Look at the graph of the data points, here :
https://www.desmos.com/calculator/o7kuhjqe3b
Neither "C" nor "D" [ both linear ] will model the data
It appears from the graph that "B" is the best choice
Note .......derivative of arctan (u) = 1 / ( 1 + u^2) * du .....so......
f(x) = arctan (sin (5x)) = [ 1 / [ 1 + (sin(5x) )^2] * 5 cos (5x) =
[ 5 cos (5x) ] / [ 1 + sin2(5x) ]
Possible derivation: d/dx(tan^(-1)(sin(5 x))) Using the chain rule, d/dx(tan^(-1)(sin(5 x))) = ( dtan^(-1)(u))/( du) ( du)/( dx), where u = sin(5 x) and ( d)/( du)(tan^(-1)(u)) = 1/(1 + u^2): = (d/dx(sin(5 x)))/(1 + sin^2(5 x)) Using the chain rule, d/dx(sin(5 x)) = ( dsin(u))/( du) ( du)/( dx), where u = 5 x and ( d)/( du)(sin(u)) = cos(u): = cos(5 x) d/dx(5 x)/(1 + sin(5 x)^2) Factor out constants: = (5 d/dx(x) cos(5 x))/(1 + sin^2(5 x)) The derivative of x is 1: Answer: | = (15 cos(5x)) / (1 + sin^2(5x))
No, you shouldn't round up, because the 4th digit is LESS than 5. If it were 5 or greater, then you could round up. As it is, leave it as 0.378, if you don't need the 4th digit.
This is an old canard that is been around the social media for several years. Here are a couple of mathematicians explaining it:
https://www.youtube.com/watch?v=w3Nzkae_TRU
https://www.youtube.com/watch?v=emiMj8cCL5E
Woops! For some reason I was thinking Albert was told the day and Bernard was told the month !! D:
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
square root of 6 over 25
\({\color{red}\sqrt{\frac{6}{25}}}=\frac{\sqrt{6}}{5}\color{blue}=0.489897948556\)
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I cannot pretend to know how to solve this equation in a formal manner. However, I can easily program my computer with a few lines of code to find the solution!! I did just that and it came up with the smallest N as being =3,331. So that 1,373^333,331 mod 3,331 =585 !!!.
Somebody should try to verify this!.
Math problems are like puzzles, and it is kind of fun to figure out the puzzles!
And, the funny thing about math is that it all starts with simple things that just get piled on top of each other until it becomes complicated. But..ultimately it all boils down to simple things.
If you don't understand your teacher's way of explaining....maybe someone on here could help? :)
Do mean interquartile range? If you mean that, its that boxes in the middle of a box and whisker plot. There is a lower and Higher inter quartile range.
I know it's easy sometimes and fun, but it's kinda hard and I really just get the answers wrong all the time. I even had to get help from my teacher. That also didn't work.
Can I ask, why do you people like math? It's hard.
SA of rectangular right prism = 2(length * width + length * height + width * height)
SA of triangular right prism = (perimeter of base) * (height) + 2(area of base)
just type in fraction calculator in google
i mean a formula for both you know like πr2 is the formula for the area of a circle
You have your answer.
rectangles and triangles
There are many different right prisms.
eg rectangular prism, cube, cylinder, triangular prism, etc etc etc.
For surface are you just have to work out the area of all the sides seperately and then add them all together.
ya cant read a thing.
If you are going to make posts in French, use the French forum
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