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Here : https://www.desmos.com/calculator/owddboe2e6

y  =  a      .....will always be horizonttal line at "a"

googolplex

No, they are not. One(x^2) is second order. The other(x^3) is third order.

Ashley bought 4n articles for c cents each. When she sold 3n of the articles she noticed that she had recovered her initial investment. Express in terms of c the amount she charged for each article.

Let the price of each article sold =x. So, we have:

4nc =3nx, solve for c. Divide both sides by 4n

c =3nx / 4n

c =3/4x - amount she charged for each article purchased. Or,

x = 4/3c - amount she charged for each article sold.

The x3 and x2 are like terms, but the 2 is not.

Solve for x:
(x + 1)/2 + (2 x - 3)/9 = 11

Put each term in (x + 1)/2 + (2 x - 3)/9 over the common denominator 18: (x + 1)/2 + (2 x - 3)/9 = (9 (x + 1))/18 + (2 (2 x - 3))/18:
(9 (x + 1))/18 + (2 (2 x - 3))/18 = 11

(9 (x + 1))/18 + (2 (2 x - 3))/18 = (9 (x + 1) + 2 (2 x - 3))/18:
(9 (x + 1) + 2 (2 x - 3))/18 = 11

9 (x + 1) = 9 x + 9:
(9 x + 9 + 2 (2 x - 3))/18 = 11

2 (2 x - 3) = 4 x - 6:
(4 x - 6 + 9 x + 9)/18 = 11

Grouping like terms, 9 x + 4 x - 6 + 9 = (9 x + 4 x) + (9 - 6):
((9 x + 4 x) + (9 - 6))/18 = 11

9 x + 4 x = 13 x:
(13 x + (9 - 6))/18 = 11

9 - 6 = 3:
(13 x + 3)/18 = 11

Multiply both sides of (13 x + 3)/18 = 11 by 18:
(18 (13 x + 3))/18 = 18×11

(18 (13 x + 3))/18 = 18/18×(13 x + 3) = 13 x + 3:
13 x + 3 = 18×11

18×11 = 198:
13 x + 3 = 198

Subtract 3 from both sides:
13 x + (3 - 3) = 198 - 3

3 - 3 = 0:
13 x = 198 - 3

198 - 3 = 195:
13 x = 195

Divide both sides of 13 x = 195 by 13:
(13 x)/13 = 195/13

13/13 = 1:
x = 195/13

The gcd of 195 and 13 is 13, so 195/13 = (13×15)/(13×1) = 13/13×15 = 15:
Answer: |x = 15

Ashley bought 4n articles for c cents each. When she sold 3n of the articles she noticed that she had recovered her initial investment. Express in terms of c the amount she charged for each article.

\(4c=3x\)

\(\large x=\frac{4c}{3}\)

\(Ashley \ sold \ the \ 3 \ items \ at \ the \ price \ of \large \ x=\frac{4c}{3}\)

  !

please this is urgent for a job

22 as a percentage of 1378

\(22:x=1378:100\%\)

\(\large x=\frac{22\times 100\%}{1378}\)

\(x=1.59652\ \%\)

  !

3.1415926535

how many times does 6.3 million go into 9 billion?

\(EU\ 1\ Billion = 10^{12}\)

\(US\ 1\ Billion=10^{9} \)

\(\large EU\frac{9\times10^{12}}{6.3\times 10^6}=2.72\overline{72}\times 10^6\)

\(\large US\frac{9\times10^{9}}{6.3\times 10^6}=1.\overline{428571}\times 10^3\)

  !

7log(3x)+3log(5x) =15

(3x)^7 * (5x)^3 = 10^15

2187 x^7  * 125 x^3 = 10^15

273375 x^(7+3) = 10^15

x^(10) = 10^15 / 273375     Take 10th root of both sides

x = 9.04324

At a simple interest rate of 5.5%

4 = (1.055)^n

n=25.89 years

25.89 years.

Solution

(Capital sum)    X   (1.055)^x          =  4 X (Capital sum)

(1.055)^x                                          =  4

take logs of both sides

x ln(1.055)                                          =ln4

x                                                         = ln(4)   /   ln (1.055)      

                                                            = 25.89

You can put 6 into 49 8 times to get 48. That leaves you with one left over. (All a matter of counting on your fingers.)

9000000000/6300000 = 1428.5714285714285714

9/6.3 = 1.4285714285714286

((sqrt(37)cos(t))/37)^2  ....we can express this as.....

(√37)²  * cos² (t) /  37²  =

( 37) / (37²) * cos² (t)  =

(1/37) cos² (t) =

cos² (t) / 37

a system of linear equations is a group of linear equations that will either intersect (one solution), be parallel (no solution) or be the exact same (infinitely many solutions).

18*200 = 24*V₂

3600 = 24V₂      divide both sides by 24

150  = V₂

ok,

29 digits before dot (.)

so,

1.6x10^29

or

0.16 x10^30

0.16 Nonillion 

or it can also be written as 100 Octillion where Octillion means 10^27

4 + 4/5  =   24/5    ...so.....

(24/5) (24/5)  =  576 / 25

What are the first four multiples of 9

-39 < 6v + 9  ≤ 39         subtract 9 from everything

-48 < 6v  ≤ 30         divide by 6

- 8 < v ≤ 5

We are solving this :  [ the shot will be at 0 m above the ground at the finish ]

-0.004s^2 +0.64s+1.94  = 0   multiply   by  -250

s^2 - 160s -  485  = 0       add 485 to each side

s^2 - 160s   = 485 

Take 1/2 of 160  [80] .........   square it  [6400] and add to each side

s^2 - 160s  + 6400   = 485 + 6400        factor the left side and simplify the right

(s - 80)^2  = 6885        take the + √ root

s - 80  =   √6885       add 80 to boh sides

s =  √6885  + 80 ≈    162.98 m    [ that's one heck of a throw....LOL  !!!  ]

You need to know the form of the function x(t).

For example, you could have: x(t) = t/4 or x(t) = (t^2)/48 + 2/3 or ...

These will give different results for the integral in general.