Yes, assuming it is a circle (which I believe it is because "circumference" is used in the title), the area is indeed 0\(114.91ft^2\). Apparently, being ill does not obstruct your computational abilities. I hope you get better soon!
Of course, \(r=\frac{19}{\pi}\), and the area of a circle is \(\pi r^2\). Plugging what we know for r, we ge tthe following:
\(\pi*\left(\frac{19}{\pi}\right)^2\) | Distribute the exponent to both the numerator and denominator. |
\(\left(\frac{19}{\pi}\right)^2=\frac{19^2}{\pi^2}=\frac{361}{\pi^2}\) | |
\(\frac{\pi}{1}*\frac{361}{\pi^2}\) | Before multiplying the fractions together, notice that there is a common factor of pi in both the numerator of one fraction anf the denominator in another. |
\(\frac{361}{\pi}\approx114.91ft^2\) | |
In other words, good job!
Before we can calculate the value of \(\frac{7}{10}+\frac{7}{12}\), we must create a common denominator. The LCD of both the denominators is 60.
In this step, I will convert \(\frac{7}{10}\) to a fraction with a denominator of 60.
\(\frac{7}{10}\) | Multiply the numerator and denominator by 6/6. |
\(\frac{7}{10}*\frac{6}{6}\) | Notice that multiplying by 6/6 is actually multiplying by 1, which means that the value of the fraction remains unchanged. |
\(\frac{42}{60}\) | |
And now I will manipulate \(\frac{7}{12}\) as well.
\(\frac{7}{12}*\frac{5}{5}\) | Yet again, we multiply the fraction by 1. |
\(\frac{35}{60}\) | |
Since the denominators are the same in both fractions, now we can add them together.
\(\frac{42}{60}+\frac{35}{60}\) | Add the numerator and preserce the denominator. |
\(\frac{77}{60}=1\frac{17}{60}=1.28\overline{33}\) | |