All Answers 358947 Answers

Melody, I believe he/she is saying that the arc intercepted by angle ABC (minor arc AC) is 110 degrees.

Correction:  There are 6, not 8, multiplications for the raw polynomial.

a₃*x*x*x = 3 multiplications (4 terms) and a₂*x*x = 2 multiplications (3 terms) 

9/6/14

Another problem for Admin to iron out

These are different questions and the second one is incorrect.

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(log(sqrt(10)+1))^2=

$${{log}_{10}\left({\sqrt{{\mathtt{10}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}^{\,{\mathtt{2}}} = {\mathtt{0.383\: \!570\: \!947\: \!098\: \!647\: \!1}}$$

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log(sqrt(10)+1)^2

$${{log}_{10}\left({\sqrt{{\mathtt{10}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}^{\,{\mathtt{2}}} = {\mathtt{0.383\: \!570\: \!947\: \!098\: \!647\: \!1}}$$

yup 77 months. but don't understand how to get to that.

(log(sqrt(10)+1))^2=

$${{log}_{10}\left({\sqrt{{\mathtt{10}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}^{\,{\mathtt{2}}} = {\mathtt{0.383\: \!570\: \!947\: \!098\: \!647\: \!1}}$$

So it did - another wrinkle for Andre to iron out!

Sorry Alan.

PS I have already sent Andre an email telling him of this probem.  I am assuming that he puts calculator errors near the top of his priority list!

I found this you tube clip but it looks pretty boring.  Sorry.

continued

I still don't know what you want but

A=180-68=112 degrees  (opp angles in cyclic quad are supplementary)

104+C=2*71 = 142  (the angle at the centre = 2* angle at the circumference when both are subtended from the same arc.

C=142-104=38 degrees

If I scribbled down the correct numbers here on my scrap of paper i got B = 120 degrees (accuracy very questionable at this moment)

I still do not know what you actually want!

Maybe you just want all the angles at the centre.  I am a bit slow sometimes - i'm not much good at forensic mathematics.

Ok the last angle is just 360 degrees minus the other 3 angles.

I did use brackets - Math (Input=Result) removed them!  Try it!

Is 104 degrees and C and B degrees the angles from the centre that subtend to those arcs?

What is O?

I do not understand what you are asking.

Here is some information on platonic solids

 the systematic treatment of magnitude, relationships between figures andforms, and relations between quantities expressed symbolically.

Maybe this is my shortfall but what angle is 110 degrees ?  I don't understand.

When I want to use a picture I almost always use the "snipping tool" that was automatically included with my Window 7 operating system.  It is easy to use and then the picture can just be uploaded.

Maybe this information will help you?

between means 

$${\mathtt{23}}{\mathtt{\,\small\textbf+\,}}{\mathtt{24}}{\mathtt{\,\small\textbf+\,}}{\mathtt{25}}{\mathtt{\,\small\textbf+\,}}{\mathtt{26}}{\mathtt{\,\small\textbf+\,}}{\mathtt{27}}{\mathtt{\,\small\textbf+\,}}{\mathtt{28}}{\mathtt{\,\small\textbf+\,}}{\mathtt{29}}{\mathtt{\,\small\textbf+\,}}{\mathtt{30}}{\mathtt{\,\small\textbf+\,}}{\mathtt{31}}{\mathtt{\,\small\textbf+\,}}{\mathtt{32}}{\mathtt{\,\small\textbf+\,}}{\mathtt{33}}{\mathtt{\,\small\textbf+\,}}{\mathtt{34}}{\mathtt{\,\small\textbf+\,}}{\mathtt{35}}{\mathtt{\,\small\textbf+\,}}{\mathtt{36}}{\mathtt{\,\small\textbf+\,}}{\mathtt{37}}{\mathtt{\,\small\textbf+\,}}{\mathtt{38}}{\mathtt{\,\small\textbf+\,}}{\mathtt{39}}{\mathtt{\,\small\textbf+\,}}{\mathtt{40}} = {\mathtt{567}}$$

Alan and CPhill have used good techniques that would be very useful if you needed to add up a much wider range of numbers.

Say you wanted the sum of all numbers between 100 and 1650.

that would be 101+102+.......+1649.

You wouldn't add them one at a time - it would take too long!

Thank you Alan,  i appreciate you pointing out this error.  

I am surprised that you didn't use brackets in your answer because without brackets the meaning is not clear.

I don't have any idea what you are asking and I think if anyone else did you would already have an answer.

Sorry.

Wow, that's like, the simplest answer I've ever seen.

How could I not see that 

thanks Alan

10x - 3y = 69   ...(1)

2x - 9y = 39    ...(2)

Multiply (1) throughout by 3

30x - 9y = 207   ...(3)  Rewrite (2) below it

2x - 9y = 39      ...(2)

Subtract (2) from (3)

28x - 0 = 207-39 or

28x = 168

Divide both sides by 28

x = 168/28 or

x = 6

Put this back into equation (2)  (or equation (1), whichever you prefer);

2*6 - 9y = 39 or

12 - 9y = 39

Subtract 12 from both sides

-9y = 27

multiply both sides by -1

9y = -27

Divide both sides by 9

y = -27/9

y = -3

so x = 6 and y = -3

$${\mathtt{41}}{\mathtt{\,-\,}}{\mathtt{22}}$$ Thats all you gotta do.Simple.

P.S I'm not counting decimals.