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EP and i have interpreted this question differently.

I think that he has interpreted that the second leg goes half the speed of the first leg and he has found his answer.

This may well be the intended interpretation

BUT

I interpret it that the second leg takes twice as long and how far it is is irrelevant.

If the first leg cost $1.20

and the second leg takes twice as long then I think the cost will be 60c

need help with an equation?
(1.618034)6 - (-0.618034)6 x6 = ___________________________ =8  

\( 1.618034^{6} - (-0.618034)^6 x^6=8 \) 

\(1.618034^{6}-8= (-0.618034)^6 x^6\)

\(x^6=\frac{1.618034^6-8}{(-0.618034)^6}=9.88854456251\)

\(x=\pm \sqrt[6]{9.88854456251} \)

\(x_1=1,46505994841\)

\(x_2=-1,46505994841\)

  !

\(\)

Finally, I managed to double the number of accurate digit to: 32,064!!!.

SUBTRACTING a NEGATIVE makes it a POSITIVE :

-7 - (-9) = -7 + 9 = 9-7= 2

20 cents.

rate x time = distance

First distance = 3/4                    Second Distance = 1/4         (the two legs of your commute)

r (t) = 3/4                                     r(2t) = 1/4                          (the second leg takes twice as long)

r (1) = 3/4                                     r(2) = 1/4

r = 3/4  = 6/8                                r = 1/8

So you can see the first-leg train is SIX times faster than the second-leg train

so the fair for the second one should be 1/6th the first one 

1/6 x 1.20 = 20 cents

34*15/4=

[34 * 15] / 4  =

510 / 4  =

255 / 2 =

127.5

divide 1000 by 100 000 000 000 000and add 3

\(\frac{1000}{10^{14}}+3=3.000 \ 000 \ 000 \ 01\)

Yes, I started 10 minutes ago.

!

The word "factorial" is generally used on "whole integers", such as 2!, 14!, 25!.....etc.

If you have a number with a fraction such as 2.5!, 4.45!, 15.21!...., that is called the "Gamma function".

This Greek letter Γ, is called "capital gamma" and is used to calculate the Gamma function. So, for your question:Γ(.50) =0.886226^2 x 4 =π. You were curious about it, weren't you!!.

((4800*(1-0.1)+14677.64)/(1+x)+((4602.45*(1-0.1)+14677.64)/(1+x)^2+((4400.94*(1-0.1)+14677.64)/(1+x)^3+((4195.41*(1-0.1)+14677.64)/(1+x)^4+((3985.77*(1-0.1)+14677.64)/(1+x)^5+((3771.93*(1-0.1)+14677.64)/(1+x)^6+((3553.82*(1-0.1)+14677.64)/(1+x)^7+((3331.34*(1-0.1)+14677.64)/(1+x)^8+((3404.42*(1-0.1)+14677.64)/(1+x)^9+((2872.95*(1-0.1)+14677.64)/(1+x)^10+((2636.86*(1-0.1)+14677.64)/(1+x)^11+((2396.04*(1-0.1)+14677.64)/(1+x)^12+((2150.41*(1-0.1)+14677.64)/(1+x)^13+((1899.87*(1-0.1)+14677.64)/(1+x)^14+((1644.31*(1-0.1)+14677.64)/(1+x)^15+((1383.65*(1-0.1)+14677.64)/(1+x)^16+((1117.77*(1-0.1)+14677.64)/(1+x)^17+((846.57*(1-0.1)+14677.64)/(1+x)^18+((569.95*(1-0.1)+14677.64)/(1+x)^19+((287.80*(1-0.1)+14677.64)/(1+x)^20=-240000

X=?

I trust you realize that 3/3 = 1

so 4/3 x 3/3 = 4/3    ( or   12/9  which simplfies to 4/3)

A little ambiguous (see thread from a couple of days ago re : 48/2(9+3)

(2/3)^2   x   3/4 =  4/9  x 3/4 = 1/3

2/(3^2)   x    3/4 =  2/9 x 3/4 = 1/6

(2/3)^(2*3/4) 2/3 ^(6/4) = .54433

etc.....

Not POSITIVE, but I think the answer is given in radians/sec

281. 718 R/sec   =   44.83 Hz

tan^2(x) = tan x what are the possible values of x in 0=<x<360

\(tan^2x-tanx=0\\ tanx(tanx-1)=0\\ tanx=0\qquad or \qquad tanx-1=0\\ x=0,\; 180,\;360,\;\;or\;\; tanx=1\\ x=0, \;180,\;360,\;\;or\;\; x=45, \;225\\ x=0^\circ \;\;45^\circ,\;\;\;180^\circ, \;\;225^\circ \qquad 0 \le x<360 \)

what would be the resonat frequncy for a series RLC circuit with the following components: a 1kV resistor, a 900 mH inductor, and a 0.014 mF capacitor

The answer is 25.

For the previous question, find the mean and the variance of g(x) = ex-1?

Well if you have the original graph, the inverse is its reflection across the line y=x

cos-1(0.73218673816)

There are two interpretations

1.\((a^{-1}=\frac{1}{a})\)

\(cos^{-1}(0.73218673816rad)=\frac{1}{cos(0.73218673816rad)}=1.34460226097\)

\(cos^{-1}(0.73218673816deg)=\frac{1}{cos(0.73218673816deg)}=1.00008165786\)

2. \( (Keys \ of \ the \ pocket \ calculator)\)

\(cos^{-1}(0.73218673816)=acos(0.73218673816)\)

\(=42.93deg =0.749269312889rad\)

Merry Christmas and a happy new year, asinus :- )   !

The notation makes no sense. 

HEHEHEHE......!!!!!

I like it!  I just sent it to a friend in Algeria :)

<!DOCTYPE html>

<html>

<head>

<title>

Hard Mathz

</title>

</head>

<body>

<p id="hardMath">

</p>

<script>

var x = 2;

var y = 2;

var z = x + y;

document.getElementById("hardMath").innerHTML = z

</script>

</body>

</html>

I was able to get: 16,034 accurate digits!!. That is the end of my attempts! My large-number calculator simply stalls on number greater than that.

Alright! I was able to compute it to 3,985 accurate digits!!.

Just a FYI:

Before we go too far down this thread, a little clarification.....this is generally referrd to as Euler's NUMBER   ..... Euler's CONSTANT is something else. 

Happy Hanukkah !   ....  or  Merry Christmas Eve.....   Or Kwanzaa (26th)....

.....or just "Have a nice day"