Rectangle abcd has a length of 4x+1 and a width of 2x-5 rectangle edfg has. A legmth of 3x+2 and a width of of x-3 what is the sum of the perimeter?
Perimeter=2 [L + W]
Rectangle:abcd: 2[4x+1 +2x - 5] + Rectangle edfg: 2[3x+2 + x - 3]
Simplify the following:
2 (4 x+2 x-5+1)+2 (3 x+x-3+2)
Grouping like terms, 4 x+2 x-5+1 = (4 x+2 x)+(1-5):
2 ((4 x+2 x)+(1-5))+2 (3 x+x-3+2)
4 x+2 x = 6 x:
2 (6 x+(1-5))+2 (3 x+x-3+2)
1-5 = -4:
2 (6 x+-4)+2 (3 x+x-3+2)
Grouping like terms, 3 x+x-3+2 = (3 x+x)+(2-3):
2 (6 x-4)+2 ((3 x+x)+(2-3))
3 x+x = 4 x:
2 (6 x-4)+2 (4 x+(2-3))
2-3 = -1:
2 (6 x-4)+2 (4 x+-1)
2 (6 x-4) = 12 x-8:
12 x-8+2 (4 x-1)
2 (4 x-1) = 8 x-2:
8 x-2+12 x-8
Grouping like terms, 12 x+8 x-8-2 = (12 x+8 x)+(-8-2):
(12 x+8 x)+(-8-2)
12 x+8 x = 20 x:
20 x+(-8-2)
-8-2 = -10:
20 x+-10
Factor 10 out of 20 x-10:
Answer: |10 (2x - 1)
