215

To ADD or SUBTRACT fractions, you will need to have a COMMON DENOMINATOR

22   is common to 11 and 2

-1/2  x 11/11 = -11/22

3 (9/11) = 42/11    42/11 x 2/2 =  84 / 22

Now you can add them

-11/22 + 84/22 = (-11+84)/22 = 73/22 = 3 7/22

COMBINING two of the above answers      2 digits comprise   10 nemerals and 26 letters for each space  (36 possibilites for each space)   if you disallow special characters (!@#$%^&*   etc)

36 x 36 = 1296  possibilities     probability of guessing the correct last two digits  then becomes   1/1296

Question is unclear in that it does not say WHAT is allowed in the last two digits...numbers only?  Letters only?  Numbers AND letters only?   Special characters???    etc....

YMMV !    LOL

If there are 6 of them and they each pay 15%   that is  6 x 15= 90%    They are 10% short of the $ 720 needed  (or $72)

=14423.22  (just use the calculator)

Jess ate   35   of them  (the question SAYS that)

Fraction left   (120-35)/120 =  85/120  =85/120 = 17/24

8x(6x+6) = 48x^2 + 48x

If you meant :  (8)(6x+6) =48x + 48

1/4  x  1/2  =  (1x1)/(4x2) = 1/8

We'll have to know  the concentration of the compound.     (mg/ml)

MEAN is the average of a list of numbers.

MEDIAN is the number in the middle of the list

First arrange in increasing order

14  27  30  32  32         The median is   30

30% of 60 =  30/100 x 60 = 18

x = adult tickets                Revenue from adult tickets = $12 * x  = 12x

1/3x = children's tickets    Revenue from child's tix                       = 10/3 

x +   1/3  x  = 1500

4/3 x = 1500

x = 1500 *  3/4 = 1125      = adults      12 (1125) = money from adult tix = $13,500   

\(\big(\frac{2}{3}*\frac{2}{3}\big) + 6.25\)

\(\frac{4}{9}+6.25\)

\(\frac{4}{9}+6\frac{1}{4}\)

\(\frac{16}{36}+6\frac{9}{36}\)

\(6\frac{25}{36}\)

\(-3+(-2) \)

\(=\boxed{-5}\)

Assuming that it is in fraction form, 1/676 . Also, I am assuming that it is the English alphabet, with 26 letters.

Work- 

\(\frac{1}{(26\times2)}=\frac{1}{676}\)

2*10^(2-x) =5      divide both sides by 2

10^(2 - x)  =  5/2      take the base 10 log of eac side

log 10^(2 - x)  = log (5/2)     and we can write

(2 - x)  log 10   = log (5/2)      since log 10 = 1, we can ignore this, so

2 - x  = log (5/2)      add x to both sides and subtract log(5/2) from both sides

2 - log (5/2)   = x   ≈ 1.602

There are 100 possibilities for the last two digits  [ if we include 00].....therefore....you have  1/100 chance  [1 % ]  chance of choosing the correct one.....

Is there can answer? 

Is there can answer? 

65%