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|5x-3|=-7x,  

\(x < 0\ !\)

\(\begin{array}{|rcll|} \hline |5x-3| &=& -7x \qquad & | \qquad \text{square both sides} \\ (5x-3)^2 &=& (-7x)^2 \\ 25x^2-30x +9 &=& 49x^2 \qquad & | \qquad -(25x^2-30x +9) \\ 0 &=& 49x^2 -25x^2+30x -9 \\ 0 &=& 24x^2 +30x -9 \\ 24x^2 +30x -9 &=& 0 \\\\ x_{1,2} &=& \frac{-30\pm \sqrt{30^2-4\cdot 24\cdot (-9) } }{ 2\cdot 24 } \\ x_{1,2} &=& \frac{-30\pm \sqrt{900+864 } }{ 48 } \\ x_{1,2} &=& \frac{-30\pm \sqrt{ 1764} }{ 48 } \\ x_{1,2} &=& \frac{-30\pm 42 }{ 48 } \\\\ x_1 &=& \frac{-30 + 42 } { 48 } \\ \mathbf{ x_1} &\mathbf{ =}& \mathbf{ 0.25 } \qquad \text{no solution } x > 0 \\\\ x_2 &=& \frac{-30 - 42 } { 48 } \\ \mathbf{ x_2} &\mathbf{ =}& \mathbf{ -1.5 } \\ \hline \end{array}\)

The only solution is x = -1.5

Each letter represents a non-zero digit. What is the value of t?

\(\begin{array}{|rrcll|} \hline (1): & c+o-u &=& 0\\ (2): & u+n-t &=& 0\\ (3): & t+c-s &=& 0\\ \hline (1)+(2)-(3): & ( c+o-u ) + ( u+n-t ) - ( t+c-s ) &=& 0+0 -0 \\ & \not \! c +o~ - \not \! u + \not \! u+n-t - t~ - \not \!c+s &=& 0 \\ & o +n+s -2t &=& 0 \\ & o +n+s &=& 2t \\ & 2t &=& o +n+s \quad | \quad o +n+s = 12 \\ & 2t &=& 12 \quad | \quad : 2 \\ & \mathbf{t} & \mathbf{=} & \mathbf{6} \\ \hline \end{array} \)

\(\frac{6}{7}-(-\frac{1}{6}-\frac{5}6)\\ = \frac{6}{7}-(-1)\\ =\frac{6}{7}+1\\ = 1\frac{6}{7}\)

Use the '2nd' button before the sin button

Factors to  (3x-2)(x+3) = 0

so x = -3  or 2/3

sqrt(8)+sqrt(2)

2sqrt(2) + sqrt(2)

=3sqrt(2)

Solve for x over the real numbers:
abs(5 x-3) = -7 x

Split the equation into two possible cases:
5 x-3 = -7 x or 5 x-3 = 7 x

Add 7 x+3 to both sides:
12 x = 3 or 5 x-3 = 7 x

Divide both sides by 12:
x = 1/4 or 5 x-3 = 7 x

Subtract 7 x-3 from both sides:
x = 1/4 or -2 x = 3

Divide both sides by -2:
x = 1/4 or x = -3/2

abs(5 x-3) ⇒ abs(-3+(5 (-3))/2) = 21/2
-7 x ⇒ -(7 (-3))/2 = 21/2:
So this solution is correct

abs(5 x-3) ⇒ abs(5/4-3) = 7/4
-7 x ⇒ -7/4 = -7/4:
So this solution is incorrect

The solution is:
Answer: |x = -3/2

sqrtab^2 over sqrt3a^2b

\(\frac{\sqrt{a\times b²} }{\sqrt{3\times a^{2b} } } \) = \(\sqrt{ \frac{ab²}{3a^{2b} } }\)

= \(\sqrt{ \frac{b²}{3a^{b} } }\)  = \(\frac{b }{\sqrt{3a^{b} } } \)

negative 2 and 1 over 6 – negative 7 and 1 over 3

6^-21 -  3^-71  = 4.55851871299 * 10^-17 - 1.33165251887 * 10^-34 

Factorise these by taking out common factors.

x^2−7x

x² − 7x = x(x - 7)

what is -4(-2)(-8)

- 4(- 2)(- 8) = - 4 * (- 2) * (- 8) = + 8 * (- 8) = - 64

minus times minus is plus.
plus minus times minus is.

What is 4-(-3) =

Minus before the bracket changes the sign in the brackets.
From minus is plus from plus is minus.

4 - (- 3) = 4 + 3 = 7

5*1/2+5?

\( 5\times \frac{1}{2} + 5= \frac{5+ 10}{2} = \frac{15}{2} = 7.5\)

I don't know I just posted a question on it. Maybe someone will answer.

0.2857142857142857

0.2857142857142857

it is not infinite, as 1000! has a finite number of digits, making it finite. I used Wolfram Alpha to prove this. 

37500 pesos. The combined area of the bedroom is 250 sq.ft. Multiply 250 sq.ft by 150 per sq.ft and you will get 37500 pesos.

(<) means that the number on the left is lower than the one on the right. (>) is just the opposite. 2>1 means that 2 is bigger than 1, which is true.