Finding the inverse of an equations requires a few steps. I will use the orginal function f(x)=2x2+2x−1
1. Change f(x) to y.
This means that f(x)=2x2+2x−1 changes to y=2x2+2x−1. That is all that this step entails.
2. Replace all instances of y with x and all instances of y with x
This step is relatively simple, too.
y=2x2+2x−1 changes to x=2y2+2y−1. Now, this step is done.
3. Solve for y
Solving for y means to isolate it. Since the quadratic formula is only a valid option when solving for the root of the equation, we cannot use that method with multiple variables. It appears as if completing the square is the only option.
2y2+2y−1=x | We need to get the "c" term on the opposite side of the equation for completing the square. Therefore, add 1 to both sides. | ||
2y2+2y=x+1 | Since the a-term must be one in order for completing the square to work, we must divide the entire equation by 2. | ||
y2+y=x+12 | This is the trickiest bit. We need to make the lefthand side a perfect square. To do this, add (b2)2 where b is the coefficient of the linear term. You must add it to both sides because whatever you do to one side, you must do to the other. | ||
y2+y+(b2)2=x+12+(b2)2 | Replace b with the coefficient of the linear term, 1. | ||
y2+y+(12)2=x+12+(12)2 | Simplify both sides. | ||
y2+y+14=x+12+14 | The left hand side is now a perfect-square, so transform it into one. | ||
(y+12)2=x+12+14 | Before taking the square root of both sides, we should add the fractions together. | ||
x+12+14=2x+24+14=2x+34 | Reinsert this back into the equation. | ||
(y+12)2=2x+34 | Take the square root of both sides. | ||
y+12=±√2x+34 | Distribute the square root to both the numerator and denominator. Remember that taking the square root results in the positive and negative answer. | ||
y+12=±√2x+32 | Subtract 1/2 from both sides. | ||
y=±√2x+3−12 | Break them up into separate solutions. | ||
| We can convert this into function notation, if you want. | ||
f−1(x)=±√2x+3−12 |
I will get to graphing later.
The next function is f(x)=−4.9(t+3)2+45.8
Let's do the same steps again. Change f(x) to y and flip flop all "t's" and "y's."
t=−4.9(y+3)2+45.8
Last time, I solved the equation, but I won't do that with this function because it appears as if you did it correctly.
Ok, inputting it into Desmos is easier than you might think.
Equation 1: y=2x2+2x−1
Equation 1 Inverse: x=2y2+2y−1
This is the inverse because every x value is now the y-value. We can do the same for equation 2/
Equation 2: y=−4.9(t+3)2+45.8
Equation 2 Inverse: t=−4.9(y+3)2+45.8
Now, just put in both the "Equation 1 Inverse" and "Equation 2 Inverse" into Desmos, and Desmos figure out the rest. Click here to see the graph is Desmos. Spoiler Alert: both equations fail the vertical line test.
Goat eating grass from inside a circle with radius r
The goat is hooked a the perifer of circle: How long shall the rope be to let goat eat 1/2 of the grass?
Hello Guest!
The goat problem is discussed in great detail and
in a comprehensible manner with the link below.
Unfortunately in German.
But you can help with the Google translator.
http://www.khloebel.de/mathe/Ziege/Ziege.html
R ≈ 1.58r (k.h.loebel)
r∼R
Have fun with the goat problem
!