e^x = -x
A graph might be the easiest way to solve this
Here is the solution : https://www.desmos.com/calculator/bjsnjcbch7
It occurs at x ≈ -.567
i dont
Does anyone else think that this person's account is a fake?
This is a maths website with a calculator on it. It is there for a reason!
Answer: 4
Joke: Me, your mom, your aunt, and your grandma.
NOW STOP SPAMMING THESE.
√2 cos(2 θ ) = 1 divide both sides by √2
cos (2 θ ) = 1 / √2
Let 2 θ = x
cos ( x) = 1 / √2 and this happens at x = pi/4 , 7pi/4 , 9pi/4 , 15pi/4
So
2 θ = pi/4, 7pi/4 , 9pi/4, 15pi/4 divide by 2
θ = pi / 8 , 7pi/ 8, 9pi / 8, 15pi / 8 answer "B"
calculate the area of a sector with a radius of 5cm and an angle of 40 degrees
\(A=\pi\ r^2\cdot\frac{\alpha}{360°}=\pi\cdot 5^2cm^2\cdot\frac{40°}{360°}\)
\( A=8.727\ cm^2\)
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nice to know
5+3=8
sin A = 0.3154
Take the inverse sine
arcsin (0.3154) ≈ 18.38° = 18° or [180 - 18.38]° ≈ 161.62° = 162°
Find the area of a triangle if a = 15ft b = 44ft C = 66°. Round the answer to 2 decimal places.
\(A=\frac{1}{2}absin\gamma=\frac{1}{2}\cdot 15ft\cdot44ft\cdot sin\ 66°\)
\(A=301.47\ ft^2\)
The area =
(1/2) (15) (44) sin (66) ≈ 301.47 square feet
Maybe learn to spell bud! (;
How much interest would you pay on a loan of $1,230 for 15 months at 15 percent APR if the interest is 18.75 per $100?
The monthly payment @ 15% compounded monthly =$90.44
$90.44 x 15 - $1,230 =$126.60 Interest you would pay.
The monthly payment @ 18.75% compounded monthly =$92.62
$92.62 x 15 - $1,230 =$159.30 Interest you would pay.
Let the amount of money that Mandy has = M
Let the amount of money that Keith has = K
M/K = 4/5 and,
[M - 416] /K = 3/7, solve for M, K
M = $896.00 The amount of money that Mandy started with.
K =$1,120 The amount of money that Keith started with.
0.5*3 - (-2)
= 1.5 - (-2)
= 1.5 + 2 (neg * neg = pos)
= 3.5
-9x - 3(-1) = -6
-9x + 3 = -6
-9x = -9
x = 1
x=1 and y=-1
sqrt(a b) = sqrt(a) X sqrt (b) is the rule to remember.
So for example sqrt(75) = sqrt(25 X 3) = sqrt(25) X sqrt(3)
= 5 X sqrt(3)
you are right kilarofsouls
Thxs.. That really worked out for me. thank you very much.
You will have to wait a bit RedRyder, you haven't been here long enough yet ://
sin(t)cos(t)[sec(t)-csc(t)]=
\(sin(t)cos(t)[sec(t)-csc(t)]\\ =sin(t)cos(t)[\frac{1}{cos(t)}-\frac{1}{sin(t)}]\\ =\frac{sin(t)cos(t)}{cos(t)}-\frac{sin(t)cos(t)}{sin(t)}\\ =sin(t)-cos(t)\)
1/20(a)=.025
\(\frac{1}{20}a=0.25\\a=0.25\cdot 20\\\color{blue}a=5\)
\(\frac{1}{20a}=0.25 \\20a=\frac{1}{0.25}\\a=\frac{1}{0.25\cdot20}\\\color{blue}a=\frac{1}{5}\)
Kilar_of_souls
september 27 1994
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