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Lol not cute enough for me

Blue

Raj's money = 3 * David's money

r = 3d

David's money = Raj's money - $120

d = r - 120

Substitute.

r = 3 * (r - 120)    Distribute.

r = 3r - 360         Subtract 3r from both sides.

r - 3r = -360

-2r = -360           Divide by -2

r = -360/-2

r = 180

Raj's money = $180

A life? Outside of this? N-no way. Im not buying it. I wouldve believed if melody or alan said that, but you? No way. Youve always been there. You answered every question, helped every struggling high school student and explained patiently why they are wrong.

What am i supposed to do without your random "babbling of the day",what am i supposed to do without your daily b******t?

I cant imagine what wouldve happened if your nonsense posts were there for me, when i tried to understand how to use algebra, or how to solve geometry problems, or what fourier transform means?

This forum is not meant for what youre doing. Its not meant for advertisements. I dont care if your music is good or shitty like you. 

You are spamming the forum. Theres no other way to describe it. 

Either \(\sqrt{\frac{35}{6}}\)   or   \(\frac{\sqrt{210}}{6}\)

No need to be sorry! I'm not really sure which one is considered simpler. My guess is the second one. 

Sorry about this...we are just supposed to simply...so sorry...what would the answer be then?

-(I posted the original question)

Here's the frist one :

The linear distance traced out by one revolution of the ball will be

 2* pi (1 inch)  = 2pi inches

And 5 ft  = 60 inches

So......,the number of revolutions  =  60 / [ 2 pi]   =  30 / pi ≈ 9.5 revolutions

\(\sqrt{\frac72}*\sqrt{\frac53}=\sqrt{\frac72*\frac53}=\sqrt{\frac{7*5}{2*3}}=\sqrt{\frac{35}{6}} \\~\\=\frac{\sqrt{35}}{\sqrt{6}}*\frac{\sqrt6}{\sqrt6}=\frac{\sqrt{35*6}}{6}=\frac{\sqrt{210}}{6} \\~\\ \approx 2.415\)

We can't cuz we don't know

but nice try....ur quite the prankster today aren't u 😏

Here's the third one......

Circumference of coaster = 2pi (radius)

12.56  = 2pi (radius)    divide by 2pi

12.56 / [ 2pi] = radius =    6.28/pi  inches

Then....the radius of the glass  =  [ 6.28/pi -  1/2] inches

So......the circumference of the glass =

2 * pi * radius  =

2 * pi * [ 6.28/pi - 1/2) ]  ≈ 9.42 in 

Yay!!!! Thank you Admin for adding back the thing that shows other users who are composing an answer!!!! 

Very good :)

4+4 = 8.

I am 14 yrs old :)

\(5\text{pie}/6 \div 2\text{pie}\\ =\dfrac{5\text{pie}}{12\text{pie}}\\ =\dfrac{5}{12}\)

pie. lol

Pie is not pi.

what do you mean?

Left Hand Side equals 22 - 100 + 22 = -46.

Then, so what??

XY = - 46

what???????

I assume here i is a variable.

2i < i + 3

2i - i < i - i + 3

i < 3

\(\dfrac{8}{3}=\dfrac{12}{n}\\ n=12\div\dfrac{8}{3}=\dfrac{9}{2}\)

1/2 - 1

= -1/2

OR

1/(2-1)

= 1/1

= 1

Depends on what you mean

d :)

Reflection does not affect the size of the resulting image.

Do you mean \(\log_3x=\dfrac{1}{\sqrt 3}\)?

\(\dfrac{\sqrt{h^3}}{\sqrt{8}}\\ =\dfrac{h\sqrt{h}}{2\sqrt 2}\\ =\dfrac{h\sqrt{2h}}{4}\)

\(x^2+10x = 254\\ (x+5)^2=279\\ x+5 = \pm \sqrt{279}\\ x = -5 + \sqrt{279}\text{ OR }x =-5-\sqrt{279}\)

\(\sqrt{2}^n=\dfrac{2^x}{8^y}\\ 2^{n/2}=2^{x-3y}\\ \dfrac{n}{2}=x-3y\\ n = 2x - 6y\)

4ln x + 7ln x - 3ln z

= 11ln x - 3ln z

= ln x^11 - ln z^3

= ln \(\dfrac{x^{11}}{z^3}\)

I don't quite see what you're asking, here.

I never took the SAT, but I took the PSAT, ACT, and many other standardized-type tests, and my advice is just go through the questions in order, one at a time, plain and simple. If you find one that is really hard, skip it (and come back to it if you have time). But don't waste time trying to find and solve the easiest questions first. You'll just end up flipping pages and spending too much time comparing the "hardness" of questions.

Another thing is practice answering SAT-type questions. It really, really, really helps. I would reccommend the SAT practice questions on Khan Academy. I went through some of them to help prepare for the ACT, and I wish I had done more.

Here is a link to Khan Academy's SAT math practice: