All Answers 358512 Answers

5 (4x - 2) = 20x - 10

20x - 10 = 14x + 8

[20 - 14]x [-10 + 10] = [14 - 14]x + [8 + 10]

6x = 18

x = 3

5000 * 0.20 = 1000

It's a THREE POINTER from the top of the arc by GL.... !!!

Thumbs Up   ......

We could do some fancy math here....but......since he gets only 1/5 of what he sells, then he has to sell 5 times as much $1000 = $5000 in order to make $1000

...Does that make sense ???

25% = 1/4

1/4(200) = 50

200-50 = 150

it will be $150 on sale

We can rewrite this as

(3^x)(3²)= 54 + (3^x)(3)         divide through by 3

(3^x)(3) = 18 + 3^x               subtract 3^x from both sides

(3^x)(3) - 3^x  = 18               factor the left side

(3^x)(3 - 1) = 18               simplify the left side

(3^x)(2) = 18                    divide both sides by 2

3^x = 9      ... so it appears that x = 2

First, only three-dimensional objects have "volume." A circle is a two-dimensional object that has an "area."

So, let's suppose you meant that it has an area of pi/6.

The "formula" for its area is   

A = pi*r^2       where r is the radius  ......     so we have

pi/6 = pi*r^2    divide both sides by pi

1/6 = r^2          take the positive square root of both sides

√(1/6) = r   ...   and "rationalizing" the denominator produces ... √(6)/6

Looks good to me, NinjaDevo.......

(4.1*10^2)(2.4*10^3)/(1.5*10^7) = N  (N is the value of this expression)

(4.1*10²)(2.4*10³)/(1.5*10⁷) = N

(4.1*2.4÷1.5)(10²*10³÷10⁷) = N

N = (6.56*10^-2)           ---Scientific notation :D

or

N = 0.0656               ---Decimal

To make sure this is right, go ahead and put the expression in this website's calculator!

First rewrite them as 

y<-(5+x)/2

y<x

Then plot y=-(5+x)/2 and y=x and shade in the region below both curves (which is the region that satisfies both inequalities):

The red shaded area is where both inequalities are satisfied simultaneously (of course this region should cover the

range -∞<x<∞ in principle, but it is infeasible to plot all of that!)

Yeah, I did notice that too Alan. I'm not really sure there's good way to get around that with a somewhat long username though.

And thanks, it really wasn't that hard to make with the right paint program. :)

Looks good when enlarged (as on your Profile page), but looks a little smudged in the small version on the Questions page!!  Skilfully done though!

Use the on-site calculator to get

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}} = -{\mathtt{5}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,-\,}}{\mathtt{9}}\right)}{{\mathtt{4}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.850\: \!781\: \!059\: \!358\: \!212\: \!2}}\\
{\mathtt{x}} = -{\mathtt{0.649\: \!218\: \!940\: \!641\: \!787\: \!8}}\\
\end{array} \right\}$$

Hi Reinout

Are you still interested in this question or have you got it sorted ?

Call the constable of the guard!

A band of pirates hath hijack the special, private label elixir intended for Rom, the Master of Physics and Numbers.Surely he be disappointed.

The pirates have not sought a ransom, Perhaps, they prefereth the contents to the ransom. No matter. I shall order the scribes to create another, superior label for such a master. He is truly worthy!

------------

Top of the day to you, Sir Cphill.

Your coat of arms doeth represent with a certainty and assurance the great world where we liveth hath room for satire and irony.

In my dominion, such icons be rare or be not recognized for what they meaneth . ---------

Morgan^-1 Tud

It always favors the correct answer....such a shame.

I know right, this calculator is a liar.

Hmm, when I did the problem I got -4/3  as an answer.

$${\mathtt{\,-\,}}{\frac{{\mathtt{14}}}{{\mathtt{6}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{6}}}}$$

 $${\mathtt{\,-\,}}{\frac{{\mathtt{8}}}{{\mathtt{6}}}}$$

 $${\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{3}}}}$$

 Any other mathematicians want to double check this so we get the right answer?

c(8,4)=70 combinations

0.000976563 is so close to 0.5¹⁰ (=0.0009765625) that I suspect that's what it's meant to be, in which case its square root is 0.5⁵, or 1/32 (=0.03125)

$${\mathtt{w}}{\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{{\mathtt{5}}}} = {\frac{{\mathtt{7}}}{{\mathtt{2}}}}$$

add 2/5 to both sides

$${\mathtt{w}} = {\frac{{\mathtt{7}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{5}}}}$$

Multiply the numerator/deminator of the first fraction by 5, and the numerator/demoninator of the second fraction by 2. We to this to get a common demoniator so we can add the fractions.

$${\mathtt{w}} = {\frac{{\mathtt{35}}}{{\mathtt{10}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{10}}}}$$

$${\mathtt{w}} = {\frac{{\mathtt{39}}}{{\mathtt{10}}}}$$ 

or

w = 3.9

Let's check it!

w- 2/5=3 1/2 

3.9- 2/5=3 1/2    ---Imput 3.9 (or 39/10) for w

3.9 - .4 = 3.5     ---Make everything a decimal

3.5 = 3.5 ✔

You have to specify what you mean here... this could be 

(³√27) * 6

or

³√27*6

Depending on which problem you're trying to solve, your answer would be

(³√27) * 6 = 3*6 = 18

or

³√27*6 = ³√162 = 5.451361778496419

I'm thinking your probably looking for the first answer.

Let me guess...you want to find the cable length  ... ???

We have an angle and an opposite side  .....we are trying to find the hypoteneuse..so...the thing that relates these is the sine.......

sin(50) = 15/x     where x is the cable length ...  so

x = 15/sin(50)  = 19.58 ft.

The only other thing you might possibly want to know is how far the cable is anchored from the pole.

Use:    cos(50) = x / 19.58       .....and solve for x   ......!!!

18/33 = x/360

First. reduce the fraction  on the left to 6/11

So    6/11 = x/360

Cross-multiply

360*6 =  11x

2160 = 11x  ...  divide both sides by 11

x =  2160/11

93.5307436087 do 3 squarared 27 then do times 6