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whats the square root of 9896766976976

\(\sqrt(9896766976976)=4\sqrt(618547936)=4\sqrt(2*661*29243)\)

whats the square root of 38476

\(\sqrt(38476)=2\sqrt(9619)\)

whats the square root of 675

\(\sqrt(675)=5\sqrt(27)=15\sqrt3\)

whats the square root of 3241135153515332323

\(\sqrt(3241135153515332323)=\sqrt(3241135153515332323)\)

whats the square root of 987

\(\sqrt(987)=\sqrt(3*7*47)\)

\(\sqrt(98967^(32956643729657634/\pi))\)

=98967^{16478321864828817/\(\pi\)}

A=30m²

l=\(\sqrt5\)m

w=?

P=?

A=lw

\(30=w\sqrt5\)

\({30\over\sqrt5}={30\sqrt5\over5}=6\sqrt5=w\)

P=2(l+w)

P=2(\(\sqrt5+6\sqrt5\))

=\(2*7\sqrt5=14\sqrt5\)

\(P=14\sqrt5\)

it can be positive or negative 4 depending on the signs

x^2  -  1.

2x^8-4x^4=16

29 people

4people/team

\(29people*1team\over4people\)= 7 teams and 1 person not on a team

I am not sure what you are asking.....

Please help.

<:)

Assuming the acetone is a 100% solution:

15 / (15+28) x 100% = 34.88 %

674 / 68   is 674 divided by 68  = 9 r 62   =   9  62/68  =  9 31/34

What's f'(x)?

how many years is 2,354 days?

2345days * \(\frac{1Year}{365.25days} = \) \(6Years+ \ 0.42026009582Year \times \frac{365.25days}{Year} \) 

\(2345days =\)  \(6Years\) + \(153\ days\) \(including \ 2 \ leap\ years\)

Why is....

Why is.....

=(1-1/x^2) x^2

Find the sum of series

LOL XP thx Melody 

\(\dfrac{d}{dx}\ln (\sin x)\\ u=\sin x\,\,\,\, y=\ln u\\ \dfrac{dy}{dx}=\dfrac{dy}{du}\times \dfrac{du}{dx}=\dfrac{1}{u}\times \cos x=\dfrac{\cos x}{\sin x}=\cot x\)

\(\therefore f'(x)= \dfrac{d}{dx}(5x^2) + \cot x = 10x + \cot x\)

YES, being 13 and learning calculus is EVEN more cool :))

Hi Max,

Calculus is ALWAYS COOL  LOL

I don't need synthetic nor long division. I have a method because it's just multiple choice, who knows you haven't used synthetic or long div xD.

Remainder theorem. R(x) = 5(8)^3 + 9(8)^2 - 10(8) + 6 = 3,062.

Answer = B

Let x be the number of $2 notes Charlene have.

2x + 5(500-x)=1360

2x + 2500 - 5x = 1360

-3x = -1140

x = 380

Charlene have 380 $2 notes.

\(\dfrac{8.89g}{1cm^3}\\ = \dfrac{8.89\times 10^{-3}kg}{1\times 10^{-6}m^3}\\ = (8.89\times 10^3)kg/m^3\\ = 8890kg/m^3\)

This looks hard but I will give it a try.

\(\text{Let }x=\log\left(e^{(1+2i)}\right)\\ 10^x= e^{1+2i}\\ 10^x=e\times (e^i)^2\)

\(e^{i\pi}+1=0\\ (e^i)^\pi + 1=0\\ (e^i)^\pi=-1\\ e^i=(-1)^{\frac{1}{\pi}}\)

\(10^x=e\times (-1)^{\frac{2}{\pi}}\\ 10^x = e\times (1)^{\frac{1}{\pi}}\\ 10^x = e\\ x = \log e\)