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When Ibuprofen is given for fever to children 6 months of age up to 2 years, the usual dose is 5 milligrams (mg) per kilogram (kg) of body weight when the fever is under 102.5 degrees Fahrenheit. How much medicine would be usual dose for a 18 month old weighing 25 pounds?

The child is in the given age category of 6 mnths to 2 years so you do not need to worry any more about its age.

1 pound = 0.45 kg    (I looked that up on the net)

so

25 pounds = 25*0.45 Kg = 11.25Kg

5mg for each of those Kg is given

5*11.25 = 56.25 mg    

(wouldn't baby ibupofen be a liquid measured in mL ?)

Also note that the equation can be rewritten as follows

\(x^2+z^2+6z=16 \\ \rightarrow x^2+z^2+6z+3^2=16+3^2 \\ \rightarrow x^2+(z+3)^2=25 \\ \rightarrow (x-0)^2+(z-(-3))^2=5^2\)

.

"How would I find x and y to plot on a graph for the equation x-y=3 ? "

Rearrange the equation as:  y = x - 3

Choose two values of x (say, x = 0 and x = 10) and calculate the corresponding values of y.

Plot the two points on a graph and join them by a straight line.

. 

"what is the % power thats left if i drop a ball of m = 1 kg from the height of h = 1 m at earths gravity g = 9.82 ms/s. and the same values except h = 0.54 m"

It's not clear to me exactly what you are after, but:

Potential energy is given by:  PE = mgh

Kinetic energy is given by:  KE = (1/2)mv^2     where v is velocity

PE + KE = constant

Also, note that power is rate of change of energy, so should your question really be expressed in terms of power?

This 3d graph should help:

.

The WEB2.0 calculator does not do fractions.

You can use the / symbol.

A fraction line IS a division sign :)

Hi 8MP   :))

Venn Diagram

Out of 20 job seekers, 12 have degrees and 10 have some other qualification. If 2 have no qualification how many have both a degree and some other qualification?

sin²θ + cos²θ = 1

It will always equal one no matter what θ is. This comes from the pythagorean theorem.

and 3652.5 minutes = 60.875 hours

365.25 * 10 =

3652.5

What is ⌀ ?

Intergers include negative number MG ://

4!=24 because

4!=4*3*2*1   = 24

sum of all multiples of 6 between 6 and 999

This is an arithemetic progression.

The first term is 6*2=12   and the last term is  6*166=996

So that is 166-2+1=165 term

T1=6

n=165

T165= 996

d=6

\(Sn=\frac{n}{2}(T_1+Last)\\ S_{165}=\frac{996}{2}(6+996)\\ S_{165}=\frac{996}{2}(1002)\\ \)

sum = 996/2*1002 = 498996

Yes unless you mean

\(36 ^{1/3}\times 87^{1/5}- 5\)

36^(1/3)*87^(1/5)-5 = 3.0662439203221144

Hi Davis,

look, study, learn :))

2sqrt(147) + 2sqrt(27) - sqrt(98)

To simplify a square root you must look for a square number that goes into it

square numbers are

\(1^1=1 \qquad \text{not helpful though}\\ 2^2=4\\3^2=9\\4^2=16\\etc\\\)

I can see tht

147 = 49*3

27=9*3

98=49*2

so I have

\(2\sqrt{147} + 2\sqrt{27} - \sqrt{98}\\ =2*\sqrt{49*3} \quad+\quad 2*\sqrt{9*3} \quad-\quad \sqrt{49*2}\\ =2*\sqrt{49}*\sqrt3 \quad+\quad 2*\sqrt9*\sqrt3 \quad-\quad \sqrt{49}*\sqrt2\\ =2*7*\sqrt3 \quad+\quad 2*3*\sqrt3 \quad-\quad7*\sqrt2\\ =14\sqrt3 \quad+\quad 6\sqrt3 \quad-\quad7\sqrt2\\ =20\sqrt3 \quad -\quad7\sqrt2\\\)

After you look and study, ask any questions that you want to :)

Thx

\(\frac{-3\sqrt{5}}{\sqrt{15}} \\ = \frac{-3\sqrt{5}(\sqrt{15})}{\sqrt{15}(\sqrt{15})} \\ = \frac{-3\sqrt{75}}{15} \\ = \frac{-3(5\sqrt{3})}{15} \\ = \frac{-15\sqrt{3}}{15} \\ = -\sqrt{3}\)

:)

Thanks, hectictar

Thanks, hecticar

(36³)(87⁵) - 5

= (46,656)(4,984,209,207) - 5

= 232,543,264,761,792 - 5

= 232,543,264,761,787

y = (-5/2)(40) - 34

y = (-200/2) - 34

y = -100 - 34

y = -134

1. 8a-3b=-4 

    a=5-2b

You know that a equals 5-2x so put this in brackedts and sub it into your first equation.

\(8a-3b=-4 \qquad (1)\\  a=(5-2b)\qquad (2)\\~\\ 8(5-2b)-3b=-4 \\ \text{now solve it for b}\\ 40-16b-3b=-4\\ 40-19b=-4\\ 40-19b-40=-4-40\\ 19b=-44\\ b=\frac{-44}{19}\\ b=-2\frac{6}{19}\\~\\ \text{Now sub this value of b into (2)}\\ a=5-2*\frac{-44}{19}\\ a=5+\frac{88}{19}\\ a=5+4\frac{12}{88}\\ a=9\frac{3}{22}\\ so\\ b=-2\frac{6}{19}\qquad and \qquad a=9\frac{3}{22}\\ \)

You can do ther others by copying this one. :)

\(\frac{(\sqrt{54})(\sqrt{20})}{\sqrt{189}} \\ = \frac{\sqrt{(54)(20)}}{\sqrt{189}} \\ = \frac{\sqrt{1080}}{\sqrt{189}} \\ = \frac{\sqrt{1080}(\sqrt{189})}{\sqrt{189}(\sqrt{189})} \\ = \frac{\sqrt{204,120}}{189} \\ = \frac{54\sqrt{70}}{189} \\ = \frac{2\sqrt{70}}{7}\)