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Initial vertical velocity u_h = 22.5*sin(33deg) m/s

At the highest point the vertical velocity is zero, so using v = u + at we have:

0 = 22.5*sin(33deg) - 9.8t. where the acceleration of gravity is 9.81m/s² downwards.  From this you can get the time, t, in seconds.

The horizontal velocity is given by u_h = 22.5*cos(33deg) m/s so the distance (in metres) travelled in time t is given by multiplying this velocity by the value found for t.

97/12 = 8 r 1

i.e. It is 8 remainder 1

.

2a-(8a+1)-(a+2)*5=9

Sorry I forgot the 5.

\(2a-(8a+1)-(a+2)\times5=9 \)

\(2-8a-1-5a-10=9\)

\(-13a=9+10+1-2\)

\(-13a=18\)

\({\color{blue}a=-\frac{18}{13}}\)       !

\({\color{blue}a=-1\frac{5}{13}}\)      !

1/2 to1/35

\(\frac{1}{35}\ to\ \frac{1}{2}= \frac{1}{2}- \frac{1}{35}\) 

\( \frac{1}{2}- \frac{1}{35}= \frac{1\times 35-1\times2}{2\times35}\)   The smallest common multiple is 70.

\({\color{blue}=\frac{33}{70} = 0.045047}\) !

if sinx=0.3, determine the value of sinx+sin(x+2(3.14159))+sin(x+4(3.14159))

\(sinx+sin (x+2\pi)+sin (x+4\pi)\)

\(= sin x+sinx+sinx\)

\(=3sinx\)

\(if \ sinx=0.3\ then\)

\(sinx+sin (x+2\pi)+sin (x+4\pi)\)

\({\color{blue}=3\times0.3 = 0.9}\)    !

2a-(8a+1)-(a+2)*5=9

\(2a-(8a+1)-(a+2)=9 \)

\(2-8a-1-a-2=9\)

\(-9a=9+2+1-2\)

\(-9a=10\)

\({\color{blue}a=-\frac{10}{9}}\)       !

\({\color{blue}a=-1\frac{1}{9}}\)      !

What is the full number of 1.12477401e21?

1.12477401e21. This is the full number. It means=1.12477401 x 10^21 in scientific notation.

what is the period for 1/17?

1/17 = 0.0588235294117647 0588235294117647 . Its period is 16 digits.

2011^2011 =[1.45102190 x 10^6643] mod 5 = 1

You can try it!. But there are special online calculators for almost everything including "Statistics", such as this one: https://www.hackmath.net/en/calculator/statistics

Just copy and paste it in the address bar of your Browser.

The squared button is where it say x²  on the scientific calculator. And you just push the divide button for a fraction, or a fraction bar.

0. 

Subtracting a negative is like adding a positive number. So it's pretty much saying -8+8.

Find all pairs of real numbers (x,y) such that x+y=6 and x^2+y^2=28.

2011^2011=infinity

infinity/5=

infinity/5

If you round, then 97/12 is 8. But if you are looking for decimal, then it would be 8.083333----.

Find all pairs of real numbers (x,y) such that x+y=6 and x^2+y^2=28.

x = 3-sqrt(5) ≈ 0.763932 and y = 3+sqrt(5) ≈ 5.23607

x = 3+sqrt(5) ≈ 5.23607 and y = 3-sqrt(5) ≈ 0.763932

The square of an integer is 182 greater than the integer itself. What is the sum of all integers for which this is true?

Let the integer = N

N^2 = N + 182, solve for N

N = 14 and N = - 13

14 + (-13) = 1

2+3y=4y-1 subtract 3y from both sides

2 = y - 1     add 1 to both sides

y = 3

You have to know the value of one of the variables: P , Q, TC=A in order to get a numerical solution.

By the way, what is 2 doing at the end of this term: 0.004Q2 ? Is it supposed to be Q^2??.

 y=2x+10 and y=2x+15

The lines have the same slope.........only their y intercepts are different.......the first line has a y intercept of 10 and the second has a y intercept of 15....so....the lines are 5 units apart

Mole/2039

1 mole =6.022 x 10^23

[6.022 x 10^23] / 3039 =1.98 x 10^20

18 minutes / 60 =0.3 degrees

54 + 0.3 =54.3 degrees

90 - 54.3 =35.7 degrees

2011^2011 mod 5 = 1

If you're referring to arcsin, arccos, arctangent, etc.......hit the "2nd" key and you will find asin, acos, atan, etc.