Let the perhelion = .59 * 93,000,000 = 54,870,000 miles
Let the aphelion = 35.09 * 93,000,000 = 3,263,370,000 miles
(a) Then...the length of the major axis = 54,870,000 + 3,263,370,000 = 3,318,240,000 miles
Then the length of the semi-major axis = 3,318,240,000 / 2 = 1,659,120,000 miles = "c"
And the distance from the center of the ellipse to the Sun = "a" = 1,659,120,000 - 54,870,000 = 1,604,250,000 miles
(b) [ The co-ordinates of the Sun = (1,604,250,000 , 0 )
We need to find the length of the semi-minor axis = "b" thusly
b = √ [c^2 - a^2] = √ [ 1,659,120,000^2 - 1,604,250,000^2 ] ≈ 423,156,132 miles
So....our [approximate] equation is
x^2 /a^2 + y^2/b^2 = 1
(c) x^2 / 1,604,250,000^2 + y^2 / 423,156,132^2 = 1
The eccentricity = distance from the center to the foucus / length of the semi-major axis =
(d) 1,604,250,000 / 1,659,120,000 ≈ .9669 = .97
