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LOLOLOLOL :P

What observations? Did you mean the reaction between metals and acids?

If yes,

You will see less gas bubbles produced from the reaction.

And the metal will dissolve slower.

Wow. Much longer than I thought. Thanks 

It is an equation :/

John rolls a pair of standard 6-sided dice. What is the probability that the two numbers he rolls are relatively prime? Express your answer as a common fraction.

Great work Ninja :)

sorry EP our guest is right :(

Thanks for the explanation guest. :)

\(P(relatively \;prime)=\frac{23}{36}\)

There are seven wombats in a council. Three of them are hairy-nosed wombats, while the rest are all different species. If the hairy-nosed wombats are indistinguishable but the other wombats are, how many ways can the wombats seat themselves in a row?

The real meaning of this question is difficult to determine....

I think that both answers have merit.

there are 840 different ways that the wombats can sit, just like NinjaAnswer said,

but if you only care about the position of the 3 hairy nose wombats then I think out guest is correct.  :)

Yes that is a good alternative to mine and Alan's approach.  

I think Alan did it my way, or  I should say I think i did it his way  ://     

I had forgotten aoubt LancelotLink's campaign for office.  

Thanks Ginger, the memory has bought a big smile to my face :)

I wonder if LL is still off, licking his wounds, from his great defeat??

Well it would be excellent if Morgan Tud would appear and recomend a fix. That be the truth.

Euthanasia, yes tis possible, the good Doctor often be one to over prescribe, a good sleeping draft be all that is needed. ://

This realm would hardly be recognisable to Churgeon Tud on this 1st day of January in the Lords year two thousand and seventeen.  Tis sad but although one can deny the existance of evolution one cannot stop its advance.  

I think that the bridge for which the troll extracted his toll has long since been swept away by the raging floods.  Perhaps the troll was also swept to his death.  Tis so sad. 

Everyone has a price.

Ah ha I found the site I was looking for!!

You have to have a solid knowledge in Mathematics, and more specifically, in a number of branches of Mathematics such as Algebra, Calculus, Trigonometry, Geometry, Number Theory,Statistics, Probability theory.....etc, and the ability to explain your solutions as thoroughly as possible. Also, the ability to reason using good logic, such as when solving "word problems". As well, a good and solid understanding of the Sciences, such as Physics, Chemisty....etc., would be very helpful. At least, that is my understanding! Somebody could correct me on this!!.

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All of that helps......but not as much as promising  to slip  Melody a few bucks under the table......

Thanks Ginger,

Graphics are fun. :)

I was looking for an interactive graphic that I have seen and probably used before in mathsisfun.  I found some related  interactive graphics,  but not the one I was looking for.  It is a little frustrating when this happens.

I probably should look in my old information threads, I may have stored the address there, ...

mine I guess LOL   :)

Hi EP

Thank for that info, I will try and remember :)

To my knowledge much of Colorado would have high altitude so I expect it can get very cold in winter - probably not as cold as alaska though.

That polar bear plunge sounds more suited to polar bears... but hey... you get a free T-Shirt so i guess it is worth it LOL  :)

Hi NinjaAnswer,

Form me the time is 11 hours in FRONT of Greenwich Mean Time (GMT, London, United Kingdom)

But you are probably in the United States which is between 5 hours in the east and 8 hours in California and 11  hours in Western Alaska, BEHIND Greenwich mean time.

So say you live in California you are 8+11=19 hours behind me in time.

In winter ( the middle of the year in the Southern Hemsiphere) my time zone is 10+    AEST

AEST stands for Australian Eastern Standard time.

But it is summer now and we have daylight savings time, SI my time zone is  11+     AEDT

AEDT stands for Australian Eastern Daylight-savings Time.

Here is a sight that I really like and I think that you will too :)

I think that you should bookmark it :)

EP: The question is NOT about primes! The two numbers, it says, are "relatively prime"!.

Relatively Prime: Describes two numbers for which the only common factor is 1. In other words, relatively prime numbers have a greatest common factor (gcf) of 1. For example, 6 and 35 are relatively prime (gcf = 1).

Well there are 36 possible rolls

there are three  possible primes on each die    2, 3 and  5

you can roll a

2 & 2

2 & 3

2 & 5

3 & 2

3 & 3

3 & 5

5 & 2

5 & 3

5 & 5

Those are the only 9 rolls that have TWO primes      9 out of 36 rolls     9/36   or   1 /4   

The answer is \(\frac{\sqrt[2]{3}}{3}\)

Help?!?!?!?!?????/

We have to use a little bit of casework to solve this problem. If the first die shows a 1, the second die can be anything (6 cases). If the first die shows 2 or 4, the second die is limited to 1, 3, or 5 (2 * 3 = 6 cases). If the first die shows 3, the second die can be 1, 2, 4, or 5 (4 cases). If the first die shows 5, the second die can be anything but 5 (5 cases). If the first die shows 6, the second die can be only 1 or 5 (2 cases). There are 36 ways to roll two dice, 23 of which are valid, so the answer is 23/36.

I believe there are several solution for this type of puzzle due to the number of combinations possible.

Here is one solution that requires 4 men and the Explorer.

Let the natives be represented by letters A, B, C, and D and the Explorer by E. The crossing might occur like this:
Day 1: A, B, C and E set out on the first 40 km.

Day 2: A gives both B and E one day's rations and returns to base. B, C and E set out on the next 40 km.

Day 3: C gives E a day's rations and returns to the first camp [set up at the end of Day 1]. B and E set out on the next 40 km. In addition, A, who has returned to base, sets off with three days rations to the first base 40 km away. D also sets off for first base, but with 4 days rations.

Day 4: A has met up with C and gives him a day's rations. Both men return to base. B gives E a day's rations and sets off back to the second camp [80 km from base]. E now has sufficient supplies to complete the crossing  unassisted. D sets off from the first camp bound for the second.

Day 5: E continues on his way. D, who has met up with B, shares his rations with B and both make their way to the first camp. A, with four days rations, also makes his way to the first camp.

Day 6: E has only two days to go. A has met up with B and D and the three return to base camp, sharing the rations A has left.

Day 7: E completes his crossing.

Case 1: 1 T 

3 options for where the T is, 4 options for A, R, G or E and 3 for the last slot.

3 * 4 * 3 = 36

Case 2: 2 T's

3 options for non T's and four options for the last slot. 

3 * 4 =  12

Total:

36 + 12 = 48<------------Answer

Cool!!