Find the value of x that makes each statement true
sin (x/3 + 10) = cos x
\(sin(\frac{x}{3}+10)=cosx\)
\(cosx=\sqrt{1-sin^2x}\)
\(sin(\frac{x}{3}+10)=\sqrt{1-sin^2x}\)
\(sin^2(\frac{x}{3}+10)=1-sin^2x\)
\(x_1 = 12,52765316663493rad\)
\(x_2 = -6,205750411731104rad\)
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