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THIS IS MATH SITE GET AUTA HERE

Wolves can survive with ONLY 2.5 pounds a day, but they won't really live a... 'healthy' life.

They approximately eats 5 pounds a day in order to reproduce successfully.

The MAXIMUM they can eat a day is about 22.5 pounds.

I can't really see how this is going. Did you copy & pasted?

If the first set, {1 2 3 4 ... 57 58} is A = {1~58}, n{A} = 58. 

The bottom one, {3, 4, 5, 6, 59, 60}.. I think you meant {3~60?} let's just call that B, because we can't have 2 As.

n(B) = 58.

ok. They both have 58

So IF I'm getting the problem right, this will be in a sequence. 

floor level = n

1+4n

which looks.....simple?

n=58 (since you said it was 58th level)

58*4 = 232

232+1 = 233

there you go. Hope i got the problem right.

Firstly, \(\sqrt{479}≈21.8\), making the problem mostly done already.

it will be 22 ft approximately, since the decimal point is larger than 5.

ANSWER : 22 ft

Why are you confused? What is the area of a square?

Area = S^2, where S = Side of the square.

S^2 = 479   take the square root of both sides.

S = Sqrt(479)

S = 21.89 = ~ 22 feet - side length of the field. 

2.

Please don't post things that you can just easily figure out.

n(A) means NUMBER OF NUMBERS () in a set of A.

you said n(AxB) is 858, and n(B) is 22, so n(A) = n(AxB/B) = 858/22 = 39.

So n(A) = 39.

In \(sqrt(6)\), 6 is not a square number, meaning it won't be a whole nor natural number.

rational is a type of number that can be represented by a fraction. it can sometimes be infinite, but not in this case.

So this only leave us with irrational.

the value of \(sqrt(6)\) is somewhere between 2 and 3, but closer to 2.

Logarithms, or Log, represented as \(Log_{x}(y)=z\), is same as \(x^z=y\). But In \(x^z=y\), you are trying to get the value of y, but in \(Log_{x}(y)=z\), you are trying to get the value of z, not y. Sometimes you will not see x in place. That means it's value is set to 10. So \(Log_{x}(y)=z\) means something like "if you have put an exponent z to x and got y, what is that exponent z's value?".

Just remember this. That's all you have to do.

what is pie times two squared rounded to the nearest hundredth

\((\pi\times 2)^2=39.48\)

  !

12.6

Very helpful, thank you so much!

The  ' h ' stands for ' hyperbolic'  .   The hyperbolic functions  sinh cosh tanh    are a completely different family of functions from sin cos tan  ( which are known as circular functions.)       Depending on how far you take maths,you may meet the hyperbolic functions later.  But first,get properly acquainted with the circular functions. That's fundamental if you are going to progress in calculus.

$10 x 40 hours = $400 what Drey earned in regular pay.

$490 - $400 = $90 what Drey earned in overtime.

$90 / $15 = 6 hours that Drey worked in overtime.

40 + 6 = 46 hours that Drey worked in 1 week, regular + overtime hours.

Solve for x:
4 x^2 = 2.25

Rewrite the right-hand side of the equation.
2.25 = 9/4:
4 x^2 = 9/4

Divide both sides by a constant to simplify the equation.
Divide both sides by 4:
x^2 = 9/16

Eliminate the exponent on the left-hand side.
Take the square root of both sides:
x = 3/4                 or                   x = -3/4

What you have written is the equation of a straight line     3y = 2x + 12.          Since there is an infinite number of points on a straight line ,there is an infinite solution set. You would need  another equation to obtain a specific solution. If you had another (linear) equation in  x  and  y  then your solution would be the unique point where the two lines intersected.

2.44948974278

irrational

The appropriate formula is:  M  =  P [ i (1 + i)ⁿ ] / [ (1 + i)ⁿ - 1 ]

where:  M  =  monthly payment

             P  =  principal ( 100, 000 )

             i  =  monthly interest rate ( 0.0875 / 12 )     [ Since 8.75 is a yearly rate, divide by 12 ]

             n  =  number of monthly payments ( 360 )

M  =  100000 [ 0.0875/12 (1 + 0.0875/12) ^ 360 ] / [ (1 + 0.0875/12) ^ 360 - 1 ]

M  =  $786.70

is the square root of 6 a whole, natural, rational, or irrational number

What is %40 of %70

\(\begin{array}{|rcll|} \hline \%40 \text{ of } \%70 \\ &=& 40\ \% \times \ 70\% \\ &=& 40\times \ 70\ \% \% \\ &=& 2800\ \% \% \\ &=& 28\times 100\ \% \% \quad | \quad 100\ \% = 1 \\ &=& 28\times 1 \% \\ &=& 28\ \% \\ \hline \end{array} \)

Don't get confused by the idea of   'per cent   X   another per cent'   which I think is bothering you. 'Per Cent' just means

'hundredth'.

So 40 per cent   X  70 per cent  is just   40 hundredths    X    70 hundredths.

Which is   40/100   X   70/100

Which is 4/10   X  7/10   =28/100     which is 28  hundredths   which is 28%. 

40%*70%=0.28=28%

Two different natural numbers are selected from the set

\( \{1, 2, 3, \ldots, 6\}\).

What is the probability that the greatest common factor of these two numbers is one?

Express your answer as a common fraction.

\(\begin{array}{|r|r|r|r|} \hline n & & \text{greatest common factor } = 1 & \text{greatest common factor } \ne 1 \\ \hline 1. & 5,6 & 1 \\ \hline 2. & 4,6 & & 2 \\ 3. & 4,5 & 1 \\ \hline 4. & 3,6 & & 3 \\ 5. & 3,5 & 1 \\ 6. & 3,4 & 1 \\ \hline 7. & 2,6 & & 2 \\ 8. & 2,5 & 1 \\ 9. & 2,4 & & 2 \\ 10. & 2,3 & 1 \\ \hline 11. & 1,6 & 1 \\ 12. & 1,5 & 1 \\ 13. & 1,4 & 1 \\ 14. & 1,3 & 1 \\ 15. & 1,2 & 1 \\ \hline & sum & 11 \\ \hline \end{array}\)

The probability is \(\mathbf{\tfrac{11}{15}}\)

Ten 6-sided dice are rolled. What is the probability that exactly three of the dice show a 1?

Express your answer as a decimal rounded to the nearest thousandth. 

thanks!

\(\begin{array}{|rcll|} \hline && \binom{10}{3} \times \left(\frac16 \right)^3 \times \left(\frac56 \right)^7 \\\\ &=& \frac{120 \times 5^7 }{6^{10}} \\ \\ &=& \frac{9375000}{60466176} \\ \\ &=& 0.15504535957 \ (15.5 \% ) \\ \hline \end{array}\)

\(\begin{array}{lcll} \text{possibilities: 10 dices, three "1" } &=& \binom{10}{3} \\ \text{probability: 3dices, three "1" } &=& \left(\frac16 \right)^3 \\ \text{probability: 7dices, no "1" } &=& \left(\frac56 \right)^7 \\ \end{array}\)

how do you multiply (x-1) with abs(x)

  \(If\;\; x >0  \text{ then the product is }  x(x-1) = x^2-x\)

 \(If\;\; x <0 \text{ then the product is }  -x(x-1) = -x^2+x = -(x^2-x)\)