(log(x^2*\sqrt(b))/a=_*_+_*_-_
\(log\frac{(x^2*\sqrt{b})}{a}\\ =log x^2+log\sqrt{b}-loga\\ =log x^2+log(b)^{0.5}-loga\\ =2*log x+0.5*log(b)-loga\\ \)
it is a thick heavy weapon, mostly like a club, some people "cosh" people to either kidnap them or steal from them, i would also recommend looking through Bshirels google dictionary answer as well though
Hope this helps :D
thanks
how do you reduce 7/28?
\(\frac{7}{28}=\frac{1\cdot 7}{4\cdot 7}=\frac{1}{4}\)
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A cone is a circluar pyramid and the volume of any pyramid is
volume = (1/3) *area of base * perpendicular height
\(volume =\frac{1}{3}*\pi r^2*h\)
he should have eight sheeps left, hope this helps :D
the explanation is that, if the farmer has fifteen sheep, and he kills all of them, but he says there are 8 left, then you just take the number he says are left, and thats youre answer :D
7 is your answer
What formula do you use
y= 2x+8
-5=3x+2y
-5= 3x+2(2x+8) y=2x+8
-5=3x+4x+16 y=2(-3)+8
-21=3x+4x y-6+8
-21=7x
y=2
x=-3
(2n2 + n)/5
Step 1: (3n2)/5
Step 2: [3(52)]/5
step 3: (3*25)/5
Step 4: (75)/5
Step 5: 15
Click me for your answer!
18.18436*119 = 2163.93884
1.2*1239595959939 = 1487515151926.8
The first soultion is y=2x+8
And the second is y=-3/2-5/3
Oh okay.. Thank you Alan
we were put on this earth to have a happy life
Answer will be:
\({log}_{2}(16 384)=14\)
Perhaps for the midpoint I should have done f([a + b]/2)*(b - a), though, in this case, the result would be the same.
7^7^7 mod 1000 = 343 Remainder.
cos^2(x) + cos^2(pi - x)= 1
\(cos^2(x) + cos^2(\pi - x)= 1\)
\(x=\mathbb{R}\) all together!
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