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sin v = 0,5

Decide the value of: sin 2v

$\begin{array}{rcl|rcl|rcl} \sin(2v) &=& 2\cdot \sin(v)\cdot \cos(v) & \cos(v) &=& \sqrt{1-\sin^2(v)} & \sin(v) = \frac12 \\ & & & &=& \sqrt{1-\left(\frac12 \right)^2} \\ & & & &=& \sqrt{1- \frac14} \\ & & & &=& \sqrt{\frac34} \\ & & & &=& \frac{\sqrt{3}}{2} \\ &=& 2\cdot \frac12\cdot \frac{\sqrt{3}}{2} & &=& \frac{\sqrt{3}}{2} \\ &=& \frac{\sqrt{3}}{2} \\ \end{array}$

$\sin(2v) = \frac{\sqrt{3}}{2}$

I don't understand what you are trying to show people Asad ..... :/

"How many joules of PE does a 12 kg rock have after falling from a 76 m cliff and reaches 7 m/s?"

E = PE + KE    E is total energy, PE is potential energy, KE is kinetic energy.

Top of cliff:  E = 12*9.8*76 + 0 joules

E stays constant so when velocity is 7 m/s

12*9.8*76 = PE + (1/2)*12*7^2

PE = 12*9.8*76 - (1/2)*12*7^2 or PE ≈ 9314 joules

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The angle is 120° to end up in quadrant II.  i.e. tan(120°) = -sqrt(3)

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Find b: 5a/c - y - d/b =z

$\color{red}\frac{5a}{c}-y-\frac{d}{b}=z\\-\frac{d}{b}=z+y-\frac{5a}{c}\\-\frac{d}{b}=\frac{cz+cy-5a}{c}$

$-\frac{b}{d}=\frac{c}{cz+cy-5a}\\\color {blue}b=\frac{cd}{5a-cz-cy}$

Find m: 4n/ab - c/m=x

$\color{red}\frac{4n}{ab}-\frac{c}{m}=x\\-\frac{c}{m}=x-\frac{4n}{ab}\\ -\frac{c}{m}=\frac{abx-4n}{ab}\\ -\frac{m}{c}=\frac{ab}{abx-4n}$

$m=\frac{abc}{4n-abx}$

  !

Suppose q is an angle in the standard position whose terminal side is in Quadrant II and tan Ø= - square root of 3

$arctan( -\sqrt{3})=-60°$

$The \ free \ limb \ of \ the \ angle -60 ° \ forms \ the \ angle \ {\color{red}150 °} \ in \ the \ third \ quadrant.$

.                                                                                           incorrect

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Thanks Alan! 

$The \ free \ limb \ of \ the \ angle -60 ° \ forms \ {\color{blue}the \ angle \ 180° -60° = \ 120 °} \ in \ the \ third \ quadrant.$

An engineer estimates the angle of elevation to the top of the building to be 50°.
After moving 1.5 meters further away, the angle of elevation was 40°.
How high is the top of the building?

$\begin{array}{|lrcll|} \hline (1) & \tan(50^{\circ}) &=& \frac{h}{x} \\ & x &=& \frac{h}{\tan(50^{\circ})} \\\\ (2) & \tan(40^{\circ}) &=& \frac{h}{1.5+x} \\ & \tan(40^{\circ}) &=& \frac{h}{1.5+\frac{h}{\tan(50^{\circ})}} \\ & \tan(40^{\circ})\cdot \left( 1.5+\frac{h}{\tan(50^{\circ})}\right) &=& h \\ & 1.5\cdot \tan(40^{\circ}) + h\cdot \frac{ \tan(40^{\circ}) } { \tan(50^{\circ}) } &=& h \\ & h-h\cdot \frac{ \tan(40^{\circ}) } { \tan(50^{\circ}) } &=& 1.5\cdot \tan(40^{\circ}) \\ & h\cdot \left(1- \frac{ \tan(40^{\circ} ) } { \tan(50^{\circ}) } \right) &=& 1.5\cdot \tan(40^{\circ}) \\ & h\cdot \left( \frac{ \tan(50^{\circ})-\tan(40^{\circ} ) } { \tan(50^{\circ}) } \right) &=& 1.5\cdot \tan(40^{\circ}) \\ & h &=& 1.5\cdot \left( \frac{ \tan(50^{\circ})\cdot\tan(40^{\circ}) }{ \tan(50^{\circ})-\tan(40^{\circ} ) } \right) \\ & h &=& 1.5\cdot \left( \frac{ 1.19175359259\cdot 0.83909963118}{ 1.19175359259-0.83909963118 ) } \right) \\ & h &=& 1.5\cdot \left( \frac{ 1 }{ 0.35265396142 } \right) \\ & h &=& 1.5\cdot 2.83564090981 \\ & h &=& 4.25346136471\ m \\ \hline \end{array}$

The top of the building is 4.25 m high.

Simplify the expression

1. Reorder the terms

${26^3}p\times3!\rightarrow{26^3}\times3!\times p$

2. Evaluate the power

${26^3}\times3!\times p\rightarrow17576\times6p$

3. Calc the product

$17576\times6p\rightarrow105456p$

Answer

$105456p$

See? You call everyone "blarney"!

All im asking is for you to stop mocking those people even if they are idiots. Please.

Btw i already wrote a response, it disappeared somehow. I think i remember questions that i cant find and people with much less points than they had a day ago.

Why would I want to do that?

If you have specific, curious questions, I may answer or not. This is finals’ week; I don’t have much time for blarney, but I will make time to roast a tasty vole, or at least devour it raw. 

As in the outside is all letters like this?

X + Y = Number 

2X + Y = Number

Around 11 to 1

 the answer is -4

-8 - -4 = -4

then the miuns and the negative changes to a postive 

-8 + 4 = -4

Nope. He have cancer probably.

for me about 9:30

volume of a sphere = (4π/3)(radius³)

4.5π = (4π/3)(r³)

Divide both sides by (4π/3) .

4.5π / (4π/3) = r³

4.5π * 3/(4π) = r³

27/8 = r³

Take the cube root of both sides.

$\sqrt[3]{\frac{27}{8}}=r \\~\\ \frac{\sqrt[3]{27}}{\sqrt[3]{8}}=r \\~\\ \frac{3}{2}=r$

r = 3/2 centimeters

$\frac{3x}{8z}\,*\,\frac{12}{6y}=\frac{3x\,*\,12}{8z\,*\,6y}=\frac{36x}{48yz}=\frac{3x}{4yz}$     :)

There are 3 * 60 = 180 minutes in 3 hours

If Billy keeps on smokin 5 cigarettes a minute,

after 180 minutes he will have smoked 180 * 5 = 900 cigarettes

And since he had 200 cigarettes to start with,

he will have 200 - 900 = -700 cigarettes after 3 hours 

pretty late

A story of two enemies that changed their lives forever.

what is 8x to the negative 3 power

$(8x)^{-3}=\frac{1}{(8x)^3}=\frac{1}{512x}$

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how do i do this

y=1/4x+1 2y=2x-4

$y=\frac{1}{4}x+1\\2y=2x-4$

$2\cdot( \frac{1}{4}x+1)=2x-4\\\frac{1}{2}x+2=2x-4\\6=\frac{3}{2}x$       [$y=\frac{1}{4}x+1$ 

$x=4$

$y=1+1$

$y=2$

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Thanks Alan!   I correct that.