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9a2-m2+10mn-25n2

\(9a^2-m^2+10mn-25n^2\\ =9a^2-[m^2-10mn+25n^2]\\ =9a^2-(m-5n)^2\\ =[3a-(m-5n)][3a+(m-5n)]\\ =(3a-m+5n)(3a+m-5n)\\\)

I think that there is a huge difference between Algebra 2 and Pre-cal. 

Much harder...

Well, um...I don't know if I fully understand this topic, but I'll try to answer  .

n(A x B) when distributed would be n(A)* n(B).

And n(A x B) is 75.

We also know n(A) = 15.

So if n(A)* n(B) is equivalent to n(A x B), then n(A)* n(B) = 75.

N(A) is 15, so substitute 15 for n(A) to get 15* n(B) = 75.

Divide both sides by 15 and get n(B) = 5.

So n(B) = 5.

Correct me if I'm wrong.

I think it is an answer that you have gotten by solving, but doesn't work when you plug it in the original equation.

Could anyone give a better/correct answer?

A solution of a simplified version of an equation that does not satisfy the original equation. Watch out for extraneous solutions when solving equations with a variable in the denominator of a rational expression, with a variable in the argument of a logarithm, or a variable as the radicand in an nth root when n is an even number.

Let U = {1, 2, 7, 8, 10, 13, 15, 17, 18}

Determine the complement of the set {1, 8, 10} 

The complement is ___

{2,7,13,15,17,18}

Find

(a) the number of subsets and

(b) the number of proper subsets of the set.

{x|x is an odd integer between -8 and 8}

Let A = { -7, -5, -3, -1, 1, 3, 5, 7 }

Number of elements = 8

(a)  A has \(2^8 = \mathbf{256} \)  subsets

(b)  A has \(2^8-1 = \mathbf{255}\)  proper subsets

Let A = {5, 6,7,8,9,10}

A. How many subsets does A have?

B. How many proper subsets does A have?

A. A has \(2^6 = \mathbf{64} \)  subsets
B. A has \(2^6-1 = \mathbf{63}\)  proper subsets

Let A = {4, 5, 6, 7, 8, 10, 11}

A. How many subsets does A have?

B. How many proper subsets does A have?

A. A has \(2^7 = \mathbf{128}\)  subsets

B. A has \(2^7 -1 = \mathbf{127}\) proper subsets

The digits 1,2,3,4 and 5 can be arranged to form many different 5-digit positive integers with five distinct digits.
 In how many such integers is the digit 1 to the left of the digit 2?

\(\begin{array}{|r|r|r|r|r|r|} \hline & & 1 \text{ left } 2& 1 \text{ left } 2& 1 \text{ left } 2& 1 \text{ left } 2 \\ \hline n & \text{permutation} & \text{ distance }0 & \text{ distance }1 & \text{ distance }2 & \text{ distance }3 \\ \hline 1. & 12345& 0 \\ 2. & 12354& 0 \\ 3. & 12435& 0 \\ 4. & 12453& 0 \\ 5. & 12543& 0 \\ 6. & 12534& 0 \\ 7. & 13245 && 1 \\ 8. & 13254 && 1 \\ 9. & 13425 &&& 2 \\ 10. & 13452 &&&& 3 \\ 11. & 13542 &&&& 3\\ 12. & 13524 &&& 2 \\ 13. & 14325 &&& 2 \\ 14. & 14352 &&&& 3 \\ 15. & 14235 && 1 \\ 16. & 14253 && 1 \\ 17. & 14523 &&& 2 \\ 18. & 14532 &&&& 3 \\ 19. & 15342 &&&& 3 \\ 20. & 15324 &&& 2 \\ 21. & 15432 &&&& 3 \\ 22. & 15423 &&& 2 \\ 23. & 15243 && 1 \\ 24. & 15234 && 1 \\ 25. & 21345 \\ 26. & 21354 \\ 27. & 21435 \\ 28. & 21453 \\ 29. & 21543 \\ 30. & 21534 \\ 31. & 23145 \\ 32. & 23154 \\ 33. & 23415 \\ 34. & 23451 \\ 35. & 23541 \\ 36. & 23514 \\ 37. & 24315 \\ 38. & 24351 \\ 39. & 24135 \\ 40. & 24153 \\ 41. & 24513 \\ 42. & 24531 \\ 43. & 25341 \\ 44. & 25314 \\ 45. & 25431 \\ 46. & 25413 \\ 47. & 25143 \\ 48. & 25134 \\ 49. & 32145 \\ 50. & 32154 \\ 51. & 32415 \\ 52. & 32451 \\ 53. & 32541 \\ 54. & 32514 \\ 55. & 31245 &0 \\ 56. & 31254 &0 \\ 57. & 31425 && 1 \\ 58. & 31452 &&& 2 \\ 59. & 31542 &&& 2 \\ 60. & 31524 && 1 \\ 61. & 34125 &0 \\ 62. & 34152 && 1 \\ 63. & 34215 \\ 64. & 34251 \\ 65. & 34521 \\ 66. & 34512 &0 \\ 67. & 35142 && 1 \\ 68. & 35124 &0 \\ 69. & 35412 &0 \\ 70. & 35421 \\ 71. & 35241 \\ 72. & 35214 \\ 73. & 42315 \\ 74. & 42351 \\ 75. & 42135 \\ 76. & 42153 \\ 77. & 42513 \\ 78. & 42531 \\ 79. & 43215 \\ 80. & 43251 \\ 81. & 43125 &0 \\ 82. & 43152 && 1 \\ 83. & 43512 &0 \\ 84. & 43521 \\ 85. & 41325 && 1 \\ 86. & 41352 &&& 2 \\ 87. & 41235 &0 \\ 88. & 41253 &0 \\ 89. & 41523 && 1 \\ 90. & 41532 &&& 2 \\ 91. & 45312 &0 \\ 92. & 45321 \\ 93. & 45132 && 1 \\ 94. & 45123 &0 \\ 95. & 45213 \\ 96. & 45231 \\ 97. & 52341 \\ 98. & 52314 \\ 99. & 52431 \\ 100. & 52413 \\ 101. & 52143 \\ 102. & 52134 \\ 103. & 53241 \\ 104. & 53214 \\ 105. & 53421 \\ 106. & 53412 &0 \\ 107. & 53142 && 1 \\ 108. & 53124 &0 \\ 109. & 54321 \\ 110. & 54312 &0 \\ 111. & 54231 \\ 112. & 54213 \\ 113. & 54123 &0 \\ 114. & 54132 && 1 \\ 115. & 51342 &&& 2 \\ 116. & 51324 && 1 \\ 117. & 51432 &&& 2 \\ 118. & 51423 && 1 \\ 119. & 51243 &0 \\ 120. & 51234 &0 \\ \hline sum & & 24 & 18& 12 & 6 \\ \hline \end{array}\)

1.2916

-2, -2, -3, 0, 12, 38, 83.....

Look at the difference between the terms at several levels as follows:
0, -1, 3, 12, 26, 45..............First difference
-1, 4, 9,  14, 19....................Second difference
5, 5, 5, 5.............................Third difference

Now, to get the next term in your sequence, just add the last terms as follows:

5 + 19 + 45 + 83 =152, 5 + 24 + 69 +152 =250.........etc. So, your sequence  would be:

-2, -2, -3, 0, 12, 38, 83, 152, 250, 382........etc.

P.S. You could also use this formula to generate any term that you want:

 a(n) = 1/6 (5n^3 - 33n^2 + 64n - 48) 

n = [69 - 4] / 5 + 1 = 14 terms

[4 + 69] / 2 x 14 =

 73 / 2 x 14 = 511

Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height. 

40% of 70% may seem difficult, but parsing the expression's different parts is essential to being able to understand this

"Of" is an indicator of multiplication. Knowing this, the expressions changes to \(40\%*70\%\).

The height of a sphere would be its diameter.  Let's call this  " d " .

And the formula for the surface area of a sphere is...

surface area  =  4 * pi * (radius)²

                                                                  Since  radius = d/2 ,  we can say...

surface area  =  4 * pi * (d / 2)²

                                                                  The problem tells us that  surface area = 800 cm²

    800 cm²    =  4 * pi * (d / 2)²

                                                                  Multiply out the exponent.

    800 cm²    =  4 * pi * d² / 4

                                                                  Simplify

    800 cm²    =  pi * d²

                                                                  Divide both sides by  pi .

800 / pi cm²  =  d²

                                                                  Take the positive square root of both sides.

√[ 800 / pi ] cm  =  d

15.958  cm  ≈  d

What is the probability that each of her next five stops is on the 7th floor or higher, You can go down one and go up 4, 

\(\frac{2x}{3}+\frac{x}{3}=\frac{3x}{3}=x\)

0.9375

-3(n + 6) + 10  =  -8

To solve this equation for  n , first let's subtract  10  from both sides.

-3(n + 6)  =  - 8 - 10

-3(n + 6)  =  -18

Next, divide both sides of the equation by  -3  .

n + 6  =  -18 / -3

n + 6  =  6

Next, subtract  6  from both sides of the equation.

n  =  6 - 6

n  =  0

if so i SOO want to do it....

PLEASE HELP!!!!!!!!

TY sir, god bless u 

Obviously they did, man. They need help with knowing how big E is. Does it show that on a calculator, man? Be helpful please. I don't have the answer so I can't help you, sorry.

Hi Cassie,

I know you deleted this because you think it is wrong :)

[I know because Cassie told me]

Instead of dots it is better so just leave your answer and write underneath, or on top that you know it is wrong.

OR

 If you really do not want it there then you can delete it but just write.

"Deleted becasue it is the wrong answer"    or something like that.