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1.08321 * 1012 ck written in standard notation.

\(1.08321 * 1012 \ ck =1096.20852 \ ck \approx 1096 \ ck\)

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because  the  google  was   not  working

it is 7

what was your q

that is so funny jk

V_{square pyramd} =  (1/3) * Area of Base * Height ......so,,,,

605 = (1/3)*  Area of Base  * 15   simplify

605  =  5 * Area of Base     divide both sides by 5

121 cm^2   =  Area of Base

Since the pyramid has a square base...the length of an edge  = sqrt (121)  =  11 cm

3.14159265

donno

My teacher has a wall sticker thing of that on his wall. 7UR7L3M4N☢🐢☣

What does that mean? 7UR7L3M4N☢🐢☣

I don't know!!! It just ran away!!!! 7UR7L3M4N☢🐢☣

Can you square an 8 without the ² counting as 'not an 8'

Probably not

What operations can I use?

Can I use constants such as pi?

If I can I can get it in 0 8s so probably not

ceil(pi*pi*pi*pi)+floor(pi*pi*pi)+floor(pi*pi)+floor(pi*pi)

Absolute Value, shown on calculators as abs(x) or |x|, is basically the positive version of a number. Here are some examples:

abs(1.4)=1.4

abs(27)=27

abs(-6)=6

abs(0)=0

abs(-3.3)=3.3

That is a great poem . did you come up with it

He spent $6.03 on the pizza

7 

←DE→ is tangent to circle C at point D. What is the measure of ∠DEC?

∠DEC= 180°- 90° - 51° = 39°

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-1.875

Two triangle vertices intercept a diameter....so......the angle opposite that diameter = 90

Since the sum of any three angles in a triangle = 180, the other two angles must also sum to 90

So

39 + x  = 90        subtract 39 from each side

x = 90 - 39   =   51°

SFTL.......add the first two amounts......subtract that total from the third  =  amount spent on pizza...!!!

We have two areas to consider......a parallelogram and a triangle

Area_{parallelogram}  =  Base x Height  =  10 x 6   = 60m^2

Area_triangle  =  (1/2) Base  x Height  = (1/2)(12)(6)  = (1/2)(72)  = 36m^2

Total area  = [60 + 36]m^2  = 96 m^2

Use the distance formula between points

For instance

Distance   (-2,3) to  (2, 4)  = 

sqrt [ (-2 -2)^2 + (4 - 3)^2 ]  =  sqrt ( 16 + 1 )   sqrt (17 )  ≈  4.1231

Here's a pic of all the sides with their lengths :

I'll let you finish the math.....!!!!

This one  :    2(m∠JKL)=mJL

The measure of an intercepted arc  =  twice the measure of  an inscribed angle intercepting that arc

3. This one is a little hard to see,  NSS....

The small right triangle at the bottom left  has a hypotenuse of 10 and one leg of  6

So.....the other leg  =  sqrt (10^2 - 6^2)  =  sqrt (100 - 36) = sqrt (64) = 8

And this right triangle and the one at the top are related in the following way ......

6  / 10   = h / 16      ......multiply both sides by 16......

16*6/ 10  = h

96/10  = h

9.6  = h

4.  Area  =  (1/2)Base x Height  =  (1/2)(13)(4)  = (1/2)(4)(13)  = 2 * 13   = 26 in^2

Just  as Singerforthelord found  !!!!!