All Answers

+1491

0

They were probably asked to round if the correct answer was marked wrong. Then again there is nothing to round up. What am l even doing on here?! l have an AP test tomorrow! D:

HighSchoolCalculusMay 9, 2017

#1

+9488

+4

I think this is what the equation is:

H(t) = -4.9t^2 + 40t

We want to know what t is when h(t) = 75

So plug in 75 for h(t) and solve for t.

75 = -4.9t^2 + 40t

Subtract 75 from both sides.

0 = -4.9t² + 40t - 75

Now we can use the quadratic formula to solve for t.

$t = {-40 \pm \sqrt{40^2-4(-4.9)(-75)} \over 2(-4.9)}\\~\\t={-40 \pm \sqrt{130} \over -9.8}\\~\\ t=\frac{-40+\sqrt{130}}{-9.8}\qquad\text{or}\qquad t=\frac{-40-\sqrt{130}}{-9.8}$

t ≈ 5.245 seconds or t ≈ 2.918 seconds

hectictarMay 9, 2017

#1

-7

+1

86.3%

pandicorn876May 9, 2017

#1

+48

+1

B because any 2 sides added have to be greater than the 3rd.

ParthForThreeMay 9, 2017

#1

0

Use a proportion:

3/4=x/156

4x=156*3

4x=468

4x/4=468/4

x=117students

Therefore 117 students ordered hot lunch

GuestMay 9, 2017

#1

+116

+1

Surface Area of Half a Cylinder:

^{$A=\frac{1}{2}(2\pi*r*h+ 2\pi*{r}^{2})$}

Hope This Helps!

-MagikaRedNiteTiger

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MagikalRedNiteTigerMay 9, 2017

#2

+118704

+2

I got a math test back and the question was 5000(0.04)(0.0833) i got 16.66 but it was marked wrong she said it should have been 16.67 and that i just rounded wrong. i have tried on every calculator i have and i still only get 16.66 . I lost a point off my test for this and she wont admit that she maybe wrong and just blammed it on my calculator

Your teacher is wrong unless you have not written the question correctly .. like maybe there was a dot above something indicating that it was a repeating decimal.

5000(0.04)(0.0833)

=10000(0.04)(0.0833) /2

=833*0.04/2

=833*0.02

=833*0.01*2

=8.33*2

=16.66

You can show your teacher that if you want to :) (I didn't use a claculator)

MelodyMay 9, 2017

#1

+118704

+1

Hi Adam

$\displaystyle\sum_{n=4}^{10}\;(0.8n-0.4)\\~\\ \displaystyle\sum_{n=4}^{10}\;(0.8n)+\displaystyle\sum_{n=4}^{10}\;(-0.4) \qquad \text{that is 0.4 for (4,5,6,7,8,9,10)}\\~\\ =(0.8*4+0.8*5+......0.8*10) -( 7*0.4)\\ =0.8(4+5+6+7+8+9+10) -( 2.8)\\ =0.8(49) -( 2.8)\\ =36.4$

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