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Sorry, I used 9% instead of 8%!!.

FV = 125,000 x 1.02^3

FV =125,000 x 1.061208

FV =132,651.

what is compound interest when Rs. 125000 is invested for 9 months at 8% per annum, compounded quarterly?

FV = PV x [1 + R]^N

FV =125,000 x [1 + 0.09/4]^(9/3)

FV =125,000 x [1.0225]^3

FV =125,000 x   1.069030140625

FV =133,628.77

Mel, I did'nt understand it. I need it with the formula i've given

Don't see any image......but we need to find the central angle, theta, of the sector....so we have :

Arc length =  radius * ( theta in radians)

15 = 10 * ( theta in radians )    divide both sides by 10

15 / 10  =  3 / 2   =  1. 5 rads

So.....the area of the sector  =

(1/2) * radius^2  * theta in rads   =

(1/2) * 10^2 * 1.5   =   75 cm^2

You probably will not like my answe much Sara because I do not do questions like this by formula.

I can never remember formulas that I do not think I really need.  It is some weird kind of mental block  

Find the ratio in which the point(-3,k) divides the line segment joining the points (-5,-4) and (-2,3). Also find the value of k.

Look at the x values first

-2--5=3

-3--5=2

so the dividing point  is 2/3 of the way starting from the first end point.           The ratio is 2:3

so the k value must also be 2/3 of the way, starting from the first end point

Now the y difference in y values must be in the same ratio.

3--4=7

k--4 = k+4

\(\frac{k+4}{7}=\frac{2}{3}\\ 3k+12=14\\ 3k=2\\ k=\frac{2}{3} \)

Well if you are not happy with this website and can't tolerate some nonsense, find another website.it's just as plain as that.

check Gingerale's reply. i see you haven't commented on that one!

no. im afraid 2^4x stands for 2^4x

2^4x-7=32/+7=

2^4x=39

4x=Log₂(39)

x=(Log₂(39))/4

x=1.3213505547155622.....

Oh yea. now i see thx

I'm sorry fr nt explaining things properly. please check the following link for more info:

https://web2.0calc.com/questions/help-decide-the-schedule

Dicord is an app where we can create servers and chat.MJ have createda server called JayClan there. create your account in discord and join the group!

In your picture A is the right angle, in Alan's picture B is the right angle

yes i know that. the letters can be changed but i did'nt understand by what u meant as

"what you did wrong is you marked a specific angle with B and thought it means B is the right angle! but thats wrong, because 'A' is the right angle!."

but B is the right angle ryt?

And what does it mean?

What are we supposed to do in that "clan"?

(I have no idea what discord is if you will explain i will be grateful)

Ok i think i know how to explain it to you.

when you first learned the pythagoras theorem, the teacher probably drew a right triangle on the board. The teacher then marked the right angle with the letter 'B' and said that (AB)²+(BC)²=(AC)².

The teacher was right. But you forgot something. You dont have to mark the right angle with 'B'. The teacher coulve marked it with 'C'. That means instead of (AB)²+(BC)²=(AC)² the theorem would've been (BC)²+(AC)²=(AB)². You dont need to mark something with a specific letter for it to work.

what you did wrong is you marked a specific angle with B and thought it means B is the right angle! but thats wrong, because 'A' is the right angle!.

also, in my first post i wrote:

You simply wrote 'B' instead of 'A', 'C' instead of 'B' and 'A' instead of 'C'.

 I was wrong, i dont know if it helps you but you wrote 'A' instead of 'B', 'B' instead of 'C' and 'C' instead of 'A'.

hope it helps!

ok now this is getting confusing. the position of the co-ordinates does matter ryt?

But in my dig angle b=90. my co-ordinated were in the wrong places so my answer was wrong.

my working was like this: (as per the 1st dig)

AB=\(\sqrt{}25 = 5\)

BC =\(\sqrt{}50 =5\sqrt{}2\)

AC= \(\sqrt{}25 = 5\)

using pythagoram theorm, AC²=AB²+BC²

5=5²+\(5\sqrt{}2\)²

5 not = 25+50

But as per Alan's dig:

AB=\(\sqrt{}25 = 5\)

BC =\(\sqrt{}25 = 5\)

AC=​\(\sqrt{}50 =5\sqrt{}2\)​
using pythagoram theorm, AC²=AB²+BC²

\(5\sqrt{}2\)²=5²+5²

50=25+25=50

My bad, in your picture 'A' is supposed to be 90.

The number of zeroes is the number of times it is divisible by 10. think about it. 5*10=50. we Multiplied by 10, and got a new zero. multiplying it again will give us another zero.

Read my answer

no, we WILL get a right triangle. You simply wrote 'B' instead of 'A', 'C' instead of 'B' and 'A' instead of C. it doesnt change the fact its a right triangle. well yes, in alans picture the angle b=90. in your inaccurate picture (which is probably the reason you got confused) c=90.

its like calling x 'n' in x*2+3=5 and thinking the answer will be different. it wont. you didnt change anything besides the letters and it doesnt matter. dont worry, you got the right answer.

if ^ stands for multiplication then

2*(4x-7)= 32

4x-7= 32/2

4x-7=16

4x=16+7=23

x=23/4=5.75

hope this is correct!

( stole frm CPhill XD)

yea thx

yes. i got the answer. but when i first attempted the question i changed the co-ordinates of the vertices. if the co-ordinates are changed we don't get a right answer right? The first one is mine and the 2ed one is alan's.

Isn't the question about the number of trailing zeros in:

5 x 10!? =18,144,000?

A more pictorial approach! 

This wouldn't be so good for much bigger numbers though!

.

124.46

لاقرب عشره

Arabic: " To the nearest 10th?"

124.46 =124.5