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Aug 29, 2017
 #2
avatar+17 
0
Aug 29, 2017
 #1
avatar+9491 
+3

cups of vinaigrette  =  cups of vinegar + cups of oil

 

Let's call the amount of additional cups of oil  " x " .

There are   3  cups of vinegar   , and there are   1 + x  cups of oil   in the batch so far.

 

cups of vinaigrette  =  (3) + (1 + x)

cups of vinaigrette  =  4 + x

 

We want there to be  25  cups of vinegar for every  100  cups of vinaigrette.   That is....

 

\( \frac{\text{number of cups of vinegar}}{\text{number of cups of vinaigrette}}=\frac{25}{100} \)       Plug in  3  for cups of vinegar and  4 + x  for cups of vinaigrette.

 

\(\frac{3}{4+x}\,=\,\frac{25}{100} \\~\\ (4+x)(25)\,=\,(3)(100) \\ 100+25x\,=\,300 \\ 25x\,=\,200 \\ x\,=\,8\)                 Now solve this for  x  . First, let's cross-multiply.

 

So....she needs to add  8  cups of oil .

--------------------------------------------------

 

The final recipe will have  9  cups of oil. To find the price, we need to know how many ounces this is.

1 cup    =  8 ounces          Multiply both sides by  9  .

9 cups  =  72 ounces

 

The final recipe will have  3  cups of vinegar.

1 cup    =  8 ounces

3 cups  =  24 ounces

 

the total price, in dollars   =   0.50 * (ounces of olive oil)  +  0.35 * (ounces of vinegar)

                                         =   0.50 * 72   +   0.35 * 24

                                         =   36   +   8.4

                                         =   44.40

Aug 29, 2017
 #1
avatar+130511 
+1

 

There are 4 weeks in every month...so....the first one becomes

332 + 4 * x * 11 =

332 + 44x

 

For the second one....the additional amount that each player must raise  = x  = 

[ amount left to be raised] /  number of players  = [ 2000 - 1456 ] / 11   = 544 / 11  ≈  $49.45

 

 

 

The product of a number, k, and four is seven more than the quotient of the number and two-thirds. Write an equation to represent this situation.

 

Product of k  and 4  = 4k

Quotient of  k and 2/3  =  k / [2/3]  =  (3/2)k

So......7 plus the second thing  =  the frist thing....or....

4k  = (3/2)k + 7

 

 

A local basketball court dimensions are 50 ft. long, 20 ft. wide, the court is lost square footage by 1/4. What are the new dimensions of the court? Write the equation out then solve. 

 

If  1/4 of the square footage is lost....then 3/4 must remain

And  L  x W  = Area

So.....the new area  =  [L x W] * (3/4)  =   [50 x  20] x (3/4)   =  1000 x 3/4  =  750 sqare feet

However.....the new dimensions could be variable

If  we assume  that  each dimension was √3/2  that of the old...we have that

(50 * √3/2) * (20 * √3/2)  =

(25 * √3) *  ( 10 √3)  =

(≈ 43.3 ft )  * (≈ 17.32 ft)   =  (new length ) * (new width)  ≈   750 square feet

 

However....if the problem is claiming that each dimension was reduced by 1/4....the new dimensions are (50 * 3/4) * (20 * 3/4)  =  (37.5 ft)  * (15 ft)  and the new area  is 562.5 square feet

 

This one was unclear....!!!

 

 

The school district has $1045 to throw a company event downtown for 50 people. If the venue cost $320 to rent out, as well as dinner cost $290. The party director wants to give bonuses to everyone with the remainder of the budget.  How much would each employee get as a bonus? Write out the equation, let x stand for the bonus.

 

 

Let's first figure out how much remains......this is given by [ 1045 - 320 - 290]

So....this amount divide by the number of people is each person's bonus.....so we have...

 

[ 1045 - 320 - 290 ] /  50    = x      solving, we have

 

[ 435 ] / 50   = x  = $8.70  per person

 

Some big "bonus," huh???

 

 

cool cool cool

Aug 29, 2017
 #2
avatar
+1
Aug 29, 2017

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