All Answers 358335 Answers

(3.173 x 10^8) - (3.09 x 10^8) =8.3 x 10^6

Use the formula:

Density=Mass / Volume, or

Volume=Mass/Density

Make sure that the density is correct. It cannot be 230 g/cm^3. There is NO SUBSTANCE on Earth that is that dense. It must be 2.30 g/cm^3.

what is 56 and 7/8 as a decimal

56+7/8 = 56.875

Np. :D

25)Format of equation of vertical line: x = (x-coord of passing point.).

ANS : D.

27) The function is y = 4.25x + 50 and that's elementary....... Solving is elementary too....... Just substitute x = 6 into the formula.

y = 4.25(6) + 50 = 25.5 + 50 = $75.5 OR $75.50 

ANS : D.

28) integers means negative and positive whole numbers. negative money is odd right? SO the answer won't be A and B.

D wouldn't be the answer too because you won't have $sqrt3 in your wallet.

ANS: C.

Thank you! You're a life saver!

Type in 208sqrt(3) in the calc and press 'Enter' on your keyboard

23) We subtitute x = -1 and y = 4 in each of the choices to test out what is the answer.

ANS : A

17) You have to test all those methods on that equation until you found out in one method the last step is x = something.

ANS : B

15) We first make the function slope-intercept form:

\(2x+5y = -30 \\5y = -2x-30\\ y = -\dfrac{2}{5}x-6\)

The format for slope intercept form is : y = (slope)x + (y-intercept) or y = mx + b

Now equate the terms: b = -6

Therefore the y-intercept is -6. ANS: D

Because this is the maths forum!! :D Welcome because you just signed up!! :D

\(\sqrt{1.2}\times \sqrt{3}\div \dfrac{1}{3}\)

= \(\sqrt{3.6}\times 3\\ =\dfrac{6}{\sqrt{10}}\times 3\\ =\dfrac{18}{\sqrt{10}}\\ =\dfrac{18\sqrt{10}}{10}\\ =\dfrac{9\sqrt{10}}{5}\)

Why are you guys so good at math :( LOL

See your later post.

\(\dfrac{0.3}{0.2(2.9)}\\ =\dfrac{0.3}{0.58}\\ =\dfrac{30}{58}\\ =\dfrac{15}{29}\)

\(\sqrt{4+2\sqrt{3}} - \sqrt{4-2\sqrt{3}}\\ =\sqrt{3+2\sqrt{3}+1} - \sqrt{3-2\sqrt{3}+1}\\ =\sqrt{\sqrt3^2+2\sqrt{3}+1^2} - \sqrt{\sqrt3^2-2\sqrt{3}+1^2}\\ =\sqrt{(\sqrt3+1)^2}-\sqrt{(\sqrt3-1)^2}\\ =(\sqrt3+1)-(\sqrt3-1)\\ =\sqrt3 -\sqrt3 + 1 - (-1)\\ =2\)

\((1.067)^{\frac{1}{12}}\)

= \(\sqrt[12]{1.067}\)

\(\approx 1.0054188769814263\)

Very impressive Max :D

25 + 56 = 81 = 8.1 x 10^1

\(a = \dfrac{a}{1}\)

5 = 5/1

6 = 6/1......

Given that the point (4,7) is on the graph of y=f(x), there is one point that must be on the graph of 2y=3f(4x)+5. What is the sum of coordinates of that point?

If x=1 then  f(4x)=f(4)=7

so

2y=3*7+5

2y=26

y=13

So that one point could be   (1,13)

 I suppose the sum of the co-ordiantes is 1+13=14

It is a bit of a weird question but that is what I think ://

:) 

:)

:)

\(\cdot\;\cdot\\ \smile\)

I would like you to share your answers to these questions.

I will go first :)

1) \(\dfrac{x^{-1}+y^{-1}}{x+y}\\ =\dfrac{(x^{-1}+y^{-1})(xy)}{(x+y)(xy)}\\ =\dfrac{y + x}{(x+y)(xy)}\\ = \dfrac{1}{xy}\)

2)\(\dfrac{x^{-1}-y^{-1}}{x-y}\\ =\dfrac{(x^{-1}-y^{-1})(xy)}{(x-y)(xy)}\\ = \dfrac{-(x-y)}{(x-y)(xy)}\\ =-\dfrac{1}{xy}\)

3)\(\dfrac{x^{-2}+y^{-2}}{x+y}\\ =\dfrac{\frac{1}{x^2}+\frac{1}{y^2}}{x+y}\\ = \dfrac{\frac{x^2+y^2}{(xy)^2}}{x+y}\\ =\dfrac{x^2+y^2}{(xy)^2(x+y)}\)

4)\(\dfrac{x^{-2}-y^{-2}}{x-y}\\ =\dfrac{(x^{-1}+y^{-1})(x^{-1}-y^{-1})}{x-y}\\ =\dfrac{x^{-1}-y^{-1}}{x-y}(x^{-1}+y^{-1})\\ =-\dfrac{x^{-1}+y^{-1}}{xy}\)

The last step of 4) is from 2)!!

Thanks Max :))

\(-a^2b^2(5a^3b-3b^3)\\=-5a^5b^3+3a^2b^5\)

You just multiply all the terms in the bracket with the -a^2b^2 term.