*height) divided by two or 0.5*b*h

Length of the base \(\sqrt{(8-1)^2+(1-1)^2}\) 

Length of base is 7 

Height = 5-1 = 4 

Area = (4*7)/2 = 14