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Thanx Alan....that is what I was (eventually) thinking....but was unsure of the question.     Cool...

=.0727 N-m

QUESTION:
I'm learning here (sometiems) ......

wouldn't COGS (Cost of Goods Sold)   be 5% 0f $2000?     

Then profit would be     3000 - 2000 - 2000(.05) = 1000 - 100 = $900

Just wondering....that is the way I THINK it should be

YAH?

Multiply degrees by  pi/180 to get radians.

360 degrees = 2 pi radians

what is the standard form of 1070400

\(The \ standard \ form \ of \ 1070400 \ is \ 1.0704 \times 10^6\)

  !

98 years old

5% of $3000 is $150.

Profit = $3000 - $2000 - $150 = $850

<OXW  = < XWO  = 90                             <ZYP  = < OYX  = 90

<PWZ = <XWO  =90                                <ZYP  = <YZP  =90

So < OXW = < PWZ                                 So < OYX  = < YZP

And <XOW  = < ZPW  = 90                      And <XOY = <ZPY

So  ΔXOW  ~ Δ WPZ                                So  ΔXOY  ~  ΔPYZ

XO / OW  = WP / PZ                                XO /OY = PY /PZ

XO * PZ  = WP * OW                                 XO* PZ  = OY* PY

So

WP * OW   = OY* PY

OW / PY  = OY/ WP

OW / PY = [ OP + PY] / [OP + OW]

OP*OW + OW^2  = OP*PY + PY^2

OP[OW − PY] +  OW^2  −  PY^2  = 0

OP[OW − PY]  +  [OW − PY] [[OW + PY]  = 0

[OW − PY] [ OP + (OW + PY) ]  = 0          

And.......since OP , PY and OW  are  all > 0  .....the second factor can never  = 0

So  [OW − PY]  must = 0   →    OW  = PY

it would be 4/10 or 2/5

my answer is x = -1/6

(1-4m)/8m-(3-1m^2)/2m^2

\(\Large\frac{1-4m}{8m}-\frac{3-m^2}{2m^2}\)

\(\Large=\frac{m(1-4m)-4(3-m^2)}{8m^2}\)

\(\Large=\frac{m-4m^2-12+4m^2}{8m^2}\)

\(\Large =\frac{m-12}{8m^2}\)

  !

angular acceleration = linear acceleration/radius, so here:  \(\alpha = 0.3/0.23s^{-2}\)

\(T=\frac{2}{3}\times 0.625\times 0.23^2\times \frac{0.3}{0.23} Nm\)

Using ...... sin (A - B)  = sinAcosB - sinBcosA ......and we have.....

(cos(pi/6))(sin(pi/5))-(sin(pi/6))(cos(pi/5)) =

sin( pi/5 - pi/6)  =

sin (pi / 30)

I assume that you want the total distance between the time it is dropped and just before it bounces the ninth time

The sum is given by

30  +  30 [1 − .5^8] / [1 − .5 ]  =  89.76m → 89.8 m

Just as EP found....!!!!

Using the triangle inequality, we have that

x+ 2x+ 1 > x + 4

2x > 3

x > 3/2

And

2x + 1 + x + 4 > x

2x > − 5

x > −5/2

And

x + x + 4  > 2x + 1

2x + 4 > 2x + 1   

True for all x

x > 3/2   is the most  restrictive interval

So....as long as x >3/2   a triangle is possible

(C)  is correct

Look at the graphs

f(x) is in red    g(x)  is in blue

(B) best describes the two functions

4(-x - 3) = 3x + 5(x - 2)

\(4(-x-3)=3x+5(x-2)\)

\(-4x-12=3x+5x-10\)      

                                  With sign change to the right side

\(-4x-3x-5x=-10+12\)              Calculation

\(-12x=2\)                                                  Calculation                                   

\(x=-\frac{1}{6}\)

   !

(3/4) / (1/4)  = 3/4  x  4/1 = 12/4 = 3

I am not sure what you HAVE, but add the distances togther and divide this SUM by the NUMBER of distances that you added together.

Check your numbers carefully. You have two multiplications + $2.65!!!!.

Just study carefully what I did. Even if you make mistakes, that is how you learn. If you have problems, ask your teacher.