All Answers 356000 Answers

6x^8y^10

Simplify 8tx+7x​92​​

12+5x

1% of 67 is one hundredth of that. So you divide by 100 and get 0.67

Now suppose you want 35%, you already have 1% so just multiply by 35.

0.67 * 35 = 23.45

Thats unfortanent

35% of 67 is 23.45

Press the = a second time, that usually works.  :)

I gave a shot and I'm not sure if I got it correct by sheer luck or if my methods were correct.

Your methods are correct.

I ended up having to use a calculator at the (-8)^3 part as I wasn't sure how to solve for that in any other way than brute forcing it.

\(\begin{array}{|rcll|} \hline &&(-8)^3 \pmod {27} \\ &\equiv& (-8)^2\cdot(-8) \pmod {27} \\ &\equiv& 64\cdot(-8) \pmod {27} \quad & | \quad 64 \pmod {27} \equiv 64-2\cdot 27 \pmod {27} = 10\pmod {27} \\ &\equiv& 10\cdot(-8) \pmod {27} \\ &\equiv& -80 \pmod {27} \\ &\equiv& -80 + 3\cdot 27 \pmod {27} \\ &\equiv& -80 + 81 \pmod {27} \\ &\equiv& 1 \pmod {27} \\ \hline \end{array}\)

It's just an another mystery of life i guess.

Life is like a box of chocolates... that's why

10^123 = 2^x

find x

\(\begin{array}{|rcll|} \hline 10^{123} &=& 2^x \quad & | \quad \log_{10}() \\ \log_{10}(10^{123}) &=& \log_{10}(2^x) \\ 123\cdot \log_{10}(10) &=& x\cdot \log_{10}(2) \quad & | \quad \log_{10}(10) = 1 \\ 123 &=& x\cdot \log_{10}(2) \\ x\cdot \log_{10}(2) &=& 123 \\ x &=& \frac{123}{\log_{10}(2)} \\ x &=& \frac{123}{0.30102999566} \\ \mathbf{x} & \mathbf{=} & \mathbf{408.597155671} \\ \hline \end{array}\)

Maths is the backbone of everything without maths you are going to be stuck

thank you melody. I really appreciate it. The help you give out on this website is top class.

It turns out I haven't learned about union's just yet nor did I know they existed.

 Thank you for putting me on the correct path.

Ok, I am going ot give you a simple answer, the pythagorean theorem. Which is a² + b² = c²

So if you have a normal right triangle, like this one, you'd use the theorem. First you'd do 5² + b² = 12².

The reason we don't know what b squared is because that is what we're finding. 5² = 25 and 12² = 144 so fill in the equation. 25 + b² = 144. Now subtract 25 from both sides. Now you get b² = 119. Now you have to remove the squared in b². Since you have to remove the power, you have to find the square root of both sides. So in b² = 119, do the square root to both sides. So now you get your answer as b = 10.908. If you just want the longest side(hypotenuse), you do a² + b²  = c². I am going to pick random numbers, let's say a is 5 and b is 6. So, 5² + 6² = c². 5 squared is 25 and 6 squared is 36. So 25 + 36 = c². 61 = c². So now you have to find the square root of both sides. The answer is 7.81. 

Thge easiest way to do a question like this is to think about the graph

f(x)= (x-8)(x+5)

This is a concave up parabola.  The roots are at  x=8  and  x=-5

Since it is concave up it is the bit inbetween these points that falls BELOW the x axis.  and that is where f(x)<0

The ends are where f(x)>0

so      x<-5    and   x>8

here is the graph.

The way to solve these   -always-     is to sketch the graph of the quadratic.I can't use the graphics on this site,but I'll try to explain.

This function is a parabola which touches the x axis at the points (-5,0)  and (8,0). You should sketch it to be clear. When x is less than   -5,f(x)   is positive    and when  x is greater than 8 f(x) is positive.  So you have the UNION of two inequalities, not what you have written above. Answer is ( can't write this in symbols because of software)

 x  is les than  (-5)      U       x is greater than 8 

Boy, every teacher can teach. All you need to do is to actually LISTEN. They got a degree and took a test on the skills of a teacher.

Ok, I'm new to trig, but asin is basically the inverse of sin.

thank you melody, I see what you mean.

I'm just trying to work out how to write it now.

Are you gong to respond to me vest4R ??

The correct answer however is -11

There is not enough info given here.  :(

I am jsut playing ....

farhan cycles the first part of a 150 km journey at an average speed of 35km/h.

x km at 35km/hour  that is  

\(\frac{x}{35} hours\)

If he takes 4.5 hours for his entire journey, find the distance that he cycles.

(150 - x)   km left

\(4.5 - \frac{x}{35} =\frac{ (4.5*35-x)}{35} = \frac{157.5-x}{35}\;\;hours\;\;left\)

\((150-x)\div \frac{157.5-x}{35}\;\;km/hour\\ \frac{35(150-x)}{157.5-x}\;\;km/hour\\\)

Use an online source of information such as khan academy. 

Hi vest4R,

"I believe -5>x>8 is correct? apparently not?"

this says

-5 is greater than x and x is greater than 8 ...

if -5 is greater than x then x must be less than -5

if x is less then -5 how can it be greater than 8  ???

See my problem?