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It isn't.   0^0 is undefined

I have closed this question because it is almost the same as the one I just answered.

You need to ask one question of a certain type, learn from the answer and then attempt the other similar questions yourself before you ask again.

We want you to learn from us, we do not want to do your homework for you - this will not help you learn. :)

 On a forward somersault dive, a divers height, H meters, above the water is given by h(t)= -4.9t^2+6t+3,  where T is the time in seconds after the diver leaves the board. 

I have already answered all this question using calculus but it occurs to me that maybe you do not know calculus yet and you were supposed to do it a different way.  Can you let me know if that is the case please.  If so I will answer again :)

Hi Micheala,

You need to learn to look at these and get as much information as possible just by sight.

You should recognise this as a parabola because it is a polynomial of degree 2 (the highest power is 2)

Also you can see it is concave down because the leading coefficient is negative (-4.9)

Also is you put t=0 you can see immediately that the initial height is 3 metres above the water.

a)  Determine the divers maximum height above the water. 

This will happen when the gradient of the tangent is 0.   And you must remember that the first derivative gives the gradient of the tangent. Find the time this happens first then sub in to find the height.

b)  How long does it take the diver to reach the maximum height? 

You already have that.

c)  For how long is the diver higher than 3 m in the water? 

Put h(t)=3 into the equation and solve it.  It is a quadratic (parabola) and you already know that one answer is t=0

find the other answer.  

plug in 2 for x

y = -3(e)(2) + 1

y = -6e + 1

By e I'm assuming you're referring to the mathematical constant (~2.7)

y  ≈ -15.31

x ^2 - y^2   =  55

x  -  y  =  11

factor  the first quation

(x + y) ( x - y)  = 55      sub the second equation in for the second factor

(x + y) (11)  =   55        divide both sides by 11

( x + y)   =   5

So......

x - y  =  11

x + y  =  5            add  these  equations

2x  =  16        divide both sides by 2

x  = 8

And using x + y  =  5   means that  y   =   - 3

x- 2x^(1/2) - 3= 0

Let x = u^2  ...so.....x^(1/2)  =  u   and we have

u^2  - 2u - 3  = 0           factor

(u - 3)  ( u + 1)  = 0      set both factors  equal to 0 and solve

u - 3  = 0                                u +  1    = 0

add 3 to both sides            subtract 1 from both sides

u  = 3                                 u  = -1

So

u^2  = 3^2  = 9  = x       or       u^2 = (-1)^2  =  1  = x

The second solution makes the original problem false......so...... x = 9  is the only solution

The sequence continues as follows:

1/24, 3/40, 9/40, 243/280, 2,187/560, 2,187/112, 59,049/560, 531,441/880........etc.

The formula used to find each term of the sequence is: 3^(2n-2) /n(n+1)(n+2)(n+3), where n=Term number = 1, 2, 3, 4.........etc.

you are fat dont try to sugar coat it bc you will eat that too

Thank you so much! 

The height of C above the ground  =  BE + FB

BE  =  AB * sin (28)  =  8 *sin (28)

FB  =  BC * cos(28)  =  5 * cos (28)

So......

BE + FB   =

 8 * sin (28)  +  5 * cos (28)  ≈  8.17 cm

Thank you very much!

Here, CD is the height of the building.

tan 36º = CD / BC

BC tan 36º = CD

BC = CD / tan 36º

tan 20º = CD / (600 + BC)

(600 + BC) tan 20º = CD

BC = CD/tan 20º - 600

\(\frac{CD}{\tan36}=\frac{CD}{\tan20}-600 \\~\\ \frac{CD}{\tan36}-\frac{CD}{\tan20}=-600 \\~\\ CD(\frac1{\tan36}-\frac1{\tan20})=-600 \\~\\ CD=-600\div(\frac1{\tan36}-\frac1{\tan20}) \\~\\ CD \approx 437.606 \text{ meters}\)

NVM I thought it said looking good.

For this we can use the elimination method.

5x + 2y = -2

3x – 5y = 17.4

Multiply the top equation through by \(\frac52\) .

\(\frac{25}{2} \) – 5y = -2

Now line this up with the second equation and add straight down.

    \(\frac{25}{2} \)x    +    5y = -5

+   3x      –    5y = 17.4

     15.5x +    0y = 12.4

15.5x = 12.4

x = 12.4/15.5

x = 0.8

Now just use this value for x in either equation to find y.

5(0.8) + 2y = -2

4 + 2y = -2

2y = -6

y = -3

9apples

0.1388888888888888888888888888888888888888888

penny

0.13888888888...

9x² - 6x

I don't really know what the instructions say to do...but we can factor out a 3x like this:

= 3x(3x - 2)

Can you give an example of one of these problems?

The most we can do here is simplify, since there is no equal sign in the original problem.

   9^2 - 6x

= 81 - 6x

And, if you want, we can factor out a 3.

= 3(27 - 2x)

6w(-5w⁴) = 6 * w * -5 * w⁴ = 6 * -5 * w * w⁴ = -30 * w⁵ = -30w⁵