Hi Eight MersenePrime,
I was thinking about your username... I looked up meridians to see where you might come from.
I am thinking that maybe you are from Strasbourg in France.... :)
I had not realized before that Bamako is further west than london - quite a lot further west !!
I love looking at maps :))
Now to answer your question :)
cos(19\pi/12)
\(cos(\frac{19\pi}{12})\\ \text{4th quadrant}\\ =+cos(\frac{(24-19)\pi}{12})\\ =+cos(\frac{5\pi}{12})\\ =+cos(\frac{3\pi}{12}+\frac{2\pi}{12})\\ =cos(\frac{\pi}{4}+\frac{\pi}{6})\\ =cos(\frac{\pi}{4})cos(\frac{\pi}{6})-sin(\frac{\pi}{4})sin(\frac{\pi}{6})\\ =cos(45^\circ)cos(30^\circ)-sin(45^\circ)sin(30^\circ)\\ =\frac{1}{\sqrt2}\times \frac{\sqrt3}{2}-\frac{1}{\sqrt2}\times \frac{1}{2}\\ =\frac{\sqrt3-1}{2\sqrt2}\\ =\frac{\sqrt3-1}{2\sqrt2}\times \frac{\sqrt2}{\sqrt2}\\ =\frac{\sqrt6-\sqrt2}{2*2}\\ =\frac{\sqrt6-\sqrt2}{4}\\ \)
.