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OK......got your ORIGINAL funcion.......when you differentiate constants go away.... when you INTEGRATE constants get added...are you differnetiatin w respect to x or y?

dx  or dy ?

The web 2 calc will do that too ElectricPavlov - well it will if you are using it on the home page anway, but this number is just too large large to be displayed.

I just tried it on my casio and i got the same result that is 'maths error'

Wolfram Alpha does give an approximation but few calcs would.

differentiate y=In tan^2x

\(y=ln(tan^2x)\\ \frac{dy}{dx}=\frac{2tanxsec^2x}{tan^2x}\\ \frac{dy}{dx}=\frac{2sec^2x}{tanx}\\ \frac{dy}{dx}=\frac{2cosx}{sinxcos^2x}\\ \frac{dy}{dx}=\frac{2}{sinxcosx}\\ \frac{dy}{dx}=\frac{4}{sin2x}\\ \frac{dy}{dx}=4cosec2x\\ \)

Thanx!   It is always good to have + and - feedback .....that is how I RE-learn all of that 'stuff' from so long ago....

    G'Day ! (P.S.....Why not get an account?)

Some calculators will switch to EXPONENTIAL display...or SCIENTIFIC notation.... you lose some ACCURACY, but at such LARGE numbers it is usually insignificant.......YMMV

Thanx for your answer! It always helps ME to have a financial person on this site !

Really??? 'Time' magazine????  What a liberal piece of junk that is....Google is too!   C'mon ! What kind of brainwashing are you subliminally  being subjected to?????   THIS is a horribly biased question I will NOT answer.

Calculating a bond price has 2 components:

1) Find the PV of par value of the bond, using the commonly known PV formula.

2)Find the PV of the stream of coupons, using the commonly used Annuity Formula.

3) Add 1 and 2 above together, which is your bond price.

Calculating all of the above, you get:

1 =$35.55 + 2=$57.29, and the total is:

$92.84 per hundred(bond prices are calculated per $100). Simply divide by 100 and multiply by any amount you may have.

Guest answerer is absolutely correct but the number is not infinity it is just that it is too big to display so this calc says it is infinity but it isn't really.   

Solve the following system:
{4 P+2 Q = -2 | (equation 1)
4 Q-2 P = 16 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 P+2 Q = -2 | (equation 1)
0 P+5 Q = 15 | (equation 2)
Divide equation 1 by 2:
{2 P+Q = -1 | (equation 1)
0 P+5 Q = 15 | (equation 2)
Divide equation 2 by 5:
{2 P+Q = -1 | (equation 1)
0 P+Q = 3 | (equation 2)
Subtract equation 2 from equation 1:
{2 P+0 Q = -4 | (equation 1)
0 P+Q = 3 | (equation 2)
Divide equation 1 by 2:
{P+0 Q = -2 | (equation 1)
0 P+Q = 3 | (equation 2)
Collect results:
Answer: |P = -2              and               Q = 3

The calculator here has a maximum display of 199! =~10^372. Do you have any understanding how big your number is? You simply cannot comprehend it!!!!.

There are different methods used to calculate " effective annual rate" on discounted notes in many countries. In the USA, the "EAR" is calculated as follows:

EAR =[1 +(quoted rate/n) ]^n - 1, where "quoted rate" =8.53%, n =365/60.

EAR =[1 + (0.0853/(365/60)) ]^(365/60) - 1

EAR =[1 + 1.01402192]^6.0833 - 1

EAR = 1.0884 - 1 x 100

EAR = 8.84% Effective annual rate.

Wow....a little unclear here.....what is 'E' ??

You didn't give enough information.....haha     DO their ladders reach all of the way to the top????  I hope not!!!!

Perimeter of WHAT???    Need more info please !

Don't overthink it ! LOL   The velocities are just additive   3 + 6 = 9 m/s   

Believe me   ....  I paddled 450 miles of the Yukon River in a canoe two years ago.....it was always GREAT to find a fast current !!!!!!!!

EP: From "Guest #4" answer, your answer #9 is the correct answer. And it is the sum of a "Geometric Series", whose 1st. term=2,400, common ratio =1.04 and the number of terms=40.

" U "

Correction: I used the wrong coeeficient of friction in my previously posted solution   

    I used 0.4 instead of the stated 0.1  

Here are the corrections:

Friction force =  .1  x 44.55 = 4.455

Required pushing force =  4.455kg + 22.69 = 27.15 kg force

Sorry !!!!!

That depends on the speed (velocity??) the diesel is flowing at.

Or if you want to do it manually (though maybe not recommended as this can get rather tedious), multiply 6 by itself 50 times  :)

6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6

(I think that's 50 times?)

I'm assuming you want to simplify the expression?

Original expression

          (a + b + c)² - (a + b - c)²

Expand exponents

          (a + b + c) * (a + b + c) - (a + b - c) * (a + b - c)

Multiply out the brackets (essentially FOIL)

          (a² + ab + ac + ba + b² + bc + ca + cb + c²) - (a² + ab - ac + ba + b² - bc - ca - cb + c²)

Substitute in the minus sign (second brackets set) and remove all the brackets

          a² + ab + ac + ba + b² + bc + ca + cb + c² - a² - ab + ac - ba - b² + bc + ca + cb -c²

Simplify like terms (and cancel out the ones that aer opposite {ex. +2ab and -2ab})

          a² + 2ab + 2ac + b² + 2bc + c² - a² - 2ab + 2ac - b² + 2bc - c²

          2ac + 2bc + 2ac + 2bc

             4ac + 4bc

Pull out the 4 and the c as they are constant in all remaining terms

          4c(a+b)

Breathe a breath of relief :)

\(\sqrt{3x^2-5x}=\sqrt{x^2+2x+5}\) помогите

Firstly both expressions under the sqrts must be positive.  I'll think about that more later.

\(3x^2-5x=x^2+2x+5\\ 2x^2-7x-5=0\\ 2x^2-7x-5=0\\ \triangle=49+40=89\\ x=\frac{7\pm\sqrt{89}}{4}\)

(7+sqrt(89))/4 = 4.108495283014151

(7-sqrt(89))/4 = -0.608495283014151

x=\frac{7\pm\sqrt{89}}{4}

 3*(4.108495283014151)^2-5(4.108495283014151) = 30.096724056577831167 >0   The plus version is good

3*(-0.608495283014151)^2-5(-0.608495283014151) = 4.153275943422170167  >0   Good

By visual inspection I can see that the DH sides will be real.

So the answers are     \(x=\frac{7\pm\sqrt{89}}{4}\)

Here is the graph