All Answers 358940 Answers

normally you divide it by 3.14

The compound interest formula is given by:

Where

P = principal amount (the initial amount you borrow or deposit)

r  = annual rate of interest (as a decimal)

t  = number of years the amount is deposited or borrowed for.

A = amount of money accumulated after n years, including interest.

n  =  number of times the interest is compounded per year

 To solve for t......

First divide both sides by P

Now, take the log of both sides....this will give us

log (A/P) = log (1 + r/n)^nt

And by a  property of logs, we can bring the (nt) "out front," and we can write

log (A/P) = (nt)* log (1 + r/n)    ........ Now divide both sides by n  and log(1 + r/n)

So we have

[log (A/P)] / [n * log(1 + r/n] = t

And that's what "t" is

The answer is 40

For #7 - 13, it is mostly using the Distributive Property, as well as polynomial multiplication.

The formula for the volume of a pyramid is:

$${\mathtt{V}} = {\frac{{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{Ah}}$$ where A is the area of the base and h is the height of the pyramid (perpendicular to the base, not the slant height).

The area of the base for a triangular pyramid would be the area of the triangle, which would be $${\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{Bh}}$$ where b is the length of the base of the triangle, and h is the height of the triangle.

Once you find the area of the pyramid's base, substitute that value for A in the first equation above, and multiply it by (1/3) and the height of the pyramid.

This page can help as well:

http://www.mathsteacher.com.au/year10/ch14_measurement/25_pyramid/21pyramid.htm

We need a picture of "A" or some other information - like two points that lie on "A."

That would, I believe, depend on what A is.

You can divide by the commonly used value for pi  = 3.14

when you say to plot what exactly do you mean?? Can you give me an example?? 

To divide 3/4 by 4/7:

Multiply 3/4 by 7/4.

21/4    Keep your answer in fraction form, unless otherwise noted

This is just a single point at x-coordinate 6 and y-coordinate 4.

5n² = -42n

One solution is n = 0

Another is found when n is not 0. In that case you can divide both sides by n to get

5n = -42

Divide both sides by 5

n = -42/5

or n = -8.4

Enter 1 + 3/4 + 5 + 4/9 in the calculator.

Just type in your calculator 64/100*25

25% is a quarter. A quarter of 64 is 16.  

Type alt 0176 on the numeric keypad (keeping your finger on the alt key while you type the numbers).

3(x+2)+4(2x+1)

3x+6+8x+4

11x+10

If tan(A)=0.333 then A = tan^-1(0.333)  (on a calculator tan^-1 is usually represented by atan) so:

$${\mathtt{A}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.333}}\right)} \Rightarrow {\mathtt{A}} = {\mathtt{18.417\: \!758\: \!370\: \!539^{\circ}}}$$

A ≈18.4° This is the result in first quadrant.

Because tan also has the same value in the 3rd quadrant the solution could also be A = 180°+18.4° = 198.4°

Not quite rosala.

If 5=6/x, multiply both sides by x to get 5x = 6.

Now divide both sides by 5 to get x = 6/5 (or x = 1.2)

Do it one step at a time.

Then it seems like you should plot the first of the eight values at 15 seconds, the second at 30 seconds, the third at 45 seconds and so on.

 However, you should really have recorded the time at which you took each measurement.  There is likely to be a lot of unnecessary scatter otherwise!

I determine the values of DO with portable dissolved oxygen meter at school but i didn't write the time of every value of DO    The only data i have for time calibration  like i said in the beginning is to measure 8 values of DO per 15 sec for 2min 

let me tell u that the puzzle is perfectly correct !

but ur method ist and also the puzzle contains all the information required to solve it ,i would suggest u to understand the puzzle much nicely and if u cant understand it thats the reason for its called a "Puzzle " !

think before it !

5=6/x

x=6*5

x=30

isnt that the answer , melody !

i didnt knew that method alan and i think its the correct one ! so rebeenjalal u follew alans method ! alan thumbs up from me 

$${\mathtt{1\,234\,567\,890}}{\mathtt{\,\times\,}}{\mathtt{1\,234\,567\,890}} = {\mathtt{1\,524\,157\,875\,019\,052\,100}}$$

Pretty, isn't it?