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The whole point of this is to scare you all... Its April Fools day!

But At least we all know at the end that the only part of it that is true is that my birthday is on Apr. 19!

YOU ALL ARE TOO EASY TO TRICK!!

If Gaussian prime = b,

a=b=a=b

Lol I'm sorry!!! 

Me too!

8/3 = 12/n

n = 21

APRIL FOOLS!

Actual Solution: 

8/3 = 12/n 

(8/3)*n = 12

n = 12/(8/3)

n = 12*(3/8)

n = 12*(3/8) = 4 1/2

Assuming a(t) is acceleration, then

velocity is:  v(t) = t³/3 - t² + 6t + k₁     where k₁ is a constant

position is:  s(t) = t⁴/12 - t³/3 + 3t² + k₁t + k₂  where k₂ is another constant.

The two constants are found from:

s(0) = 0:    0 = k₂

s(1) = 20:   20 = 1/12 - 1/3 + 3 + k₁ + k₂

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You literally gave me a heart attack I started screaming my parents had to ask what was wrong OMGGGGGGGG I Hateu sooo much but love u more ahhhh lol

Happy April Fools....

YES MJ! Nice joke

Lol, realy?? :D

YOU ALMOST GAVE ME A HEART-ATTACK! XDDDD

could u explain using latex? i did'nt get it

Im here if you need me.

Prove that α is a Gaussian prime iff α(conjugate) is a Gaussian prime

Here is a "Rule of Thumb" when trying to find the number of trailing zero of a large factorial:

Example: How many trailing zeros are there in 5,000! ???.

You simply divide the number in question by "powers of 5", as follows:

5,000/5 =1,000

5,000/25=200

5,000/125 =40

5,000/625 =8

5,000/3,125 =1, when there a fraction involved, just ignore the fraction and take the integer part.

Total =1,000+200+40+8+1 =1,249 trailing zeros in 5,000!.

Solve for x: P.S. This is how I read it: sqrt(3x^2) - 2sqrt(2x) - 2sqrt(3) = 0, solve for x
-2 sqrt(3) - 2 sqrt(2) sqrt(x) + sqrt(3) sqrt(x^2) = 0

Add 2 sqrt(3) to both sides:
sqrt(3) x - 2 sqrt(2) sqrt(x) = 2 sqrt(3)

Subtract sqrt(3) x from both sides:
-2 sqrt(2) sqrt(x) = 2 sqrt(3) - sqrt(3) x

Raise both sides to the power of two:
8 x = (2 sqrt(3) - sqrt(3) x)^2

Expand out terms of the right hand side:
8 x = 3 x^2 - 12 x + 12

Subtract 3 x^2 - 12 x + 12 from both sides:
-3 x^2 + 20 x - 12 = 0

The left hand side factors into a product with three terms:
-(x - 6) (3 x - 2) = 0

Multiply both sides by -1:
(x - 6) (3 x - 2) = 0

Split into two equations:
x - 6 = 0 or 3 x - 2 = 0

Add 6 to both sides:
x = 6 or 3 x - 2 = 0

Add 2 to both sides:
x = 6 or 3 x = 2

Divide both sides by 3:
x = 6 or x = 2/3

-2 sqrt(3) - 2 sqrt(2) sqrt(x) + sqrt(3) sqrt(x^2) ⇒ -2 sqrt(3) - 2 sqrt(2) sqrt(2/3) + sqrt(3) sqrt((2/3)^2) = -8/sqrt(3) ≈ -4.6188:
So this solution is incorrect

-2 sqrt(3) - 2 sqrt(2) sqrt(x) + sqrt(3) sqrt(x^2) ⇒ -2 sqrt(3) - 2 sqrt(2) sqrt(6) + sqrt(3) sqrt(6^2) = 0:
So this solution is correct

The solution is:
Answer: | x = 6

That's it!

We can find x as follows :

Area =  (1/2) * x^2 * sin(27°)

8  =  (1/2) * x^2 * sin(27°)       multiply both sides by 2

16  = x^2 * sin (27°)    divide both sides by sin (27°)

[ 16 / sin (27°) ]  = x^2         take the square root of both sides

sqrt [ 16 / sin (27°) ]   = x  ≈  5.937  cm^2

Maybe you understand CPhill's explanation better ?

It is good that you said you did not understand.  I appraciate you being honest :))

Thanks, Melody.....here's another way....

Slope of the line  = [ 3 - - 4 ] / [ - 2 - - 5]  =  7 / 3

And the equation of the line is

y = ( 7 / 3) (x - -2) + 3  

y = (7 / 3) (x + 2) + 3      and when x  = -3, we can find k as

k = ( 7 / 3) ( -3 + 2)  + 3

k = ( 7 / 3) (-1)  + 3   =   2/3    so.....the point is ( -3, 2/3 )

And the ratio is given by

[Distance from (-5, -4) to ( - 3 , 2/3) ] /  [ Distance from ( -3, 2/3) to ( -2 , 3) ]

Distance from (-5, -4) to (-3, 2/3)   =  sqrt [ ( -3 - - 5)^2 + ( - 4 -2 /3)^2 ]  

sqrt [ 4   + (-14/3)^2 ] =  (2/3)sqrt(58)

Distance from ( -3, 2/3) to ( -2 , 3) =  sqrt [ (-2 - - 3)^2 + (3 - 2/3)^2 ]   =

sqrt [ 1  + (7/3)^2 ] = (1/3) sqrt(58) 

So......(-3, 2/3)   divides the line in the ratio of :

[(2/3)  sqrt (58)] / [ (1/3) sqrt (58) ]   =

[2/3] / [ 1/3]  =  2 / 1  =    2 :  1

lol what is that.

I'd say 1.0.1.-1.2.0

Given that AB = AC, BD = BD(bc it's just the same), and angle ABD = angle CBD

First B can be used.

C can be used because hypotenuse and one side is equal

D can be used because angle ADB = angle CDB = 90 deg

A still can be used because we can use the right angles and 2 pairs of equal sides to derive that the remaining pair of sides are equal......

This is a bad question......

Soz. my Bad

dilation with scale factor -1 does not make any change in size, therefore the answer is C.