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find common factors on both the bottom and top - and them eliminate them

\(\frac{4x+8}{2x+16}\)

find common factors

\(\frac{2(2x+4)}{2(x+8)}\)

eliminate

\(\frac{2x+4}{x+8}\)

ta dah!

No this isn't a graphs question. Its like angles..

this is a graph question right?

if so - what x value do you want - the intersect?

Im assuming without a calculator;

well - lets turn \({3.806}^{2}\)

into \({(x+0.806)}^{2}\) where \(x=3\)

now we expand \(x^2 +2(0.806)+{(0.806)}^{2}\)

0.806\(\times\)0.806 is much easier to do than 3.806^2

\(0.806\times0.806 = \)

2((0.806 * 0.400)+(0.806 * 0.003))

2((0.32+0.0024)+(0.002418))

2(0.3224+0.002418)

2(0.324818)

0.649636

\(x^2+2(0.806)+0.649636\)

sub \(x=3\)

\((3)^2+2(0.806)+0.649636\)

\(9+1.612+0.649636\)

\(11.261636\)

ta dah!

10141204801825835211973625643008*8 = 81129638414606681695789005144064

Suck it up butter cup!

sup

4^5-8*25-50+7=781

562500/(.75*11)/365 = 186.7995018679950187

Hello! :)

ASAP or as so as possible

              A    S   A  P

In awnser to your second question;

Chan rule is essentially used to differentiate anything in silly brackets - ie. if the powers of the brackets mean that binomial expansion would take too long. ie.\({(x^2+x+1)}^{5}\)

The product rule is used to differentiate any chain rule (ie. any silly bracket powers) when they are multiplied by anything esle; ie \(x{(x^2+x+1)}^{5}\)

The quotient rule is used when you have a chain rule, but it is part of a fraction. ie\(\frac{x}{{(x^2+x+1)}^{5}}\)

However - the quotient rule is simply the product rule in a different form - i would reccomend turning all quotient rule questions into product rule questions; as \(\frac{x}{{(x^2+x+1)}^{5}}\)\(= (x){(x^2+x+1)}^{-5}\)

Where is your question?   You list a temp  and a pressure and a density.....but no question.

some more info would help... xD

Factor the following:
2 x^4-x^3-7 x-10

The possible rational roots of 2 x^4-x^3-7 x-10 are x = ±1/2, x = ±5/2, x = ±1, x = ±2, x = ±5, x = ±10. Of these, x = -1 and x = 2 are roots. This gives x+1 and x-2 as all linear factors:
((x+1) (x-2) (2 x^4-x^3-7 x-10))/((x+1) (x-2))

 | |
x | - | 2 | | 2 x^3 | + | 3 x^2 | + | 6 x | + | 5
2 x^4 | - | x^3 | + | 0 x^2 | - | 7 x | - | 10
2 x^4 | - | 4 x^3 | | | | | |
 | | 3 x^3 | + | 0 x^2 | | | |
 | | 3 x^3 | - | 6 x^2 | | | |
 | | | | 6 x^2 | - | 7 x | |
 | | | | 6 x^2 | - | 12 x | |
 | | | | | | 5 x | - | 10
 | | | | | | 5 x | - | 10
 | | | | | | | | 0:
(2 x^3+3 x^2+6 x+5)/(x+1) (x+1) (x-2)

 | |
x | + | 1 | | 2 x^2 | + | x | + | 5
2 x^3 | + | 3 x^2 | + | 6 x | + | 5
2 x^3 | + | 2 x^2 | | | |
 | | x^2 | + | 6 x | |
 | | x^2 | + | x | |
 | | | | 5 x | + | 5
 | | | | 5 x | + | 5
 | | | | | | 0:
Answer: |2 x^2+x+5 (x+1) (x-2)

Firstly - convert the fraction into a linear equation;

\(1/(x^2+1)\) goes to \(1\times{(x^2+1)}^{-1}\)

Now you can just use the chain rule - or whatever you have been taught

let \(u=x^2+1\)

therefore \(f(x) = 1+ {(u)}^{-1}\)

therefore\(\frac{dy}{dx}(1+{(u)}^{-1})=-1{(u)}^{-2}\)

thats part one \o/

Part two;

if \(u=x^2+1\)

therefore \(\frac{dy}{dx}(x^2+1)=2x^1+0\)

Combine part two and part one;

\((2x)(-1){(u)}^{-2}\)

sub in for \(u\)

\((2x)(-1){(x^2+1)}^{-2}\)

simplifiy brackets

\(-2x{(x^2+1)}^{-2}\)

turn into a fraction

\(\frac{-2x}{(x^2+1){}^{2}}\)

ta dah!

-95

Its actually 19. ^^

Find the derivative of the following via implicit differentiation:
d/dx(f(x)) = d/dx(1/(1+x^2))
The derivative of f(x) is f'(x):
f'(x) = d/dx(1/(1+x^2))
Using the chain rule, d/dx(1/(x^2+1)) = d/( du)1/u 0, where u = x^2+1 and ( d)/( du)(1/u) = -1/u^2:
f'(x) = -(d/dx(1+x^2))/((x^2+1)^2)
Differentiate the sum term by term:
f'(x) = -1/(1+x^2)^2 d/dx(1)+d/dx(x^2)
The derivative of 1 is zero:
f'(x) = -(d/dx(x^2)+0)/(1+x^2)^2
Simplify the expression:
f'(x) = -(d/dx(x^2))/(1+x^2)^2
Use the power rule, d/dx(x^n) = n x^(n-1), where n = 2: d/dx(x^2) = 2 x:
f'(x) = -1/(1+x^2)^2 2 x
Expand the left hand side:
Answer: |f'(x) = -(2 x)/(1+x^2)^2

In expanded form:

f(t) = 5184 t^10+8640 t^9+2160 t^8-3360 t^7-1700 t^6+444 t^5+345 t^4-20 t^3-30 t^2+1

Factor the following: x^2-13 x-30 The factors of -30 that sum to -13 are 2 and -15. So, x^2-13 x-30 = (x+2) (x-15): Answer: | | (x+2) (x-15)

what is 2700000 in standard form.

It is ALREADY in standard form!!.

2,700,000 = 2.7 x 10^6 This is in scientific notation.

what is 75.2% of 248,709,873. or how do i solve this question divide, multiply, subtract, or add? 

75.2% means =75.2 / 100 =0.752, then you multiply:

0.752 x 248,709,873 =187,029,824.496, which is the answer.