f(x) = x^2 -3x
g(x) = x-3
f(x) > g(x)
So we have that f(x) > g(x) means that
x^2 - 3x > x - 3 subtract x from both sides.....add 3 to both sides
x^2 - 3x - x + 3 > 0 factor
x (x -3) - 1(x - 3) > 0 ....... (x - 3) is the common factor
(x -1) (x -3) > 0 .......Set to 0
(x -1) ( x - 3) = 0
Setting each factor to 0 gives us the solutions of x = 1 and x = 3
This tells us that the solutions will come from these possible intervals :
(-inf, 1) , (1, 3) or (3, inf) ........ test a point in the inequality (x -1) (x -3) > 0 in each interval
If x = 2, the inequality will be untrue
If x = 4 it will be true and it will be true if x = 0
So.....the correct solutions are : (-inf, 1) U (3, inf) or x < 1 U x > 3