All Answers 356018 Answers

Agreed!!. Most certainly you have nothing else to do!!.

62134

exterior angle = (180+ (360/15)) deg = 204 deg

internal angle = (180- (360/15)) deg = 156 deg

Sum = 360 deg

sqrt3(27x^6)

\(\sqrt[3]{27x^6}\\ =({27x^6})^{1/3}\\ ={27^{1/3}(x^6})^{1/3}\\ ={27^{1/3}x^{6/3}}\\ =3x^{2}\\\)

sqrt3(125y^12)

You should try this one by yourself :)

My goodness, you must be bored tonight/today.  

40%

1/6

9/20

9/20

what is the critical points in this equation F(x) = x^3-3x^2+3x+1?

Mr Google tells me that critical point is what Americans call stationary points.

Ok well that is when the first derivative =0

F(x) = x^3-3x^2+3x+1

F'(x) = 3x^2-6x+3

3x^2-6x+3=0

x^2-2x+1=0

(x-1)^2=0

x=1   

F(1) = 1-3+3+1=2

so the only critical point is (1,2)

F''(x) = 6x-6

F''(1) = 6-6=0 Mmm

As x tends to 1 from above, f"(x)>0    concave up

As x tends to 1 from below, f"(x)<0    concave down

So at (1,2) there is a horizontal point of inflection.

-7 X x

= -7x

I know what I did wrong 

I was writing math down in a document (diffing and integrating) then pasting the result & original function in a calculator if I had trouble simplifying. Silly me kept thinking that f prime of x is what I got after integrating back because I never actually finished the cycle, pasted f prime of x next to the original problem ...

(with an equal sign in between and less syntax denoting them) and they did not make a true statement. I kinda got panicky cause my problem most of the time is copying the problem down wrong and not - not finishing the problem - and I had it copied just as it should have been to begin.

So with that, I am sorry for jumping so quickly for help from anyone willing to do so!

  - That guy who is probably gonna keep doing it, even though he is sorry, as he has panicky math issues.

On a side note, why do you use ∫ syntax when integrating... and it's not necessary to? So much easier to just rewrite the original alone instead of a ton of unnecessary information and gaps. Just curious if you think ∫ looks cool or like that sense of completeness... Looking at you Melody.

When you subtract one square number from another the answer is 35. What are the two square numbers?

\(\begin{array}{rclrr} a^2 - b^2 &=& 35 \\ \underbrace{(a-b)}_{=5}\cdot \underbrace{(a+b)}_{=7} &=& 35 = 5\cdot 7 \\ \end{array}\)

\(\begin{array}{lrcl|r|r} & && & I. & II. \\ \hline & a-b &=& 5 & \\ & && & + & - \\ & a+b &=& 7 & \\ \hline \end{array} \)

\(\begin{array}{lrcl} I. \\ & 2a &=& 7+5 \\ & 2a &=& 12 \\ & a &=& 6 \\\\ II.\\ & 2b &=& 7-5\\ & 2b &=& 2 \\ & b &=& 1 \end{array}\)

\(\begin{array}{|rcll|} \hline 6^2 - 1^2 &=& 35 \\ \hline \end{array}\)

YOU DON'T !

6^2 - 1^2 = 36 - 1 → 35

.

y = 1/ln(x)

y = ln(x)^-1

dy/dx = -ln(x)^-2*(dln(x)/dx)

Now dlnx)/dx = 1/x so dy/dx = -ln(x)^-2/x  or  dy/dx = -1/(x*ln(x)^2)

.

If we assume it is the x-axis that forms the tangents at x = -5 and x = 2, then we can do the following:

The y-intercept is just the value we chose for g.

It would be tedious to solve the four simultaneous equations for a, b, c and d by hand though!

.

(1/2)!

(1/2)! = 0.8777726925922196

sqrt(pi)/2 = 0.8862269254527579

Yes that does seem to be a rather big error. :/