All Answers 358149 Answers

$$\\\left(\frac{0.084\;kg}{1\;
\textcolor[rgb]{1,0,0}{\not}{w}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{k}
}\right)* \left( \frac{1\;
\textcolor[rgb]{1,0,0}{\not}{w}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{k}
}{7\;days} \right)=\frac{0.084}{7}\frac{kg}{days}=0.012\;\frac{kg}{days}\\\\
\Rightarrow 0.012\;\mbox{kg per day}$$

\\\left(\frac{0.084\;kg}{1\;
\textcolor[rgb]{1,0,0}{\not}{w}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{k}
}\right)* \left( \frac{1\;
\textcolor[rgb]{1,0,0}{\not}{w}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{e}\textcolor[rgb]{1,0,0}{\not}{k}
}{7\;days} \right)=\frac{0.084}{7}\frac{kg}{days}=0.012\;\frac{kg}{days}\\\\
\Rightarrow  0.012\;\mbox{kg per day}

Yes that is one way.

If it is a complicated function then you learn to recognise them and you can get the exact features from the numbers.

For example 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}} = {\mathtt{0}}$$   

Just by looking at it I can tell that it is a concave up parabola (like a u shape).  And it crosses the y axis at -6

And very tiny numbers too!

We can share 

Are you Gib's pet walrus?

---

No. I am a mouse. That’s why I know what the “meeses” do.

Jerry

PS does anyone have some cheese?

Jerry?

Are you Gib's pet walrus?

If you have escaped Gib will be very concerned about you.

http://web2.0calc.com/questions/130402-friday-private-message-from-gib#r103424

Thank you Angel.

And thank you for giving CPhill thumbs up too.  I don't know if he has seen your comment and 'thumb' yet but I know he will be very pleased!  

Melody.

You do inequalities exactly the same as equations EXCEPT

you have to turn the signs around if you

* swap sides

*multiply or divide by a NEGATIVE number

*Take the reciprocal of both sides (turn them upside down)

I think that about covers it.

Maybe this site will help

Good answer zegroes

Sorry Zegroes but you messed up!

$$sin^2(sin^{-1}x)\\

=[sin(sin^{-1}x)]^2\\

=x^2$$

This is because sine and inverse sine cancel each cancel each other out.

Well.....each "candy" must be cylindrical in shape and has a volume of

pi x r^2*h = pi x .25 * 1 = .25pi in³

And since the jar has a capacity of 104 in³

Then the number of candies it will hold = 104 /( .25 * pi) ≈ 132 candies

Easy, Anonymous.....Let's not turn Water into Whine.......

Why was the question Urgent?

Did you need to know how to divide the vodka to make screwdrivers?

0.084 kg divided by 7 is 0.012

...continued.

if x is in degrees:

$$\\cos(x) = cos\left[180\textcolor[rgb]{1,0,0}{\ensuremath{^\circ}}-cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]
\quad | \quad \pm cos^{-1}\\
\pm x=\pm \left[ 180\ensuremath{^\circ}} -cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]\\
x=180\ensuremath{^\circ}} -cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\\
cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]=180\ensuremath{^\circ}}-x
\quad | \quad \cos{}\\\\
\frac{0.25}{6,76}*\cos{(x)}=\cos{(180\ensuremath{^\circ}}-x)}\\
\frac{0.25}{6,76}*\cos{(x)}=\underbrace{\cos{180\ensuremath{^\circ}}}_{-1}\cos{(x)}
+\underbrace{\sin{180\ensuremath{^\circ}}}_{0}\sin{(x)}\\
\frac{0.25}{6,76}*\cos{(x)}=-\cos{(x)}\\
\frac{0.25}{6,76}*\cos{(x)}+\cos{(x)}=0\\
\cos{(x)}\left(\frac{0.25}{6,76}+1\right)=0\\
\cos{(x)}=0\quad | \quad \pm \cos^{-1}\\
\pm x=\frac{\pi}{2}\\\\
\boxed{x=\frac{\pi}{2} \pm 2\pi*k\qquad or \qquad x=-\frac{\pi}{2} \pm 2\pi*k}$$

\\cos(x) = cos\left[180\textcolor[rgb]{1,0,0}{\ensuremath{^\circ}}-cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]
\quad | \quad \pm cos^{-1}\\
\pm x=\pm \left[ 180\ensuremath{^\circ}} -cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]\\
x=180\ensuremath{^\circ}} -cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\\
cos^{-1}(\frac{0.25}{6,76}*\cos{(x)})\right]=180\ensuremath{^\circ}}-x
\quad | \quad \cos{}\\\\
\frac{0.25}{6,76}*\cos{(x)}=\cos{(180\ensuremath{^\circ}}-x)}\\
\frac{0.25}{6,76}*\cos{(x)}=\underbrace{\cos{180\ensuremath{^\circ}}}_{-1}\cos{(x)}
+\underbrace{\sin{180\ensuremath{^\circ}}}_{0}\sin{(x)}\\
\frac{0.25}{6,76}*\cos{(x)}=-\cos{(x)}\\
\frac{0.25}{6,76}*\cos{(x)}+\cos{(x)}=0\\
\cos{(x)}\left(\frac{0.25}{6,76}+1\right)=0\\
\cos{(x)}=0\quad | \quad  \pm \cos^{-1}\\
\pm x=\frac{\pi}{2}\\\\
\boxed{x=\frac{\pi}{2} \pm 2\pi*k\qquad or \qquad x=-\frac{\pi}{2} \pm 2\pi*k}

Thanks for letting me know Chris.

I/we will have to teach zegroes to give links instead of copying the whole answer.

wow that was very understanding when you explained it ... Thank you very much for helping me!

This is the answer ->...1+1=2

Well.....you're probably not "stupid'..it required some level of intelligence to find your way here, didn't it??...you just might know the answer to this question.

Remember........a man is considered wise if he admits he doesn't know something...

Well....enough of my pearls of wisdom

The answer is 15! = 1,307,674,368,000

The "!" is known as a  "factorial'

Let me give you a simpler example of this......Suppose we had three books on a shelf and we wanted to know how many different ways we could arrange them. Well, we have:

(3 ways to select the first book) x (2 ways to select the second book) x (1 way to select the last book) = 3 x 2 x1 = 3!

So, you can extrapolate this to your basketball roster by

15 x 14 x 13 x 12 x..........x 3 x 2 x1 = 15!

And that's it......Good luck to you...

12 grams per day?

That is one anorexic hamster.

Most hamsters eat 30 to 35 gram per day.

Dwarf hamsters eat 20 to 25 grams per day.

This hamster needs professional help!

Hamster Huey

(4 flavors) x (8 toppings) = 32 choices

.084 / 7 = .012kg

So we have

(√5 -3)²  =

(√5 -3) (√5 -3) ....which gives us

√5*√5 - 3√5 -3√5 +(-3)(-3)

5 - 6√5 + 9

14 - 6√5