All Answers 358291 Answers

First find the mean:

m = (5 + 1 + 1 + 8 + 4 + 5)/6 → 24/6 → 4

Mean Absolute Deviation:

MAD = (|5 - 4| + |1 - 4| + |1 - 4| + |8 - 4| + |4 - 4| + |5 - 4|)/6

MAD = (1 + 3 + 3 + 4 + 0 + 1)/6 → 12/6 → 2

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17,073

You add decimals just like you add whole numbers. Here's an example:

  3.4

+6.3

-------

=9.7

Here's another one:

    0.576

+  4.33

----------

=  4.906

Does this make sense? 

2 cups of sugar

1/3 cups of butter

Setup proportions to solve for both the sugar and butter. In a recipe, all ingredients must be proportional because otherwise, the meal will be not be exactly as the recipe calls for:

Let x = the cups of sugar

Let y = the cups of butter

\(\frac{\frac{3}{4}}{x}=\frac{\frac{3}{8}}{1}=\frac{\frac{1}{8}}{y}\)

We should solve each proportional individually. I'll solve for the cups of sugar first:

Let's utilize the exact same process for solving for y, the amount of cups of butter:

Dont Cheat

\(y=-12\)

If you are ever unsure whether or not your answer is correct, plug the y-value into the equation. Then, check to see that the equation is true:

\(\frac{2.5}{2}=1.25\)

One half of 2.5 is the equivalent of saying what is 1/2 * 2.5. "Of" is referring to multiplication, in this case:

Work it out the other way round, so 360 - 94 = 266. Therefore, the ? is 266.

cot(π/5)=1.37638192

\(\sqrt{36}=6 \)

So square root of 36 is 6 

Thanks again hectictar 

Every time x goes up by 1 unit, y goes up by 4 units....so, this looks linear!

Thanks!

\(x^{\frac23}(8x)^{\frac13} \\~\\ =x^{\frac23}\cdot 8^{\frac13} \cdot x^{\frac13} \\~\\ =x^{\frac23+\frac13}\cdot 2 \\~\\ =x^{\frac33}\cdot2 \\~\\ =x^1\cdot2 \\~\\ =2x\)

(4 - 5)^2   =   (-1)^2   =   (-1) * (-1)   =   1

Remember, a negative times a negative is a positive!

\((cd)^{\frac12}(d^{\frac13}) \\~\\ =c^{\frac12}\cdot d^{\frac12}\cdot d^{\frac13} \\~\\ =c^{\frac12} \cdot d^{\frac12+\frac13} \\~\\ =c^{\frac12}\cdot d^{\frac56} \\~\\ =\sqrt{c} \cdot \sqrt[6]{d^5}\)

We need an equation that tells us the speed of the car at any time.

To do that, we can take the derivative of the position equation.

Let's call that function v(t) .

v(t)  \(=\frac{d}{dt} (\frac14t^2+1) \\~\\ =\frac{d}{dt} \frac14t^2 +\frac{d}{dt}1 \\~\\ =(\frac14)(2)(t)+0 \\~\\ =\frac12t\)

And the average speed is given by...

average speed  \(=\frac{\text{distance}}{\text{time}} \\~\\ =\frac{s(10)-s(0)}{10} \\~\\ =\frac{(\frac14(10)^2+1)-(\frac14(0)^2+1)}{10} \\~\\ =\frac{5}{2}\)

Now we just need to know what t equals when v(t) = \( \frac52 \)

\(\frac52 = \frac12t \\~\\ \frac{5}{2}\div\frac{1}{2} =t \\~\\ 5=t\)

Complementary angles are equal to 90-x°.

If you are looking for the complementary angle of 12, subtract it from 90.

90-12=78°.

 thanks!

[ (4/5) a^2  ] ^2      apply the outer exponent over both terms in the bracket

(4/5)^2   *  (a^2)^2  =

( 16/25) a^4

log ( 3x + 8)  = 2

In exponential form we have

10^2  =  3x  + 8      

100 = 3x + 8      subtract 8 from both sides

92   =  3x           divide both sides by 3

92/3   = x 

One more "formula" 

Segment area  =

(1/2 ) R^2 (θ) - (1/2) R^2 sin (θ)  =

(1/2) R^2   [ θ -  sin ( θ) ]       where  θ  is the measure - in radians - of the central angle  of the sector

Very nice, hectictar.......!!!

I'll just name a few possibilities:

-12/-1=12

-24/-2=12

-36/-3=12

-48/-4=12

-1481481468/-123456789=12

I think you get the idea...