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Personally, whenever I see something like this, I abstain and move on to the next question.

I can't be bothered to fathom out what the writer intends.

ok asinus :)

I'll concede

It is a very good example of why it is so important to use brackets properly - even if the poster thinks they may not really be needed.

Melody,the equation is not unique.
To be clear is not trivial.
A guest mentions this essay. Readable!

Hi Max,

I looked at your question but I am not good at these.  I have not seen Heureka in a while but hopefully he will drop in and give us an answer.  I love to learn how to do these from him.

OR Maybe guest 5 will come back and clarify what he was talking about because it didn't make any sense to me.  :(

528/4 = 500/4 + 28/4 = 125 + 7 = 132

Thanks Melody :)

i dont know

My goodness I have never seen so many any answers for a trivial questions.

I'll add my 2 cents worth  :))

48/2(9+3)

=48/2*12

=24*12

=288

That is why you need to use brackets EVEN if you think the meaning is clear!

You mean synthetic I think  :)

There are a heap of you tube videos on this.

Here is one of them 

Here is another Australian Christmas song to entertain you :)) 

SONG

Yea , that'd be a bummer HSC ://

Merry Christmas! l love this month, they jolly spirits, the lights, the cold, and spending the holidays with those you love. What l don't love is having my birthday being on the 24th... l get cheated out of so many presents...

Actually, scroll down to admins answer #4

because you can post pictures without uploading ti elsewhere first

Here is an explanation of the calculus involved...

\(y=f(x)\\ \frac{dy}{dx}=f'(x)\\ \int_{x_1}^{x_2} \frac{dy}{dx}dx\\=\left[y\right]_{x_1}^{x_2}\\=\left[f(x)\right]_{x_1}^{x_2}\\ =f(x_2)-f(x_1) \)

So if you graph the differential curve against x and then find the area under that curve between x1 and x2 (you do this by finiding the definite integral of it between x1 and x2)    you will always get   f(x2)-f(x1)

I understand this bit perfectly I just don't comprehend why it works this way.  Maybe a pictorial explanation might help. ://  idk.

312/24  x  $6   =

13   bags    x     $6   =

$78

I thank all who have thought about it!
Merry Christmas wishes asinus    !

Hi guest 5

I do not see that you have answered the question.

The question asks you to differentiate   xsin(1/x)    not just   sin(1/x)

The answer that Wolfram alpha gives is

Looking better at what you hae written you have said that it is just a starting point, which is fair enough but 

I would like you to explain this statement of yours:

"  Now use your formula sinA - sinB -2cos(A+B)/2 .sin(A-B)/2   "

Where does this come from - there is not even an equal sign so how can it be a formula?

WolframAlpha will generally solve most equations  :

http://www.wolframalpha.com/input/?i=4x+%2B+3++%3D+0

This is an old problem.....here is a good explanantion...but no clear answer as to which is "more correct"

https://math.berkeley.edu/~gbergman/misc/numbers/ord_ops.html

I think we should aim for UNambiguity in ALL of our calcs....wouldn't want to be launching in to space with ambiguous calculations used by the engineers !!!

We can write the above equation of 16÷4(4)=16÷4×4.

According to BODMAS rule, Division should be first done before the multiplication.

So, 16÷4×4=4×4 {Bodmas rule}

=16

Finally, 16 is the correct answer.

x=42000^-1  =  0.0000238095238095

No one said anything about them being simultaneously in the numerator and denominar.....(9+2) is only in the numerator....

I guess we will just agree to disagree....but go to this website and enter the equation as written:

https://www.cymath.com/answer.php?q=48%2F2(9%2B3)

or this one

https://www.wolframalpha.com/

or this one

http://www.quickmath.com/webMathematica3/quickmath/equations/solve/basic.jsp

or this one

http://www.homeschoolmath.net/worksheets/equation_calculator.php

That would be 10^23      H2  MOLECULES  (if they were in free molecular form...which they aren't)

Let x  and y  be the numbers....and we have....

x * y   −  2

See  here  :     http://web2.0calc.com/questions/instructions-on-uploading-pictures