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TAN = sin/cos   so where it would equal 1 or - are at the pi/4  3pi/4   etc    where it would be -1   would be 2nd and 4th quadrants  

3pi/4     7pi/8     or 135 and 315 degrees

You would graph it as shown in the image below.

999979103354521

2x -21= 3-x re-arrange

2x + x = 21 + 3

3x = 24 divide both sides by 3

x = 24/3

x = 8

swhat steps did yhou take ChistherGold to get x = 8? ,y teacher want me to show my work. ugh

It doesn't.

The answer is C.  All debt scenarios, except for C, show an average payment greater than $94

He promised to repay the loan by giving his parents at least $94 from his paycheck each week.

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In fact, many things have been used as a type of instrument. So, in some ways, it can be considered an instrument. I myself play many instruments (my favorite being the viola), but if used right, mayo could make sounds that could make it qualify as one.

You will learn best when you try it yourself.

I have in fact not wasted any time of my life. I am in fact using my time wisely that I may have left to help others.

The inverse is the opposite of an operation. For example, the inverse of multiplication is division.

2^x * 5^y, = 100 2^y 5^x = 1000 x+y=?

Using Newton-Raphson method:

x= (2 log(2) - 3 log(5))/(log(2) - log(5)) ≈ 3.75647

y= (3 log(2) - 2 log(5))/(log(2) - log(5)) ≈1.24353

x + y = 3.75647 + 1.24353 =5

If you put this equation (2x - 21 = 3-x) into the calculator you will have an answer of x = 8.

This means that you must multiply 2.334565493759846 by pi which is a number that goes up to a million digits also known as 3.14. Once you do that, divide the answer by 45 and you will get your answer. 2.334565493759846​ * pi / 45 = 7.334253804520160483e0.

Thank you all very much for your help guys! But I must solve it using the half- angle formulas. Sorry I forgot to mention that, I was in a rush. Also with correct brackets it is sin (pi/5)

Also the problem says that given \(\sin ( \frac{\pi } {10}) = \frac{( -1 + \sqrt{ 5}) }{4}\), find \(\sin ( \frac{\pi } {5})\)

Formula:

\(\begin{array}{|rcll|} \hline \sin(2\varphi) &=& 2\cdot \sin{\varphi} \cdot \cos{\varphi} \\ \cos{\varphi} &=& \sqrt{1-\sin^2{\varphi}} \\\\ \sin(2\varphi) &=& 2\cdot \sin{\varphi} \cdot \sqrt{1-\sin^2{\varphi}} \\ \hline \end{array}\)

We set:

\(\begin{array}{|rcll|} \hline \sin{2\varphi} &=& \sin( \frac{\pi } {5})\\\\ \sin{\varphi} &=& \sin( \frac{\pi } {10})\\ &=& \frac{ \sqrt{ 5}-1 }{4} \\ \hline \end{array} \)

We have:

\(\begin{array}{|rcll|} \hline \sin(2\varphi) &=& 2\cdot \sin{\varphi} \cdot \sqrt{1-\sin^2{\varphi}} \\ \sin( \frac{\pi } {5}) &=& 2\cdot \frac{ \sqrt{ 5}-1 }{4} \cdot \sqrt{1- \left(\frac{ \sqrt{ 5}-1 }{4}\right)^2 } \\ \sin( \frac{\pi } {5}) &=& \frac{ \sqrt{ 5}-1 }{2} \cdot \sqrt{1- \left(\frac{ \sqrt{ 5}-1 }{4}\right)^2 } \\ \sin( \frac{\pi } {5}) &=& \frac{ \sqrt{ 5}-1 }{2} \cdot \sqrt{\frac{16- (\sqrt{5}-1)^2 }{16} }\\ \sin( \frac{\pi } {5}) &=& \frac{ \sqrt{ 5}-1 }{2} \cdot \sqrt{\frac{16- (5-2\sqrt{5}+1) }{16} }\\ \sin( \frac{\pi } {5}) &=& \frac{ \sqrt{ 5}-1 }{2} \cdot \sqrt{\frac{16- 5+2\sqrt{5}-1) }{16} }\\ \sin( \frac{\pi } {5}) &=& \frac{ \sqrt{ 5}-1 }{2} \cdot \sqrt{\frac{10+2\sqrt{5} }{16} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ (\sqrt{5}-1)^2 }{4} \cdot \frac{(10+2\sqrt{5}) }{16} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ (\sqrt{5}-1)^2\cdot (10+2\sqrt{5}) } {64} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ (5-2\sqrt{5}+1)\cdot (10+2\sqrt{5}) } {64} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ 60+12\sqrt{5}-20\sqrt{5}-4\cdot 5 } {64} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ 40-8\sqrt{5} } {64} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{ \frac{ 8\cdot 5-8\sqrt{5} } {8\cdot 8} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{\frac{8\cdot 5}{8\cdot 8} -\frac{8\sqrt{5}}{8\cdot 8} }\\ \sin( \frac{\pi } {5}) &=& \sqrt{\frac{5}{8} -\frac{\sqrt{5}}{8} }\\ \hline \end{array} \)

so what are the steps to get the answer for 2a+3b=3.00 and 4a+8b=7.00

step by step.

2^x * 5^y = 100

2^y * 5^x = 1000

x+y = ?

\(\begin{array}{rcll} 2^x \cdot 5^y &=& 100 \\ 2^x \cdot 5^y &=& 10^2 \\\\ \hline \\ 2^y \cdot 5^x &=& 1000 \\ 2^y \cdot 5^x &=& 10^3 \\\\ \hline \\ (2^x \cdot 5^y)\cdot (2^y \cdot 5^x) &=& 10^2 \cdot 10^3 \\ 2^x \cdot 2^y \cdot 5^y \cdot 5^x &=& 10^{2+3} \\ 2^x \cdot 2^y \cdot 5^y \cdot 5^x &=& 10^{5} \\ 2^{x+y} \cdot 5^{y+x} &=& 10^{5} \\ (2\cdot 5)^{x+y} &=& 10^{5} \\ 10^{x+y} &=& 10^{5} \\\\ \mathbf{x+y} & \mathbf{=} & \mathbf{ 5 } \\ \end{array} \)

Also the problem says that given sin (pi/10) =( -1 + sqrt 5)/4, find sin(pi/5)