1) Area of a hexagon with a perimeter of 24 ft
The side length is 1/6 of this = 4 ft.....
And the area = 6(1/2)(4)^2*sqrt(3)/2 = (3/2)*16*sqrt(3) =
24*sqrt(3) ft^2 ≈ 41.6 ft^2
2) The largesr circle that can be constructed in such a rectangle will be one with a radius of 7.
And the area outside the circle but still inside the rectangle =
Area of the rectangke - the area of the circle =
(14 * 21) - pi (7^2) = 294 - 49pi ≈ 140.1 sq ft
P.S. - I'll provide a pic, if you want.
